Chapter 22: Problem 3
Give the type of hybrid orbitals used by xenon in each species. a. \(\mathrm{XeF}_{2}\) b. \(\mathrm{XeF}_{4}\) c. \(\mathrm{XeO}_{3}\) d. \(\mathrm{XeOF}_{4}\) e. \(\mathrm{XeO}_{4}\) f. \(\mathrm{XeO}_{6}^{4-}\)
Short Answer
Expert verified
a. sp鲁d, b. sp鲁d虏, c. sp鲁, d. sp鲁d虏, e. sp鲁, f. sp鲁d虏
Step by step solution
01
Determine the Number of Regions of Electron Density
For each molecule, the first step is to find the number of regions of electron density surrounding the xenon atom. This is done by adding the number of bonds to xenon and lone pairs of electrons on xenon. A simple rule is: each bond counts as one, and each lone pair also counts as one.
02
Identify the Hybridization
Using the number of regions of electron density from Step 1, identify the type of hybrid orbitals. Remember that 2 regions corresponds to sp, 3 to sp虏, 4 to sp鲁, 5 to sp鲁d, and 6 to sp鲁d虏 hybridization.
03
Apply to \\(\mathrm{XeF}_{2}\\)
XeF鈧 has 2 bonds and 3 lone pairs, totaling 5 regions of electron density. For 5 regions, the hybridization is sp鲁d.
04
Apply to \\(\mathrm{XeF}_{4}\\)
XeF鈧 has 4 bonds and 2 lone pairs, totaling 6 regions of electron density. For 6 regions, the hybridization is sp鲁d虏.
05
Apply to \\(\mathrm{XeO}_{3}\\)
XeO鈧 has 3 bonds and 1 lone pair, totaling 4 regions of electron density. For 4 regions, the hybridization is sp鲁.
06
Apply to \\(\mathrm{XeOF}_{4}\\)
XeOF鈧 has 5 bonds and 1 lone pair, totaling 6 regions of electron density. For 6 regions, the hybridization is sp鲁d虏.
07
Apply to \\(\mathrm{XeO}_{4}\\)
XeO鈧 has 4 bonds and no lone pairs, totaling 4 regions of electron density. For 4 regions, the hybridization is sp鲁.
08
Apply to \\(\mathrm{XeO}_{6}^{4-}\\)
XeO鈧嗏伌鈦 has 6 bonds and no lone pairs, totaling 6 regions of electron density. For 6 regions, the hybridization is sp鲁d虏.
Unlock Step-by-Step Solutions & Ace Your Exams!
-
Full Textbook Solutions
Get detailed explanations and key concepts
-
Unlimited Al creation
Al flashcards, explanations, exams and more...
-
Ads-free access
To over 500 millions flashcards
-
Money-back guarantee
We refund you if you fail your exam.
Over 30 million students worldwide already upgrade their learning with 91影视!
Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Electron Density
Electron density refers to the distribution of electrons in a molecule around a central atom. It's a critical concept in determining the type of hybridization necessary for bonding. Think of it as the electron聽traffic surrounding the central atom. If there鈥檚 a lot of activity鈥攖hat is, many bonds and lone pairs鈥攖he electron density is high. Conversely, fewer bonds or lone pairs mean lower electron density.
To calculate electron density, we count every bond (single, double, or triple) and every lone pair of electrons as one region of electron density. This accumulation of electron regions influences the molecular geometry and the type of hybrid orbitals needed. For example, in the case of \( ext{XeF}_2\), there are 2 bonds and 3 lone pairs, which totals 5 regions of electron density. Understanding these concepts helps predict the shape and the type of hybridization for molecules.
To calculate electron density, we count every bond (single, double, or triple) and every lone pair of electrons as one region of electron density. This accumulation of electron regions influences the molecular geometry and the type of hybrid orbitals needed. For example, in the case of \( ext{XeF}_2\), there are 2 bonds and 3 lone pairs, which totals 5 regions of electron density. Understanding these concepts helps predict the shape and the type of hybridization for molecules.
sp鲁 Hybridization
When a central atom is surrounded by 4 regions of electron density, sp鲁 hybridization occurs. These regions can be comprised of any combination of bonds and lone pairs. This hybridization involves mixing one s orbital and three p orbitals in the atom's valence shell to form four equivalent orbitals.
The resulting orbitals form a tetrahedral shape, which is ideal for minimizing repulsions between electron clouds. The bond angles in a perfect sp鲁 hybridized tetrahedron are about 109.5 degrees. This type of hybridization is common in carbon compounds, such as methane (CH鈧), but can also be found in compounds like \( ext{XeO}_3\) and \( ext{XeO}_4\), where xenon exhibits this tetrahedral structure due to its 4 regions of electron density.
The resulting orbitals form a tetrahedral shape, which is ideal for minimizing repulsions between electron clouds. The bond angles in a perfect sp鲁 hybridized tetrahedron are about 109.5 degrees. This type of hybridization is common in carbon compounds, such as methane (CH鈧), but can also be found in compounds like \( ext{XeO}_3\) and \( ext{XeO}_4\), where xenon exhibits this tetrahedral structure due to its 4 regions of electron density.
sp鲁d Hybridization
In cases where a central atom has 5 regions of electron density, sp鲁d hybridization comes into play. This involves the mixing of one s, three p, and one d orbitals. The resulting hybrid orbitals create a trigonal bipyramidal arrangement鈥攊magine a pair of pyramids base-to-base.
This configuration allows for better accommodation of five regions by distributing electron density evenly and minimizes repulsion. The typical bond angle between equatorial positions in this hybridization is 120 degrees, while the angle between equatorial and axial is 90 degrees. \( ext{XeF}_2\) is a classic example of sp鲁d hybridization in xenon compounds, with xenon actually adopting a linear geometry due to three lone pairs occupying the equatorial positions.
This configuration allows for better accommodation of five regions by distributing electron density evenly and minimizes repulsion. The typical bond angle between equatorial positions in this hybridization is 120 degrees, while the angle between equatorial and axial is 90 degrees. \( ext{XeF}_2\) is a classic example of sp鲁d hybridization in xenon compounds, with xenon actually adopting a linear geometry due to three lone pairs occupying the equatorial positions.
sp鲁d虏 Hybridization
For molecules with 6 regions of electron density, sp鲁d虏 hybridization is necessary. This process involves the combination of one s orbital, three p orbitals, and two d orbitals to form six evenly distributed hybrid orbitals. These orbitals arrange themselves in an octahedral geometry鈥攁 shape with six equal vertices.
This type of hybridization is typical in many transition metal complexes but also in certain inert gas compounds. It provides optimal angles of 90 degrees between all adjacent regions, which significantly reduces electron repulsion and stabilizes the molecule. Notable examples include \( ext{XeF}_4\), \( ext{XeOF}_4\), and \( ext{XeO}_6^{4-}\), where xenon's high electronegativity allows it to form such complex structures. These examples illustrate how xenon can mimic transition metal behavior by utilizing its available d orbitals for bonding.
This type of hybridization is typical in many transition metal complexes but also in certain inert gas compounds. It provides optimal angles of 90 degrees between all adjacent regions, which significantly reduces electron repulsion and stabilizes the molecule. Notable examples include \( ext{XeF}_4\), \( ext{XeOF}_4\), and \( ext{XeO}_6^{4-}\), where xenon's high electronegativity allows it to form such complex structures. These examples illustrate how xenon can mimic transition metal behavior by utilizing its available d orbitals for bonding.