/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 29 Three different sets of data of ... [FREE SOLUTION] | 91Ó°ÊÓ

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Three different sets of data of \([\mathrm{A}]\) versus time are giv the following table for the reaction \(A \longrightarrow\) prod [Hint: There are several ways of arriving at answer each of the following six questions. $$\begin{array}{cccccc} \hline \text { I } & & \text { II } & & \text { III } & \\ \hline \begin{array}{c} \text { Time, } \\ \text { s } \end{array} & \text { [A], M } & \begin{array}{c} \text { Time, } \\ \text { s } \end{array} & \text { [A], M } & \begin{array}{c} \text { Time, } \\ \text { s } \end{array} & \text { [A], M } \\ \hline 0 & 1.00 & 0 & 1.00 & 0 & 1.00 \\ 25 & 0.78 & 25 & 0.75 & 25 & 0.80 \\ 50 & 0.61 & 50 & 0.50 & 50 & 0.67 \\ 75 & 0.47 & 75 & 0.25 & 75 & 0.57 \\ 100 & 0.37 & 100 & 0.00 & 100 & 0.50 \\ 150 & 0.22 & & & 150 & 0.40 \\ 200 & 0.14 & & & 200 & 0.33 \\ 250 & 0.08 & & & 250 & 0.29 \\ \hline \end{array}$$ What is the approximate half-life of the first-order reaction?

Short Answer

Expert verified
The approximate half-life of the first-order reaction is 75 seconds.

Step by step solution

01

Identify Presented Data

The concentration-time data is presented in three sets (I, II, and III). All sets start with the initial concentration of \([A]\) as 1.00 M. We are interested in Set I, as it corresponds to the first-order kinetic reaction in this exercise.
02

Locate Half of Initial Concentration

Half of the initial concentration is 1.00 M / 2 = 0.50 M. In Set I, the given concentration closest to 0.5M is 0.47M. This concentration is observed at time 75 s.
03

Determine the Half-Life

As the half-life is defined by the time it takes for concentration to decrease to half of its initial value, by inspection of the data, the half-life is approximately the same as the time when [A] became approximately 0.50M. Therefore, the half-life for this reaction is about 75 s.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Chemical Kinetics
Chemical kinetics involves the study of how quickly chemical reactions occur. It provides insights into the speed of a reaction and the factors affecting this speed.
In kinetic studies, changes in the concentration of reactants and products over time are monitored to figure out the rate at which a reaction proceeds.
  • Different reactions happen at different speeds. Some are incredibly fast, like explosions, while others are slow, like rusting.
  • Understanding kinetics helps in optimizing conditions to speed up desirable reactions, such as in industrial manufacturing, or to slow down unwanted reactions, like food spoiling.
By examining the concentration-time data, as given in the table, we can determine the rate law of a reaction, which tells us how the concentrations of reactants influence the rate. It plays a crucial role in determining the half-life of reactions.
First-Order Reaction
In chemical kinetics, a first-order reaction has a rate that depends linearly on one concentration term.
In other words, the rate of reaction is directly proportional to the concentration of a single reactant.
If the concentration of the reactant decreases by half, the rate of the reaction also decreases by half.
  • The rate law for a first-order reaction is written as: \[ ext{Rate} = k[A] \] where \( k \) is the rate constant, and \([A]\) is the concentration of the reactant.
  • First-order reactions are characterized by having a constant half-life, irrespective of the initial concentration.
In the exercise, set I shows the concentration of \([ ext{A} ]\) decreasing gradually. By demonstrating that the half-life remains consistent, we can verify that the reaction is first-order.
Concentration-Time Data
Concentration-time data is crucial in kinetics as it records how the concentration of reactants changes over time.
Looking at this data helps to decide the reaction order and the reaction rate law.
For the given exercise, the data sets expose how the concentration of substance \([ ext{A} ]\) changes at certain time intervals.
  • To determine the half-life, which is the time it takes for the concentration to decrease to half its original value, we identify the time at which the concentration reaches half of its initial value.
  • In set I from the exercise, the concentration data reveals that \([ ext{A} ]\) falls from 1.00M to approximately 0.50M around 75 seconds, indicating the half-life.
Examining concentration-time data not only helps in calculating half-lives but also in comprehending the overall mechanism of the reaction.

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Most popular questions from this chapter

What are the similarities and differences between the catalytic activity of platinum metal and of an enzyme?

If the plot of the reactant concentration versus time is nonlinear, but the concentration drops by \(50 \%\) every 10 seconds, then the order of the reaction is (a) zero order; (b) first order; (c) second order; (d) third order.

The decomposition of \(\mathrm{HI}(\mathrm{g})\) at \(700 \mathrm{K}\) is followed for \(400 \mathrm{s},\) yielding the following data: at \(t=0,[\mathrm{HI}]=\) \(1.00 \mathrm{M} ;\) at \(t=100 \mathrm{s},[\mathrm{HI}]=0.90 \mathrm{M} ;\) at \(t=200 \mathrm{s}, [\mathrm{HI}]=0.81 \mathrm{M} ; t=300 \mathrm{s},[\mathrm{HI}]=0.74 \mathrm{M} ;\) at \(t=400 \mathrm{s}, [\mathrm{HI}]=0.68 \mathrm{M} .\) What are the reaction order and the rate constant for the reaction: $$\mathrm{HI}(\mathrm{g}) \longrightarrow \frac{1}{2} \mathrm{H}_{2}(\mathrm{g})+\frac{1}{2} \mathrm{I}_{2}(\mathrm{g}) ?$$ Write the rate law for the reaction at 700 K.

One example of a zero-order reaction is the decomposition of ammonia on a hot platinum wire, \(2 \mathrm{NH}_{3}(\mathrm{g}) \longrightarrow \mathrm{N}_{2}(\mathrm{g})+3 \mathrm{H}_{2}(\mathrm{g}) .\) If the concentration of ammonia is doubled, the rate of the reaction will (a) be zero; (b) double; (c) remain the same; (d) exponentially increase.

We have seen that the unit of \(k\) depends on the overall order of a reaction. Derive a general expression for the units of \(k\) for a reaction of any overall order, based on the order of the reaction (o) and the units of concentration (M) and time (s).

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