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The density of ammonia gas under certain conditions is \(0.625 \mathrm{~g} / \mathrm{L} .\) Calculate its density in \(\mathrm{g} / \mathrm{cm}^{3}\).

Short Answer

Expert verified
The density of ammonia gas under the given conditions is \(0.000625 \) g/cm^3.

Step by step solution

01

Understand the Conversion

First, you need to understand that the conversion is from larger units (liters) to smaller units (cubic centimeters). Given that 1 liter (L) is equivalent to 1000 cubic centimeters (cm^3), this means when converting to a smaller unit, the value should become smaller.
02

Perform the Conversion

To perform the conversion, utilize the relationship between liters and cubic centimeters. The given density is 0.625g/L. So, divide this value by 1000 (because 1L = 1000 cm^3) to get the density in g/cm^3. Thus, the density in g/cm^3 is \( \frac{0.625}{1000} = 0.000625 \) g/cm^3.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Ammonia Gas: Understanding Its Properties
Ammonia gas is a compound made of nitrogen and hydrogen, with the formula \( NH_3 \). It is a colorless gas with a pungent smell, often found in household cleaners and fertilizers. Ammonia's gaseous form is significant not only in industrial applications but also in environmental and biological processes.
  • It is lighter than air, which means it rises quickly when released.
  • In its pure form, it's a strong irritant and can be hazardous when inhaled.
  • Ammonia dissolves in water to form ammonium hydroxide, a weak base that is often used in cleaning products.
When discussing the properties of ammonia gas, we often encounter its density. Density tells us how much mass a substance has in a certain volume, a key factor in industrial processes that use ammonia.
Grams per Liter: A Measure of Density
Grams per liter (g/L) is a common unit used to express density for substances, particularly gases and liquids. This unit indicates how many grams of a substance exist within one liter of volume. It's a useful measure because it allows for easy comparison between different substances in similar conditions.
For ammonia gas, the density is given as \(0.625\, \text{g/L}\). This means that in each liter of space, there is 0.625 grams of ammonia. This measure can easily be converted to other units depending on the context needed, such as grams per cubic centimeter (g/cm³) for more precise or smaller-scale applications. Understanding this unit helps when determining how much space a substance will occupy or how much a certain volume weighs.
Grams per Cubic Centimeter: Precise Density Measurement
Converting density from grams per liter to grams per cubic centimeter provides a more detailed measure of density, crucial for scientific and engineering calculations. This conversion often helps when dealing with smaller quantities or when more precision is necessary.
To convert from grams per liter to grams per cubic centimeter, you divide the density by 1000, because one liter equals 1000 cubic centimeters. For ammonia, with a density of \(0.625\, \text{g/L}\), the conversion yields \(0.000625\, \text{g/cm}^3\).
  • This conversion is critical in applications where precise measurement and control of substance quantities are required.
  • It provides better accuracy for small volumes, making it easier to calculate exact amounts needed in scientific or industrial processes.
Thus, understanding and performing this conversion is vital for anyone working with chemical substances and involves interpreting measurements accurately across different units.

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Most popular questions from this chapter

Fluoridation is the process of adding fluorine compounds to drinking water to help fight tooth decay. A concentration of 1 ppm of fluorine is sufficient for the purpose. (1 ppm means \(1 \mathrm{~g}\) of fluorine per 1 million g of water.) The compound normally chosen for fluoridation is sodium fluoride, which is also added to some toothpastes. Calculate the quantity of sodium fluoride in kilograms needed per year for a city of 50,000 people if the daily consumption of water per person is 150 gallons. What percent of the sodium fluoride is "wasted" if each person uses only \(6.0 \mathrm{~L}\) of water a day for drinking and cooking? (Sodium fluoride is 45.0 percent fluorine by mass. 1 gallon \(=3.79 \mathrm{~L} ; 1\) year \(=365\) days; density of water \(=1.0 \mathrm{~g} / \mathrm{mL} .)\)

Vanillin (used to flavor vanilla ice cream and other foods) is the substance whose aroma the human nose detects in the smallest amount. The threshold limit is \(2.0 \times 10^{-11} \mathrm{~g}\) per liter of air. If the current price of \(50 \mathrm{~g}\) of vanillin is \(\$ 112,\) determine the cost to supply enough vanillin so that the aroma could be detectable in a large aircraft hangar of volume \(5.0 \times 10^{7} \mathrm{ft}^{3}\)

The surface area and average depth of the Pacific Ocean are \(1.8 \times 10^{8} \mathrm{~km}^{2}\) and \(3.9 \times 10^{3} \mathrm{~m},\) respectively. Calculate the volume of water in the ocean in liters.

A 1.0 -mL volume of seawater contains about \(4.0 \times\) \(10^{-12} \mathrm{~g}\) of gold. The total volume of ocean water is \(1.5 \times 10^{21} \mathrm{~L} .\) Calculate the total amount of gold in grams that is present in seawater and its worth in dollars, assuming that the price of gold is \(\$ 350\) an ounce. With so much gold out there, why hasn't someone become rich by mining gold from the ocean?

How many minutes does it take light from the sun to reach Earth? (The distance from the sun to Earth is 93 million mi; the speed of light \(=3.00 \times\) \(\left.10^{8} \mathrm{~m} / \mathrm{s} .\right)\)

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