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A class of 84 students had a final grade distribution of 18\(\%\) A's, 25\(\%\) B's, 32\(\%\) C's, 13\(\%\) D's, 12\(\%\) F's. How many students received each grade?

Short Answer

Expert verified
In the class of 84 students: 15 students received A's, 21 students received B's, 27 students received C's, 11 students received D's, and 10 students received F's.

Step by step solution

01

Compute number of students received A's

18\(\%\) of 84 is determined by multiplying \(0.18\) (18\(\%\) in decimal form) by 84. This yields \(0.18 \times 84 = 15.12\). Since the number of students cannot be a decimal, it rounds up to 15.
02

Compute number of students received B's

25\(\%\) of 84 is determined by multiplying \(0.25\) (25\(\%\) in decimal form) by 84. This yields \(0.25 \times 84 = 21\).
03

Compute number of students received C's

32\(\%\) of 84 is determined by multiplying \(0.32\) (32\(\%\) in decimal form) by 84. This yields \(0.32 \times 84 = 26.88\). Since the number of students cannot be a decimal, it rounds up to 27.
04

Compute number of students received D's

13\(\%\) of 84 is determined by multiplying \(0.13\) (13\(\%\) in decimal form) by 84. This yields \(0.13 \times 84 = 10.92\). Since the number of students cannot be a decimal, it rounds up to 11.
05

Compute number of students received F's

12\(\%\) of 84 is determined by multiplying \(0.12\) (12\(\%\) in decimal form) by 84. This yields \(0.12 \times 84 = 10.08\). Since the number of students cannot be a decimal, it rounds up to 10.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Grade Distribution
Understanding grade distribution is crucial when analyzing how students have performed in a class. In this context, distribution refers to how grades are spread across different categories, such as A's, B's, C's, etc. Each percentage given in the distribution represents a part of the class that's achieved a specific grade.

To calculate the number of students that fall into each grade category, you multiply the total number of students by the percentage in decimal form for that category. For example, to find out how many students received A's, you would calculate 18% of 84, which is done by converting the percentage to a decimal (0.18) and multiplying it by 84. This calculation helps schools and educators understand the overall performance of a class and make decisions based on the data.

Accurate grade distribution insights can guide improvements in teaching methods and curriculum adjustments to ensure better student outcomes in the future.
Rounded Numbers
Rounding numbers is a fundamental concept in mathematics that you will encounter across various contexts, including calculating grades. In situations where calculations might result in decimals, and you need a whole number (since you can't have a fraction of a student), rounding becomes necessary.

In this exercise, after calculating the number of students for each grade where decimals are involved, you need to round them. The common rule for rounding is: if the decimal part is 0.5 or higher, round up to the next whole number; if it's less than 0.5, round down. For example, 15.12 students for A's is rounded to 15 because the decimal is less than 0.5.

Rounding helps present data in a more understandable and practical format, especially in situations where precision isn’t critical for small ranged numbers like school grades.
Student Grades
Student grades are numerical or letter symbols representing a student's academic performance. Knowing how to calculate the number of students that fall into each grade category, as seen in this exercise, helps track and understand student achievement levels.

Grades can directly impact a student's future opportunities, including college admissions and job prospects. Therefore, accurately distributing and rounding numbers when calculating grades can have significant implications.

For educators, detailed knowledge about student grades across different levels can assist in customizing teaching strategies and focus areas to enhance learning experiences. Meaningful analysis of grades and distribution can guide schools in policy making and curriculum design, ultimately improving educational outcomes.

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Most popular questions from this chapter

Express the result of each of the following calculations in exponential form and with the appropriate number of significant figures. (a) \(\left(4.65 \times 10^{4}\right) \times\left(2.95 \times 10^{-2}\right) \times\left(6.663 \times 10^{-3}\right) \times 8.2=\) (b) \(\frac{1912 \times\left(0.0077 \times 10^{4}\right) \times\left(3.12 \times 10^{-3}\right)}{\left(4.18 \times 10^{-4}\right)^{3}}=\) {c} \(\left(3.46 \times 10^{3}\right) \times 0.087 \times 15.26 \times 1.0023=\) (d) \(\frac{\left(4.505 \times 10^{-2}\right)^{2} \times 1.080 \times 1545.9}{0.03203 \times 10^{3}}=\) (e) \(\frac{\left(-3.61 \times 10^{-4}\right)+\sqrt{\left(3.61 \times 10^{-4}\right)^{2}+4(1.00)\left(1.9 \times 10^{-5}\right)}}{2 \times(1.00)}\) [Hint: The significant figure rule for the extraction of a root is the same as for multiplication.]

To determine the volume of an irregularly shaped glass vessel, the vessel is weighed empty \((121.3 \mathrm{g})\) and when filled with carbon tetrachloride (283.2 g). What is the volume capacity of the vessel, in milliliters, given that the density of carbon tetrachloride is \(1.59 \mathrm{g} / \mathrm{mL} ?\)

Without doing detailed calculations, explain which of the following objects contains the greatest mass of the element iron. (a) \(\mathrm{A} 1.00 \mathrm{kg}\) pile of pure iron filings. (b) A cube of wrought iron, \(5.0 \mathrm{cm}\) on edge. Wrought iron contains \(98.5 \%\) iron by mass and has a density of \(7.7 \mathrm{g} / \mathrm{cm}^{3}\). (c) A square sheet of stainless steel \(0.30 \mathrm{m}\) on edge and \(1.0 \mathrm{mm}\) thick. The stainless steel is an alloy (mixture) containing iron, together with \(18 \%\) chromium, \(8\%\) nickel, and 0.18\% carbon by mass. Its density is \(7.7 \mathrm{g} / \mathrm{cm}^{3}\). (d) \(10.0 \mathrm{L}\) of a solution characterized as follows: \(d=1.295 \mathrm{g} / \mathrm{mL} .\) This solution is \(70.0 \%\) water and \(30.0 \%\) of a compound of iron, by mass. The iron compound consists of \(34.4 \%\) iron by mass.

A pycnometer (see Exercise 78 ) weighs 25.60 g empty and \(35.55 \mathrm{g}\) when filled with water at \(20^{\circ} \mathrm{C}\) The density of water at \(20^{\circ} \mathrm{C}\) is \(0.9982 \mathrm{g} / \mathrm{mL}\). When \(10.20 \mathrm{g}\) lead is placed in the pycnometer and the pycnometer is again filled with water at \(20^{\circ} \mathrm{C}\), the total mass is \(44.83 \mathrm{g}\). What is the density of the lead in grams per cubic centimeter?

A 2.18 L sample of butyric acid, a substance present in rancid butter, has a mass of 2088 g. What is the density of butyric acid in grams per milliliter?

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