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Write the orbital diagram for the ground state of the germanium atom. Give all orbitals.

Short Answer

Expert verified
The orbital diagram for germanium is: 1s虏, 2s虏, 2p鈦, 3s虏, 3p鈦, 4s虏, 3d鹿鈦, 4p虏.

Step by step solution

01

Determine the Atomic Number

The first step in writing the orbital diagram for germanium is to determine its atomic number. Germanium (Ge) has an atomic number of 32, which means it has 32 electrons.
02

Apply the Aufbau Principle

Electrons fill orbitals in the order of increasing energy levels. According to the Aufbau Principle, we start with the lowest energy orbital and move to higher ones as needed. The order is: 1s, 2s, 2p, 3s, 3p, 4s, 3d, 4p.
03

Fill the Orbitals in Sequence

Starting with the 1s orbital, fill each orbital with the maximum number of electrons it can hold, according to the sequence. This gives us: 1s虏 2s虏 2p鈦 3s虏 3p鈦 4s虏 3d鹿鈦 4p虏.
04

Draw the Orbital Diagram

Now, draw the orbital diagram with boxes for each sublevel. Each box represents an orbital, and arrows within the boxes represent electrons with their spin: - 1s: 鈫戔啌 - 2s: 鈫戔啌 - 2p: 鈫戔啌 鈫戔啌 鈫戔啌 - 3s: 鈫戔啌 - 3p: 鈫戔啌 鈫戔啌 鈫戔啌 - 4s: 鈫戔啌 - 3d: 鈫戔啌 鈫戔啌 鈫戔啌 鈫戔啌 鈫戔啌 - 4p: 鈫 鈫 (starting from the leftmost box)

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Exploring Germanium Atom Electron Configuration
Germanium is an element with the symbol Ge and it holds a fascinating position in the periodic table. Determining the electron configuration of the germanium atom is crucial for understanding its chemical behavior. Its atomic number is 32, meaning it carries 32 electrons, which are to be placed in different orbitals according to specific rules. The electron configuration for germanium is 1s虏 2s虏 2p鈦 3s虏 3p鈦 4s虏 3d鹿鈦 4p虏.
These notations show how electrons are spread across different energy levels and sublevels. The numbers (1, 2, 3, 4) represent the principal energy levels and the letters (s, p, d) indicate the type of orbital. The superscript numbers show the number of electrons in each orbital. Understanding this distribution helps in predicting germanium's reactivity and bonding capacity.
Understanding the Aufbau Principle
The Aufbau Principle is an essential rule in chemistry for building up the electron configurations of atoms. Translated from German, 'aufbau' means 'building up', which is exactly what this principle dictates鈥揺lectrons fill orbitals starting with the lowest energy first before moving to higher energy levels.
The typical filling order begins with 1s, followed by 2s, 2p, 3s, 3p, 4s, then moving to 3d and 4p. This sequence is derived from the relative energies of orbitals. The lower the energy of an orbital, the earlier it gets filled. The sequence helps explain why germanium, with 32 electrons, has its configuration end at 4p虏 after fulfilling the lower energy levels first.
  • Always fill from lower to higher energy.
  • One electron is filled at a time.
  • Ensure maximum number of half-filled orbitals for stability.
Defining the Atomic Number
The atomic number is a fundamental concept in chemistry representing the number of protons in the nucleus of an atom of an element. It's equally vital because it also indicates the number of electrons in a neutral atom, dictating how the electrons are arranged in the atom's orbitals. For germanium, the atomic number is 32.
This number situates germanium correctly on the periodic table and helps to derive its electron configuration. Every element has a unique atomic number, which is critical in identifying and understanding the element's properties and its placement in various chemical reactions.
Explaining Electron Filling Order
The electron filling order, guided by the Aufbau Principle, dictates how electrons are arranged in an atom's orbitals. This order is crucial because it determines the structure of the atom and explains the chemical behavior of elements.
Electrons fill orbitals in a sequence based on increasing energy levels. The filling order is not always straightforward due to variations in energy levels especially seen in transition metals and beyond.
  • Orbital sequence: 1s, 2s, 2p, 3s, 3p, 4s, 3d, 4p, etc.
  • Higher principal quantum numbers don't always mean higher energy鈥搒ublevels play a vital role.
  • Stability is achieved by maximizing unpaired electrons before pairing them.
Understanding the electron filling order helps in predicting how elements will engage in chemical reactions, making it an indispensable tool for any chemistry student.

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Most popular questions from this chapter

Consider two hypothetical elements, \(\mathrm{W}\) and \(\mathrm{Z}\). Element \(\mathrm{W}\) has an electron affinity of \(-300 \mathrm{~kJ} / \mathrm{mol}\), and element \(\mathrm{Z}\) has an electron affinity of \(-75 \mathrm{~kJ} / \mathrm{mol}\). a. If you have a \(\mathrm{W}^{-}\) ion and a \(\mathrm{Z}^{-}\) ion, from which ion would it require more energy to remove an electron? Explain your answer. b. If elements \(\mathrm{W}\) and \(\mathrm{Z}\) are in the same period of the periodic table, which atom would you expect to have the greater atomic radius? Why? C. Assuming that the elements are in the same period, which element would you expect to have the smaller first ionization energy? d. Do the valence electrons in element \(Z\) feel a greater effective nuclear charge than those in element W? Explain how you arrived at your answer.

Choose the electron configurations that are possible from among the following. Explain why the others are impossible. a. \(1 s^{2} 2 s^{1} 2 p^{6}\) b. \(1 s^{2} 2 s^{2} 2 p^{8}\) c. \(1 s^{2} 2 s^{3} 2 p^{6} 3 s^{2} 3 p^{6} 3 d^{7}\) d. \(1 s^{2} 2 s^{2} 2 p^{6} 3 s^{1} 3 d^{9}\)

Which of the following atoms, designated by their electron configurations, has the highest ionization energy? a. \([\mathrm{Ne}] 3 s^{2} 3 p^{2}\) b. \([\mathrm{Ne}] 3 s^{2} 3 p^{3}\) c. \([\mathrm{Ar}] 3 d^{10} 4 s^{2} 4 p^{3}\) d. \([\operatorname{Kr}] 4 d^{10} 5 s^{2} 5 p^{3}\) e. \([\mathrm{Xe}] 4 f^{14} 5 d^{10} 6 s^{2} 6 p^{3}\)

Consider the following orderings. I. \(\mathrm{Al}<\mathrm{Si}<\mathrm{P}<\mathrm{S}\) II. \(\mathrm{Be}<\mathrm{Mg}<\mathrm{Ca}<\mathrm{Sr}\) III. I \(<\) Br \(<\) Cl \(<\mathrm{F}\) Which of these give(s) a correct trend in atomic size? a. I only b. II only c. III only d. I and II only e. II and III only

Write the complete ground-state electron configuration of the tin atom, \(\mathrm{Sn}\), using the building-up principle.

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