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Consider a Daniell cell operating under nonstandardstate conditions. Suppose that the cell's reaction is multiplied by 2 . What effect does this have on each of the following quantities in the Nernst equation? (a) \(E,\left(\right.\) b) \(E^{\circ},\) (c) \(Q,\) (d) \(\ln Q\), and (e) \(n\) ?

Short Answer

Expert verified
Multiplying the cell reaction by 2 does not affect \(E\) and \(E^{\circ}\), but it squares \(Q\), doubles \(\ln Q\), and doubles \(n\).

Step by step solution

01

Effects on \(E\) and \(E^{\circ}\)

Doubling the cell's reaction will not have an effect on the \(E\) and \(E^{\circ}\). The cell potential \(E\) is independent of the stoichiometry of the reaction. The standard cell potential \(E^{\circ}\) also remains unchanged as it is only dependent on the nature of the reactants.
02

Effects on \(Q\)

The reaction quotient \(Q\) will change as it depends on the concentration of the reactants and the products. As a result, when the reaction is multiplied by 2, \(Q\) will be squared.
03

Effects on \(\ln Q\)

The natural logarithm of the reaction quotient, \(\ln Q\), will be affected since \(\ln Q\) depends on \(Q\). When \(Q\) is squared (because the reaction was multiplied by 2), \(\ln Q\) will be doubled.
04

Effects on \(n\)

The number of moles of electrons transferred in the reaction \(n\) will be doubled when the reaction is multiplied by 2 because \(n\) is directly proportional to the reaction stoichiometry.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Cell potential
Understanding cell potential is crucial in electrochemistry, as it represents the driving force behind the flow of electrons in an electrochemical cell. To put it simply, cell potential, denoted as E, is the measure of the energy per unit charge available from the redox reaction occurring in the cell.

It's composed from the difference in potential between the two electrodes. The greater the difference, the higher the cell potential, which translates to more electrical energy that can be harnessed from the reaction. When conditions deviate from standard states, such as changes in concentration, pressure, or temperature, the cell potential can be calculated using the Nernst equation, accounting for these non-standard conditions. However, it is important to note that changes in the stoichiometry of the reaction, like doubling the reaction, will not influence the cell potential directly.
Reaction quotient (Q)
The reaction quotient, known as Q, is a snapshot of the reaction's progress, comparing the concentrations of products and reactants at a given moment. It's similar to the equilibrium constant but is used for any point during the reaction, not just at equilibrium.

Determining Q

For a general reaction aA + bB ↔ cC + dD, the reaction quotient is expressed as:\[\begin{equation}Q = \frac{[C]^c[D]^d}{[A]^a[B]^b}\end{equation}\]Where the concentrations of the products C and D are raised to their respective stoichiometric coefficients and divided by those of the reactants A and B. When the reaction is modified, such as being multiplied by a factor, this affects the reaction quotient accordingly.
Standard cell potential (·¡Â°)
The standard cell potential, ·¡Â°, is a key term in electrochemistry, as it indicates the potential of a cell under standard conditions (1 M concentration of all reactants and products, 1 atm pressure, and 25°C temperature).

This reference value allows chemists to predict the direction and spontaneity of a redox reaction. Like the cell potential E, the standard cell potential ·¡Â° is unaffected by changes in the stoichiometry of the reaction, such as doubling. As such, the ·¡Â° remains a constant for a given redox reaction unless the actual reactants or their nature are changed.
Natural logarithm in electrochemistry
The natural logarithm—often seen in equations as \[\begin{equation} ln \end{equation}\]—is a central part of the Nernst equation in electrochemistry. It helps relate the cell potential to the reaction quotient (\[\begin{equation} Q\end{equation}\]) and the number of moles of electrons transferred (\[\begin{equation} n\end{equation}\]).

Using natural logarithms allows us to find the relationship between the electrochemical properties and the concentrations of reactants and products in a reaction. Importantly, when \[\begin{equation} Q\end{equation}\] changes, such as being squared due to the doubling of the reaction, \[\begin{equation} ln(Q)\end{equation}\] will change. The properties of logarithms dictate that the natural logarithm of a squared number is double the logarithm of the original number. Thus, when analyzing changes in reaction stoichiometry, one must consider the impact on the natural logarithm's value.
Moles of electrons (n)
The mole of electrons, n, is an essential value in the Nernst equation, signifying the amount of electrons transferred during the redox reaction. This number is integral when calculating cell potential, as it impacts the potential's magnitude directly.

As n is determined by the stoichiometry of the reaction, any changes to the reactant coefficients, such as doubling the reaction, will subsequently alter the value of n. For instance, if the original reaction transfers 2 moles of electrons, doubling the reaction implies that now 4 moles of electrons would be involved. Understanding the role of moles of electrons within electrochemical calculations is vital for predicting and manipulating the electrical output of chemical cells.

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Most popular questions from this chapter

Fluorine \(\left(\mathrm{F}_{2}\right)\) is obtained by the electrolysis of liquid hydrogen fluoride (HF) containing potassium fluoride (KF). (a) Write the half-cell reactions and the overall reaction for the process. (b) What is the purpose of KF? (c) Calculate the volume of \(\mathrm{F}_{2}\) (in liters) collected at \(24.0^{\circ} \mathrm{C}\) and 1.2 atm after electrolyzing the solution for \(15 \mathrm{~h}\) at a current of \(502 \mathrm{~A}\).

Describe the basic features of a galvanic cell. Why are the two components of the cell separated from each other?

A galvanic cell is constructed as follows. One halfcell consists of a platinum wire immersed in a solution containing \(1.0 M \mathrm{Sn}^{2+}\) and \(1.0 M \mathrm{Sn}^{4+} ;\) the other half-cell has a thallium rod immersed in a solution of \(1.0 M \mathrm{TI}^{+}\). (a) Write the half-cell reactions and the overall reaction. (b) What is the equilibrium constant at \(25^{\circ} \mathrm{C} ?\) (c) What is the cell voltage if the \(\mathrm{TI}^{+}\) concentration is increased tenfold? \(\left(E_{\mathrm{T} 1^{+} / \mathrm{T} 1}^{\circ}=-0.34 \mathrm{~V} .\right)\)

Calculate the standard potential of the cell consisting of the \(\mathrm{Zn} / \mathrm{Zn}^{2+}\) half-cell and the SHE. What will the emf of the cell be if \(\left[\mathrm{Zn}^{2+}\right]=0.45 \mathrm{M}, \mathrm{P}_{\mathrm{H}_{2}}=2.0 \mathrm{~atm}\), and \(\left[\mathrm{H}^{+}\right]=1.8 \mathrm{M} ?\)

An aqueous solution of a platinum salt is electrolyzed at a current of 2.50 A for \(2.00 \mathrm{~h}\). As a result, \(9.09 \mathrm{~g}\) of metallic \(\mathrm{Pt}\) are formed at the cathode. Calculate the charge on the Pt ions in this solution.

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