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The so-called pyroanions, \(\mathrm{X}_{2} \mathrm{O}_{7}^{n-},\) form a series of structurally similar polyatomic anions for the elements Si, P, and S. (a) Draw the Lewis structures of these anions, and predict the geometry of the anions. What is the maximum number of atoms that can lie in a plane? (b) Each pyroanion in part (a) corresponds to a pyroacid, \(\mathrm{X}_{2} \mathrm{O}_{7} \mathrm{H}_{n} .\) Compare each pyroacid to the acid containing only one atom of the element in its maximum oxidation state. From this comparison, suggest a strategy for the preparation of these pyroacids. (c) What is the chlorine analogue of the pyroanions? For which acid is this species the anhydride?

Short Answer

Expert verified
The Lewis structures for the pyroanions result in tetrahedral molecular geometries. The maximum number of atoms that can lie in a plane is three. Compared with their monoatomic acids, the pyroacids have a higher oxidation state, suggesting that a suitable preparation strategy would be to increase the oxidation state of the central atom. The chlorine analogue of a pyroanion would be \(\mathrm{Cl}_{2} \mathrm{O}_{7},\) the anhydride of perchloric acid.

Step by step solution

01

Drawing Lewis Structures & Predicting Geometry

Start by determining the Lewis structures for the pyroanions of Si, P, and S. All three anions will follow the general structure of \(\mathrm{X}_{2} \mathrm{O}_{7}^{n-}\), where X represents the element in question (Si, P, or S). Using Lewis dot structures, place the more electronegative atoms (Oxygen in this case) around the central atom (X) and start filling up the octets. Your resulting structures should have a single atom of X at the center, surrounded by bonded oxygen atoms. For part two of this step, you need to employ the VSEPR model to predict the geometry based on the number of pairs of electrons around the central atom. In this case, 4 regions of electron density around each X, two bonding and two nonbonding, suggest a tetrahedral molecular geometry. The number of atoms that can lie in a plane here would be three.
02

Comparing Pyroacids and Acids

When we assign hydrogen atoms to each of the pyroanions, turning them into pyroacids, we see that the compounds all have a higher oxidation state than their corresponding monoatomic acids. This is due to the extra oxygen atoms, which pull more strongly on the hydrogen's electron, resulting in a higher oxidation state for the central atom. From this comparison, we can infer that a strategy for preparing these pyroacids would be to increase the oxidation state of the central atom, perhaps through some sort of oxidation reaction.
03

Identifying Chlorine Analogue and Associated Acid

The chlorine analogue of the pyroanions would have a similar structure, but with Cl as the central atom, resulting in \(\mathrm{Cl}_{2} \mathrm{O}_{7} .\) The corresponding acid would be perchloric acid, \( \mathrm{HClO}_{4},\) as it is the most common acid with chlorine in its highest possible oxidation state, +7. In this case, perchloric acid is the species for which \( \mathrm{Cl}_{2} \mathrm{O}_{7}\) is the anhydride.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Lewis structures
Lewis structures are a way to represent molecules using symbols and dots. These structures help us visualize how atoms are bonded and show the arrangement of valence electrons. When drawing a Lewis structure for an anion like the pyroanions (\(\mathrm{X}_{2}\mathrm{O}_{7}^{n-}\)), start by determining the total number of valence electrons. You will add an extra electron for each negative charge on the anion.
For example, in these structures, each X (Si, P, or S) atom is in the center and is surrounded by oxygen atoms. Often, the central atom is less electronegative, enabling it to share more electrons to achieve a full octet.
Next, distribute the electrons around the atoms, aiming to ensure each atom fulfills the octet rule (having eight electrons either in bonds or as lone pairs). Remember to pair electrons as needed and show any remaining pairs as lone pairs on the outer atoms.
VSEPR model
The VSEPR (Valence Shell Electron Pair Repulsion) model is a useful tool for predicting the shapes of molecules. According to the VSEPR theory, regions of electron density—such as bonds and lone pairs—will arrange themselves to minimize repulsion, resulting in a specific geometry.
In pyroanions like \(\mathrm{X}_{2}\mathrm{O}_{7}^{n-}\), each X element has four regions of electron density: two bonding domains (oxygen atoms) and two nonbonding domains (lone pairs). This configuration suggests a tetrahedral shape with angles close to 109.5° between electron pairs.
While the whole structure may appear complex, note that you can visualize the central atom and adjacent atoms as forming a basic pyramid shape. Importantly, only three of these atoms can typically lie flat in a single plane, providing an easy understanding of molecular spatial arrangement.
oxidation state
Oxidation states indicate the degree of oxidation of an atom within a molecule. These numbers help determine electron ownership among elements within compounds.
For elements like Si, P, and S within pyroanions, the oxidation state is higher in pyroacids as compared to their simpler forms. This arises from the addition of oxygen, which exerts a greater pull on electrons due to its high electronegativity. In \(\mathrm{X}_{2}\mathrm{O}_{7}^{n-}\), more oxygen atoms elevate the central X atom's oxidation number through electron withdrawal.
Understanding oxidation states aids in predicting reaction outcomes. By manipulating the oxidation state—often achieved through controlled reactions or additives—scientists can readily target the synthesis or modification of compounds like pyroacids, by increasing electron withdrawal from the central atom.

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