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Write equilibrium constant expressions for \(K_{\mathrm{c}}\) and for \(K_{P}\), if applicable, for these processes: (a) \(2 \mathrm{CO}_{2}(g) \rightleftharpoons 2 \mathrm{CO}(g)+\mathrm{O}_{2}(g)\) (b) \(3 \mathrm{O}_{2}(g) \rightleftharpoons 2 \mathrm{O}_{3}(g)\) (c) \(\mathrm{CO}(g)+\mathrm{Cl}_{2}(g) \rightleftharpoons \mathrm{COCl}_{2}(g)\) (d) \(\mathrm{H}_{2} \mathrm{O}(g)+\mathrm{C}(s) \rightleftharpoons \mathrm{CO}(g)+\mathrm{H}_{2}(g)\) (e) \(\mathrm{HCOOH}(a q) \rightleftharpoons \mathrm{H}^{+}(a q)+\mathrm{HCOO}^{-}(a q)\) (f) \(2 \mathrm{HgO}(s) \rightleftharpoons 2 \mathrm{Hg}(l)+\mathrm{O}_{2}(g)\)

Short Answer

Expert verified
The equilibrium constant expressions for each set can be summarized as follows: (a) \(K_{\mathrm{c}} = \frac{[\mathrm{CO}]^2\times [\mathrm{O}_{2}]}{[\mathrm{CO}_{2}]^2}\) and \(K_{P} = \frac{(P_{\mathrm{CO}})^{2}\times P_{\mathrm{O}_{2}}}{(P_{\mathrm{CO}_{2}})^{2}}\), (b) \(K_{\mathrm{c}} = \frac{[\mathrm{O}_{3}]^2}{[\mathrm{O}_{2}]^3}\) and \(K_{P} = \frac{(P_{\mathrm{O}_{3}})^{2}}{(P_{\mathrm{O}_{2}})^{3}}\), (c) \(K_{\mathrm{c}} = \frac{[\mathrm{COCl}_{2}]}{\mathrm{[CO]}\times\mathrm{[Cl}_{2}]}\) and \(K_{P} = \frac{P_{\mathrm{COCl}_{2}}}{P_{\mathrm{CO}}\times P_{\mathrm{Cl}_{2}}}\), (d) \(K_{\mathrm{c}} = \frac{\mathrm{[CO]}\times \mathrm{[H}_{2}]}{\mathrm{[H}_{2}\mathrm{O}}\) and \(K_{P} = \frac{P_{\mathrm{CO}}\times P_{\mathrm{H}_{2}}}{P_{\mathrm{H}_{2}\mathrm{O}}}\), (e) \(K_{\mathrm{c}} = \frac{\mathrm{[H}^{+}\mathrm{]}\times \mathrm{[HCOO}^{-}]}{\mathrm{[HCOOH]}}\), and (f) \(K_{\mathrm{c}} = [\mathrm{O}_{2}]\) and \(K_{P} = P_{\mathrm{O}_{2}}\).

Step by step solution

01

Theory: Definition of \(K_{\mathrm{c}}\) and \(K_{P}\)

The concentration equilibrium constant, \(K_{\mathrm{c}}\), for a general reaction \[aA + bB \rightleftharpoons cC + dD\] is given by \[K_{\mathrm{c}} = \frac{[C]^c [D]^d}{[A]^a [B]^b}\]Meanwhile, the pressure equilibrium constant, \(K_{P}\), is defined similarly, but using partial pressures of the gases, \[K_{P} = \frac{(P_C)^c (P_D)^d}{(P_A)^a (P_B)^b}.\]Let's apply this to the six reactions given, remembering not to include solids or liquids in the expressions.
02

(a) COâ‚‚ and CO reaction

The reaction is \(2 \mathrm{CO}_{2}(g) \rightleftharpoons 2 \mathrm{CO}(g)+\mathrm{O}_{2}(g)\). For \(K_{\mathrm{c}}\), we get\[K_{\mathrm{c}} = \frac{(\mathrm{[CO]})^{2}\times [\mathrm{O}_{2}]}{(\mathrm{[CO}_{2}])^{2}}\]Since all species are gases, we can also find \(K_{P}\),\[K_{P} = \frac{(P_{\mathrm{CO}})^{2}\times P_{\mathrm{O}_{2}}}{(P_{\mathrm{CO}_{2}})^{2}}.\]
03

(b) O₂ and O₃ reaction

The reaction is \(3 \mathrm{O}_{2}(g) \rightleftharpoons 2 \mathrm{O}_{3}(g)\).Similar to (a),\[K_{\mathrm{c}} = \frac{(\mathrm{[O}_{3}])^{2}}{(\mathrm{[O}_{2}])^{3}},\]and\[K_{P} = \frac{(P_{\mathrm{O}_{3}})^{2}}{(P_{\mathrm{O}_{2}})^{3}}.\]
04

(c) CO and Clâ‚‚ reaction

The reaction is \(\mathrm{CO}(g)+\mathrm{Cl}_{2}(g) \rightleftharpoons \mathrm{COCl}_{2}(g)\).Following the same process, \[K_{\mathrm{c}} = \frac{\mathrm{[COCl}_{2}]}{\mathrm{[CO]}\times\mathrm{[Cl}_{2}]},\]and\[K_{P} = \frac{P_{\mathrm{COCl}_{2}}}{P_{\mathrm{CO}}\times P_{\mathrm{Cl}_{2}}}.\]
05

(d) Hâ‚‚O and C reaction

The reaction is \(\mathrm{H}_{2} \mathrm{O}(g)+\mathrm{C}(s) \rightleftharpoons \mathrm{CO}(g)+\mathrm{H}_{2}(g)\). Here \(\mathrm{C}(s)\) is a solid, therefore it will not appear in the expressions. So, \[K_{\mathrm{c}} = \frac{\mathrm{[CO]}\times \mathrm{[H}_{2}\mathrm{]}}{\mathrm{[H}_{2}\mathrm{O}(g)}\]and\[K_{P} = \frac{P_{\mathrm{CO}}\times P_{\mathrm{H}_{2}}}{P_{\mathrm{H}_{2}\mathrm{O}}}.\]
06

(e) Reaction of HCOOH

Here, \(\mathrm{HCOOH}(a q) \rightleftharpoons \mathrm{H}^{+}(a q)+\mathrm{HCOO}^{-}(a q)\). As this reaction is in aqueous solution, only \(K_{\mathrm{c}}\) is applicable. \[K_{\mathrm{c}} = \frac{\mathrm{[H}^{+}\mathrm{]}\times \mathrm{[HCOO}^{-}\mathrm{]}}{\mathrm{[HCOOH]}}.\]
07

(f) HgO and Hg reaction

Finally, \(2 \mathrm{HgO}(s) \rightleftharpoons 2 \mathrm{Hg}(l)+\mathrm{O}_{2}(g)\). The \(\mathrm{HgO}(s)\) is a solid and \(\mathrm{Hg}(l)\) is a liquid, so only the Oâ‚‚(g) appears in the expressions. This gives \[K_{\mathrm{c}} = [\mathrm{O}_{2}],\]and\[K_{P} = P_{\mathrm{O}_{2}}.\]

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Kc (concentration equilibrium constant)
The concentration equilibrium constant, denoted as \(K_{c}\), represents a pivotal concept in chemical equilibrium. It quantifies the ratio of product concentrations to reactant concentrations, each raised to the power of their stoichiometric coefficients in a balanced chemical equation. For the general reaction \(aA + bB \rightleftharpoons cC + dD\), \(K_{c}\) is formalized as: \[K_{c} = \frac{[C]^c [D]^d}{[A]^a [B]^b}\]
What \(K_{c}\) essentially tells us is how the concentrations of the reactants and products relate when the system is in equilibrium. Higher \(K_{c}\) values indicate a greater concentration of products relative to reactants, suggesting the reaction favors the formation of products. Conversely, a lower \(K_{c}\) implies a preference for reactants.
It’s important to note that \(K_{c}\) applies exclusively to reactions in the gas or solution phase, with concentrations expressed in moles per liter (\(M\)). The units of \(K_{c}\) depend on the particular reaction, determined by the difference in moles between product and reactant sides.
Kp (pressure equilibrium constant)
The pressure equilibrium constant, or \(K_{p}\), is closely related to \(K_{c}\), but it specifically pertains to gas-phase reactions. Instead of concentrations, \(K_{p}\) uses the partial pressures of the gases involved. For the system \(aA(g) + bB(g) \rightleftharpoons cC(g) + dD(g)\), the formula appears as: \[K_{p} = \frac{(P_C)^c (P_D)^d}{(P_A)^a (P_B)^b}\]
Understanding \(K_{p}\) involves recognizing how gaseous reactants and products' pressures balance at equilibrium. While \(K_{p}\) and \(K_{c}\) are related, they are not interchangeable, as pressure and concentration are distinct measures.* To convert between \(K_{c}\) and \(K_{p}\), one can use the relationship: \[K_{p} = K_{c}(RT)^{\Delta n}\] where \(R\) is the ideal gas constant, \(T\) is temperature in Kelvin, and \(\Delta n\) represents the change in moles of gas (moles of gaseous products minus moles of gaseous reactants).
These constants provide crucial insights into the conditions under which a reaction can be manipulated to achieve desired product yields.
Reaction Quotient
The reaction quotient, \(Q\), is a valuable tool in predicting the direction of a reaction under non-equilibrium conditions. It shares a mathematical form with \(K_{c}\) and \(K_{p}\) but is used when a system has not yet reached equilibrium. For the reaction \(aA + bB \rightleftharpoons cC + dD\), \(Q_{c}\) is given by: \[Q_{c} = \frac{[C]^c [D]^d}{[A]^a [B]^b}\]
Similarly, for gaseous reactions, \(Q_{p}\) is: \[Q_{p} = \frac{(P_C)^c (P_D)^d}{(P_A)^a (P_B)^b}\] The role of \(Q\) is to help chemists determine whether a reaction will proceed toward products or reactants to reach equilibrium:
  • If \(Q < K\), the reaction will shift to the right, producing more products until equilibrium is reached.
  • If \(Q > K\), the reaction will shift to the left, forming more reactants until equilibrium is established.
  • When \(Q = K\), the reaction is at equilibrium, with no net change occurring in the concentration of reactants and products.
By providing this comparison, \(Q\) serves as a practical measure for assessing reaction progress and equilibrium positions.

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Most popular questions from this chapter

Consider this reaction: $$ \mathrm{N}_{2}(g)+\mathrm{O}_{2}(g) \rightleftharpoons 2 \mathrm{NO}(g) $$ The equilibrium constant \(K_{P}\) for the reaction is \(1.0 \times\) \(10^{-15}\) at \(25^{\circ} \mathrm{C}\) and 0.050 at \(2200^{\circ} \mathrm{C}\). Is the formation of nitric oxide endothermic or exothermic? Explain your answer.

When a gas was heated under atmospheric conditions, its color was found to deepen. Heating above \(150^{\circ} \mathrm{C}\) caused the color to fade, and at \(550^{\circ} \mathrm{C}\) the color was barely detectable. However, at \(550^{\circ} \mathrm{C}\), the color was partially restored by increasing the pressure of the system. Which of these best fits this description? Justify your choice. (a) A mixture of hydrogen and bromine, (b) pure bromine, (c) a mixture of nitrogen dioxide and dinitrogen tetroxide. (Hint: Bromine has a reddish color and nitrogen dioxide is a brown gas. The other gases are colorless.)

Baking soda (sodium bicarbonate) undergoes thermal decomposition as $$ 2 \mathrm{NaHCO}_{3}(s) \rightleftharpoons \mathrm{Na}_{2} \mathrm{CO}_{3}(s)+\mathrm{CO}_{2}(g)+\mathrm{H}_{2} \mathrm{O}(g) $$ Would we obtain more \(\mathrm{CO}_{2}\) and \(\mathrm{H}_{2} \mathrm{O}\) by adding extra baking soda to the reaction mixture in (a) a closed vessel or (b) an open vessel?

A reaction vessel contains \(\mathrm{NH}_{3}, \mathrm{~N}_{2},\) and \(\mathrm{H}_{2}\) at equilibrium at a certain temperature. The equilibrium concentrations are \(\left[\mathrm{NH}_{3}\right]=0.25 \mathrm{M},\left[\mathrm{N}_{2}\right]=0.11 \mathrm{M}\) and \(\left[\mathrm{H}_{2}\right]=1.91 \mathrm{M}\). Calculate the equilibrium constant \(K_{\mathrm{c}}\) for the synthesis of ammonia if the reaction is represented as (a) \(\mathrm{N}_{2}(g)+3 \mathrm{H}_{2}(g) \rightleftharpoons 2 \mathrm{NH}_{3}(g)\) (b) \(\frac{1}{2} \mathrm{~N}_{2}(g)+\frac{3}{2} \mathrm{H}_{2}(g) \rightleftharpoons \mathrm{NH}_{3}(g)\)

Outline the steps for calculating the concentrations of reacting species in an equilibrium reaction.

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