Problem 11 Match each of the following spec... [FREE SOLUTION]

Chapter 11: Problem 11

Match each of the following species with one of these hybridization schemes: \(s p, s p^{2}, s p^{3}, s p^{3} d, s p^{3} d^{2} .\) (a) \(\mathrm{PF}_{6}^{-}\) (b) \(\operatorname{COS} ;\) (c) \(\operatorname{SiCl}_{4} ;\) (d) \(\mathrm{NO}_{3}^{-}\);(e) AsF \(_{5}\)

Short Answer

Expert verified

The hybridizations for the given species are - (a) \(PF_{6}^{-}\) is \(sp^{3}d^{2}\), (b) \(COS\) is \(sp\), (c) \(SiCl_{4}\) is \(sp^{3}\), (d) \(NO_{3}^{-}\) is \(sp^{2}\), (e) \(AsF_{5}\) is \(sp^{3}d\).

Step by step solution

PF6-

Look at the central atom (P). The number of atoms bonded to Phosphorus is 6 and there are no lone pairs. This implies an octahedral shape, leading to hybridization of \(sp^{3}d^{2}\).

COS

In \(COS\), C is the central atom. It is bonded to two other atoms and there are no lone pairs. This indicates a straight-line structure with bond angles of 180掳. This implies \(sp\) hybridization.

SiCl4

For \(SiCl_{4}\), the central atom is Si. The number of atoms Si is bonded to is 4 and there are no lone pairs. This corresponds to a Tetrahedral shape and hence the hybridisation is \(sp^{3}\).

NO3-

For \(NO_{3}^{-}\), the central atom is N. It is bonded to 3 atoms (oxygen atoms) and there is one resonance bond. This implies a Trigonal Planar shape and hence the hybridisation is \(sp^{2}\).

AsF5

Finally, in \(AsF_{5}\), As is the central atom. The number of atoms As is bonded to is 5 and there are no lone pairs. This implies a trigonal Bi-Pyramidal shape and hence the hybridisation is \(sp^{3}d\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Hybridization Schemes

Hybridization in chemistry is a concept explaining the structure and bonding of molecules. It is based on the combination of atomic orbitals to form new hybrid orbitals. These hybrid orbitals influence the shape and angles in a molecule. The most common types of hybridization include:

**sp hybridization**: Seen in molecules with a linear structure, involving one s and one p orbital. An example is COS, where the carbon forms two bonds, creating a straight-line layout.
**sp虏 hybridization**: Occurs in trigonal planar shapes, involving one s orbital and two p orbitals. For instance, NO鈧冣伝 shows this type with its three bonded oxygen atoms.
**sp鲁 hybridization**: Found in tetrahedral molecules, using one s and three p orbitals. An example is SiCl鈧� with four chlorine atoms symmetrically bonded.
**sp鲁d hybridization**: Related to trigonal bipyramidal structures with one s, three p, and one d orbital, as seen in AsF鈧� where five fluoro atoms bond to arsenic.
**sp鲁d虏 hybridization**: Present in octahedral shapes, involving one s, three p, and two d orbitals. PF鈧嗏伝 exemplifies this with its six fluorine atoms.

Understanding hybridization helps predict and rationalize how molecules interact and behave in different chemical environments.

VSEPR Theory

The Valence Shell Electron Pair Repulsion (VSEPR) theory is a model used to predict the geometry of individual molecules. This theory is centered on the idea that electron pairs in the valence shell of an atom will arrange themselves to minimize repulsion. This creates distinct molecular shapes. Some characteristics include:

**Linear Geometry**: Related to sp hybridization, with bond angles of 180掳, as seen in COS.
**Trigonal Planar Geometry**: Correlates with sp虏 hybridization, featuring bond angles close to 120掳, evident in NO鈧冣伝.
**Tetrahedral Geometry**: Associated with sp鲁 hybridization, having bond angles of 109.5掳, like SiCl鈧�.
**Trigonal Bipyramidal Geometry**: Matches sp鲁d hybridization, with varied bond angles (90掳 and 120掳), visible in AsF鈧�.
**Octahedral Geometry**: Connects to sp鲁d虏 hybridization, marked by consistent 90掳 angles, as PF鈧嗏伝 demonstrates.

VSEPR theory provides insight into the three-dimensional arrangement of atoms, helping to predict the molecular geometry, which directly influences chemical behavior.

Molecular Geometry

Molecular geometry refers to the three-dimensional arrangement of atoms within a molecule. It is closely linked to both hybridization and VSEPR theory. By understanding molecular geometry, we can infer many physical and chemical properties of the molecule, such as polarity and reactivity. Here are some common geometries with examples:

**Linear Geometry**: In molecules like COS, atoms lie in a single straight line, suggesting non-polar characteristics when the surrounding atoms are identical.
**Trigonal Planar Geometry**: In NO鈧冣伝, the atoms form a flat, triangle-like shape, allowing for resonance and stability.
**Tetrahedral Geometry**: In SiCl鈧�, the molecules have a symmetrical arrangement, leading to a non-polar molecule due to equal distribution of charge.
**Trigonal Bipyramidal Geometry**: Seen in AsF鈧�, this arrangement allows for flexibility in bonding angles and can create polar molecules depending on the surrounding atoms.
**Octahedral Geometry**: As displayed in PF鈧嗏伝, the atoms are symmetrically dispersed around the central atom, fostering stability and equal bond distribution.

Molecular geometry plays a crucial role in determining the function of the molecule in biological, industrial, and scientific contexts.

Chemical Bonding

Chemical bonding is a fundamental concept in chemistry that describes the attractions between atoms that lead to the formation of molecules, and it comes in various types. Two of the most significant include:

**Covalent Bonding**: Involves the sharing of electron pairs between atoms. For example, in the molecules discussed, many involve covalent bonds, where the electrons are shared to achieve stability.
**Ionic Bonding**: Involves transfer of electrons from one atom to another, leading to attraction between oppositely charged ions. While our examples mainly focus on covalent structures, ionic bonds are prevalent in compounds like salts.

Each type of bonding is guided by the principles of achieving a full valence shell and thus a lower energy state. Recognizing the type of bonding and structure helps in predicting the properties and interactions of a molecule. Understanding chemical bonding aids in deducing how molecules will react and interact under different conditions.

91影视

Match each of the following species with one of these hybridization schemes: \(s p, s p^{2}, s p^{3}, s p^{3} d, s p^{3} d^{2} .\) (a) \(\mathrm{PF}_{6}^{-}\) (b) \(\operatorname{COS} ;\) (c) \(\operatorname{SiCl}_{4} ;\) (d) \(\mathrm{NO}_{3}^{-}\);(e) AsF \(_{5}\)

Short Answer

Step by step solution

PF6-

COS

SiCl4

NO3-

AsF5

Key Concepts

Hybridization Schemes

VSEPR Theory

Molecular Geometry

Chemical Bonding

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