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Write the formulas of the products formed from the reaction of propene with each of the following substances: (a) \(\mathrm{H}_{2} ;\) (b) \(\mathrm{Cl}_{2}\); (c) \(\mathrm{HCl} ;\) (d) \(\mathrm{H}_{2} \mathrm{O}\) (in acid).

Short Answer

Expert verified
The products for the reactions are propane, 1,2-dichloropropane, 2-chloropropane, and 2-propanol respectively.

Step by step solution

01

Reaction with Hydrogen

Adding hydrogen in the presence of a catalyst to propene will cause an addition reaction. The hydrogen atoms will add to the carbon atoms of the double bond in a process known as hydrogenation, forming propane \(\mathrm{C}_{3} \mathrm{H}_{8}\).
02

Reaction with Chlorine

Adding chlorine to propene will cause a halogenation reaction. The chlorine atoms will add to the carbon atoms of the double bond, creating 1,2-dichloropropane \(\mathrm{ClCH}_{2}-\mathrm{CHClCH}_{3}\).
03

Reaction with Hydrogen Chloride

The reaction of propene with hydrogen chloride will cause a hydrohalogenation reaction. The molecule will add across the double bond following Markovnikov's rule, which means the hydrogen will add to the carbon with more hydrogen atoms already. As a result, we will get 2-chloropropane \(\mathrm{CH}_{3}-\mathrm{CHClCH}_{3}\).
04

Reaction with Water

The reaction of propene with water, especially under acidic conditions, will cause an hydration reaction. The water molecule will add across the double bond based on Markovnikov's rule. This gives us 2-propanol \(\mathrm{CH}_{3}-\mathrm{CHOHCH}_{3}\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Addition Reactions
In organic chemistry, addition reactions are a fundamental type of chemical reaction where atoms or groups of atoms are added to a molecule. These reactions typically occur at carbon-carbon double or triple bonds. In the context of alkenes like propene, addition reactions can transform unsaturated hydrocarbons into more saturated ones. Examples include the addition of hydrogen, halogens, or water across a double bond.
  • Addition reactions reduce the unsaturation of the molecule.
  • They are often catalyzed by various agents to increase the reaction rate.
  • The addition can be symmetrical, like with halogens, or asymmetrical, involving different atoms.
This versatility makes addition reactions crucial in the synthesis of various organic compounds, providing pathways to form alcohols, alkanes, and haloalkanes.
Hydrogenation
Hydrogenation is a specific type of addition reaction where hydrogen gas is added to an alkene. This process requires a catalyst, typically platinum, palladium, or nickel, which facilitates the addition. During hydrogenation, the hydrogen atoms add across the carbon-carbon double bond, converting it into a single bond and resulting in an alkane. For example, propene undergoes hydrogenation to form propane, which is a saturated hydrocarbon.
  • Hydrogenation increases the hydrogen content in the molecule.
  • Catalysts are crucial for the reaction to proceed at a practical rate.
  • This reaction is extensively used in the food industry, such as in the hydrogenation of oils to make margarine.
Hydrogenation not only changes the degree of saturation but also alters certain properties of the resulting compound, such as its melting point and texture.
Hydrohalogenation
Hydrohalogenation involves the addition of hydrogen halides like HCl or HBr to alkenes. In this reaction, the hydrogen from the acid attaches to one carbon of the double bond, while the halide ion attaches to the other. For propene, reacting with HCl results in the formation of 2-chloropropane. One of the key aspects of hydrohalogenation is its adherence to Markovnikov's rule, which guides the positioning of the halogen.
  • The hydrogen atom often adds to the carbon with more hydrogens already attached.
  • The halogen adds to the carbon with fewer hydrogen atoms.
  • This results in a regioselective addition, favoring the formation of the more stable carbonium intermediate.
Understanding hydrohalogenation helps in predicting the major product in reactions involving hydrogen halides and unsymmetrical alkenes.
Markovnikov's Rule
Markovnikov's Rule is a principle used to determine the outcome of addition reactions involving unsymmetrical alkenes and reagents. The rule states that when an unsymmetrical reagent adds to an unsymmetrical alkene, the more electronegative atom or group attaches to the carbon with fewer hydrogen atoms. This is because the intermediate formed in this fashion is more stable. For instance, in the reaction of propene with HCl, the hydrogen typically adds to the end carbon of the double bond, which has more hydrogens, while the chloride ion attaches itself to the middle carbon.
  • This guides the product distribution, often leading to a major and minor product.
  • The preference is dictated by the stability of the resulting carbocation intermediate.
  • Markovnikov's Rule helps in predicting the regiochemistry of addition reactions.
Grasping this rule is essential for students to predict which product will be the major one in hydrohalogenation and similar reactions.

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Most popular questions from this chapter

The reduction of aldehydes and ketones with a suitable hydride-containing reducing agent is a good way of synthesizing alcohols. This approach would be even more effective if, instead of a hydride, we could use a source of nucleophilic carbon. Attack by a carbon atom on a carbonyl group would give an alcohol and simultaneously form a carbon-to-carbon bond. How can we make a C atom in an alkane nucleophilic? This was achieved by Victor Grignard, who created the organometallic reagent \(\mathrm{R}-\mathrm{MgBr},\) with the following reaction in diethyl ether: $$\mathrm{R}-\mathrm{Br}+\mathrm{Mg} \longrightarrow \mathrm{R}-\mathrm{MgBr}$$ The Grignard reagent is rarely isolated. It is formed in solution and used immediately in the desired reaction. The alkylmetal bond is highly polar, with the partial negative charge on the \(\mathrm{C}\) atom, which makes the C atom highly nucleophilic. The Grignard reagent \((\mathrm{R}-\mathrm{MgBr})\) can attack a carbonyl group in an aldehyde or ketone as follows: Addition of dilute aqueous acid solution to the metal alkoxide furnishes the alcohol. The important synthetic consequence of this procedure is that we have prepared a product with more carbon atoms than present in the starting material. A simple starting material can be transformed into a more complex molecule. (a) What is the product of the reaction between methanal and the Grignard reagent formed from 1-bromobutane after the addition of dilute acid? (b) By using a Grignard reagent, devise a synthesis for 2-hexanol. (c) By using a Grignard reagent, devise a synthesis for 2 -methyl- 2 -hexanol. (d) Grignard reagents can also be formed with aryl halides, such as chlorobenzene. What would be the product of the reaction between the Grignard reagent of chlorobenzene and propanone? Can you think of an alternative synthesis of this product, again using a Grignard reagent? (e) The basicity of the \(C\) atom bound to the magnesium in the Grignard reagent can be used to make Grignard reagents of terminal alkynes. Write the equation of the reaction between ethylmagnesium bromide and 1-hexyne. [Hint: Ethane is evolved.] (f) By using a Grignard reagent, suggest a synthesis for 2 -heptyn-1-ol.

Answer the following questions for this E1 reaction: $$\begin{array}{c} \mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{C}\left(\mathrm{CH}_{3}\right)_{2} \mathrm{Br}+\mathrm{CH}_{3} \mathrm{OH} \longrightarrow \mathrm{CH}_{3} \mathrm{CH}=\mathrm{C}\left(\mathrm{CH}_{3}\right)_{2}+\mathrm{Br}^{-}+\mathrm{CH}_{3} \mathrm{OH}_{2}^{+} \end{array}$$ (a) What is the rate expression for the reaction? (b) Draw the reaction profile for the reaction. Label all parts. Assume that the products are lower in energy than the reactants. (c) What is the effect on the rate of the reaction of doubling the concentration of \(\mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{C}\left(\mathrm{CH}_{3}\right)_{2} \mathrm{Br} ?\) (d) What is the effect on the rate of the reaction of doubling the concentration of \(\mathrm{CH}_{3} \mathrm{OH} ?\)

(a) Which of the nucleophiles \(\mathrm{CN}^{-}\) or \(\mathrm{Cl}^{-}\) reacts faster with \(\mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{I}\) in an \(\mathrm{S}_{\mathrm{N}} 2\) reaction? (b) Which of the substrates, \(\mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{CH}\left(\mathrm{CH}_{3}\right) \mathrm{CH}_{2} \mathrm{I}\) or \(\mathrm{CH}_{3} \mathrm{I},\) reacts faster with \(\mathrm{OH}^{-}\) in an \(\mathrm{S}_{\mathrm{N}}\) 2 reaction?

Write equations for the substitution reaction of \(n\) -bromopentane, a typical primary haloalkane with the following reagents: (a) \(\mathrm{NaN}_{3};\) (b) \(\mathrm{N}\left(\mathrm{CH}_{3}\right)_{3};\) (c) \(\mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{C} \equiv \mathrm{CNa};\) (d) \(\mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{SNa}\).

Nylon 66 is produced by the reaction of 1,6 -hexanediamine with adipic acid. A different nylon polymer is obtained if sebacyl chloride is substituted for the adipic acid. What is the basic repeating unit of this nylon structure?

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