Chapter 10: Problem 53
Acetylene \(\left(\mathrm{C}_{2} \mathrm{H}_{2}\right)\) has a tendency to lose two protons \(\left(\mathrm{H}^{+}\right)\) and form the carbide ion \(\left(\mathrm{C}_{2}^{2-}\right),\) which is present in a number of ionic compounds, such as \(\mathrm{CaC}_{2}\) and \(\mathrm{MgC}_{2}\). Describe the bonding scheme in the \(\mathrm{C}_{2}^{2}-\) ion in terms of molecular orbital theory. Compare the bond order in \(\mathrm{C}_{2}^{2-}\) with that in \(\mathrm{C}_{2}\)
Short Answer
Step by step solution
Learn about hybridization
Understand the formation of molecular orbitals
Detail the electron configuration of \(\mathrm{C}_{2}^{2-}\)
Calculate bond order
Compare Bond Order with \(\mathrm{C}_{2}\)
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