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Both \(\mathrm{KCl}\) and \(\mathrm{NH}_{4} \mathrm{Cl}\) are white solids. Suggest one reagent that would enable you to distinguish between these two compounds.

Short Answer

Expert verified
The reagent that can be used to distinguish between KCl and NH4Cl is sodium hydroxide (NaOH). When mixed with the compounds, NH4Cl reacts to form NH3 gas with a strong smell, whereas KCl remains unreactive.

Step by step solution

01

Understanding the properties of KCl and NH4Cl

Potassium Chloride (KCl) and Ammonium Chloride (NH4Cl) are both Chlorides but have different cations. KCl consists of K+ and Cl- ions. NH4Cl consists of NH4+ and Cl- ions. The primary difference between them lies in their cations.
02

Choosing the right reagent

When considering a reagent to distinguish between these two compounds, we need to think of a reagent that would react differently with NH4+ and K+. One possible reagent is NaOH (Sodium Hydroxide).
03

Explaining the action of the reagent

When Sodium Hydroxide (NaOH) is added to these compounds, it will react differently. NH4Cl reacts with NaOH to release ammonia gas (NH3), which has a distinct sharp, pungent smell. On the other hand, KCl does not react with NaOH, and there would be no gas evolved.

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Most popular questions from this chapter

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The molar mass of a certain metal carbonate, \(\mathrm{MCO}_{3}\), can be determined by adding an excess of \(\mathrm{HCl}\) acid to react with the carbonate and then "back-titrating" the remaining acid with \(\mathrm{NaOH}\). (a) Write an equation for these reactions. (b) In a certain experiment, \(20.00 \mathrm{~mL}\) of \(0.0800 \mathrm{M} \mathrm{HCl}\) were added to a \(0.1022-\mathrm{g}\) sample of \(\mathrm{MCO}_{3}\). The excess HCl required \(5.64 \mathrm{~mL}\) of \(0.1000 \mathrm{M} \mathrm{NaOH}\) for neutralization. Calculate the molar mass of the carbonate and identify \(\mathrm{M}\).

Calculate the \(\mathrm{pH}\) at the equivalence point for these titrations: (a) \(0.10 M \mathrm{HCl}\) versus \(0.10 \mathrm{M} \mathrm{NH}_{3}\), (b) \(0.10 \mathrm{M} \mathrm{CH}_{3} \mathrm{COOH}\) versus \(0.10 \mathrm{M} \mathrm{NaOH}\).

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