Chapter 17: Problem 108
A sample of \(0.96 \mathrm{~L}\) of \(\mathrm{HCl}\) at \(372 \mathrm{mmHg}\) and \(22^{\circ} \mathrm{C}\) is bubbled into \(0.034 \mathrm{~L}\) of \(0.57 \mathrm{MH}_{3}\). What is the \(\mathrm{pH}\) of the resulting solution? Assume the volume of solution remains constant and that the \(\mathrm{HCl}\) is totally dissolved in the solution.
Short Answer
Step by step solution
Determine the Moles of HCL
Determine the Moles of \( NH_{3} \)
Identify the limiting reactant and calculate \( [NH_{4}^{+}] \)
Compute pOH
Calculate pH
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Ideal Gas Law
- P is the pressure in atmospheres (atm).
- V is the volume in liters (L).
- n is the number of moles.
- R is the ideal gas constant, 0.0821 L·atm/mol·K.
- T is the temperature in Kelvin (K).
Limiting Reactant
- HCl: 0.020 mol
- NH_3: 0.019 mol
Moles Calculation
- Moles of NH_3: 0.019 mol (calculated using 0.57 mol/L and 0.034 L)