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Identify the nucleophile and the electrophile in the nucleophilic substitution reaction of 1 -chloropentane with sodium methoxide.

Short Answer

Expert verified
Nucleophile: methoxide ion (\(\text{CH}_3\text{O}^-\)); Electrophile: carbon atom in 1-chloropentane.

Step by step solution

01

Identify the Reactants

The reaction involves 1-chloropentane, which is an alkyl halide, and sodium methoxide, which is a source of the methoxide ion (\(\text{CH}_3\text{O}^-\)), a strong nucleophile.
02

Determine the Nucleophile

A nucleophile is a species that donates a pair of electrons to form a new chemical bond. In this reaction, the methoxide ion (\(\text{CH}_3\text{O}^-\)) acts as the nucleophile because it has a lone pair of electrons that can be donated.
03

Find the Electrophile

An electrophile is a species that accepts a pair of electrons during the formation of a new chemical bond. In 1-chloropentane, the carbon atom attached to the chlorine (C-Cl) is electron-deficient and hence acts as an electrophile.
04

Conclusion

In the nucleophilic substitution reaction, the nucleophile is the methoxide ion (\(\text{CH}_3\text{O}^-\)), and the electrophile is the carbon atom in 1-chloropentane.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Nucleophile
In chemistry, a nucleophile is a reactive species rich in electrons. These molecules or ions seek out positive charges where they can donate a pair of electrons. During chemical reactions, nucleophiles are attracted to electrophiles, which have a positive charge or a partial positive charge.
  • Nucleophiles can have full negative charges (like \( ext{CH}_3 ext{O}^-\)), or simply have an excess of electron density.
  • They often bear lone pairs or \( ext{pi}\) bonds, making them ready to form new bonds.
  • Common examples of nucleophiles include:
    • Hydroxide ion (\( ext{OH}^-\))
    • Ammonia (\( ext{NH}_3\))
    • Water (\( ext{H}_2 ext{O}\))
In the reaction of 1-chloropentane with sodium methoxide, the methoxide ion (\( ext{CH}_3 ext{O}^-\)) is the nucleophile. With its lone pair of electrons, it attacks electron-deficient centers to form new bonds.
Electrophile
On the flip side, electrophiles are electron-deficient species that actively seek out electrons. They accept electron pairs from nucleophiles to form new bonds. Electrophiles can be positively charged ions or neutral molecules with a positively charged site.
  • These entities are crucial in many types of chemical reactions, especially nucleophilic substitution reactions.
  • Electrophiles tend to have a full or partial positive charge.
In the scenario of 1-chloropentane, the carbon atom bonded to the halogen (chlorine) is slightly electrophilic due to the \( ext{C-Cl}\) bond.
The high electronegativity of chlorine creates an electron-deficient carbon, which then acts as the target for nucleophilic attack by the methoxide ion.
Thus, the carbon in 1-chloropentane functions as the electrophile, joining forces with the nucleophile to drive the substitution process.
Alkyl Halide
Alkyl halides, also known as haloalkanes, form a class of compounds where a halogen atom is bonded to an alkyl group. These compounds are characterized by the general formula \( ext{R-X}\), where \( ext{R}\) represents an alkyl group and \( ext{X}\) represents a halogen like \( ext{Cl}\), \( ext{Br}\), or \( ext{I}\).
Alkyl halides have special reactivity due to the electronegativity difference between carbon and the halogen atom.
  • This difference polarizes the \\( ext{C-X}\) bond, resulting in a slightly positive carbon, which makes these compounds suitable for nucleophilic substitution reactions.
  • Additionally, the leaving group (halogen) is usually replaced by a nucleophile, such as the methoxide ion in our given reaction.
The 1-chloropentane in the exercise serves as the alkyl halide, with chlorine as the halogen connected to a pentyl group.
This structure sets the stage for the attack by the nucleophile, proceeding through a mechanism where chlorine departs, and the methoxide group takes its place.

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