/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 104 A particular microwave oven deli... [FREE SOLUTION] | 91Ó°ÊÓ

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A particular microwave oven delivers 800 watts. (A watt is a unit of power, which is the joules of energy delivered, or used, per second.) If the oven uses microwave radiation of wavelength \(12.2 \mathrm{~cm}\), how many photons of this radiation are required to heat \(1.00 \mathrm{~g}\) of water \(1.00^{\circ} \mathrm{C}\), assuming that all of the photons are absorbed?

Short Answer

Expert verified
It requires approximately \(2.56 \times 10^{24}\) photons.

Step by step solution

01

Calculate Energy Required to Heat the Water

To raise the temperature of 1.00 g of water by 1.00°C, it requires 4.18 Joules due to the specific heat capacity of water, which is 4.18 J/g°C.
02

Convert Wavelength to Frequency

The frequency \( u \) of the microwave radiation can be calculated using the speed of light equation: \( c = \lambda u \), where \( c = 3.00 \times 10^8 \text{ m/s} \) and \( \lambda = 12.2 \text{ cm} = 0.122 \text{ m} \). Thus, \( u = \frac{c}{\lambda} = \frac{3.00 \times 10^8 \text{ m/s}}{0.122 \text{ m}} = 2.46 \times 10^9 \text{ Hz} \).
03

Calculate Energy of a Single Photon

The energy of a single photon \( E \) is determined by the equation \( E = h u \), where \( h = 6.626 \times 10^{-34} \text{ J·s} \) is Planck’s constant. Substitute in the frequency from Step 2: \( E = 6.626 \times 10^{-34} \text{ J·s} \times 2.46 \times 10^9 \text{ Hz} = 1.63 \times 10^{-24} \text{ J} \).
04

Determine Number of Photons Required

Divide the total energy required by the energy of a single photon. Thus, the number of photons needed is \( \frac{4.18 \text{ J}}{1.63 \times 10^{-24} \text{ J/photon}} \approx 2.56 \times 10^{24} \) photons.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Microwave Radiation
Microwave radiation is a type of electromagnetic radiation with wavelengths ranging from one meter to one millimeter, or equivalently, with frequencies between 300 MHz (0.3 GHz) and 300 GHz.
This makes them longer than infrared rays but shorter than radio waves. Microwaves are best known for their use in microwave ovens where they are used to heat food. The microwaves cause water molecules within food to vibrate, creating thermal energy that heats the food.
In the context of the exercise, the microwave oven emits microwave radiation to heat a small amount of water.
  • This radiation is characterized by a wavelength—in this case, 12.2 cm—which is within the typical range for microwave ovens.
  • The energy delivered by this microwave oven is measured in watts. For this example, the oven delivers 800 watts, which means it provides 800 joules of energy every second.
Understanding how microwaves work helps explain how energy is transferred to food or water in this appliance.
Specific Heat Capacity
Specific heat capacity is a measure of the amount of heat necessary to change the temperature of a substance by a certain amount.
For water, the specific heat capacity is 4.18 joules per gram per degree Celsius (J/g°C). This means that to raise the temperature of 1 gram of water by 1°C, it requires 4.18 joules of energy.
  • This value is relatively high compared to other substances, which is why water is excellent for thermal regulation and storage.
  • In the exercise, this concept helps calculate the total energy needed to heat water by determining the amount of heat required to raise its temperature by a specific degree.
This calculation is crucial in determining how many photons are needed to deliver this energy, illustrating the relationship between macroscopic energy needs and microscopic photon energy calculations.
Frequency and Wavelength Conversion
Frequency and wavelength are fundamental parameters of waves that are inversely related.
They are connected by the speed of light in a vacuum ef The equation connecting them is \( c = \lambda u \), where:
  • \( c \) is the speed of light \( \approx 3.00 \times 10^8 \text{ m/s} \)
  • \( \lambda \) is the wavelength
  • \( u \) (nu) is the frequency
The exercise involves converting the wavelength of the microwave radiation to its equivalent frequency:
  • First, the wavelength is converted from centimeters to meters for consistency with the units of the speed of light.
  • Then, frequency is found by rearranging the equation to \( u = \frac{c}{\lambda} \).
  • The calculated frequency is vital for finding the energy of individual photons using another important constant, Planck's constant.
Understanding this conversion aids in creating the necessary bridge between macroscopic energy understanding and the behavior of photons.
Planck's Constant
Planck's constant \( h \) is a fundamental constant that quantifies the relationship between the frequency of a photon and its energy.
The value of Planck's constant is \( 6.626 \times 10^{-34} \text{ J}\cdot\text{s} \).
  • It serves as a bridge between the macroscopic and quantum worlds, linking quantum mechanical and classical physical properties.
  • The energy \( E \) of a photon is given by the equation \( E = h u \). This illustrates that higher frequency photons have more energy.
In the context of the exercise, Planck's constant is used to calculate the energy of a single photon at a specific microwave radiation frequency:
  • First, the frequency calculated is inserted into the equation \( E = h u \).
  • The resultant energy of a single photon can then be used to determine how many such photons are needed to provide the energy required to heat the water.
Recognizing Planck's constant's role in energy calculations is key to understanding energy quantization in quantum physics and acts as an essential component in photon energy calculations.

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Most popular questions from this chapter

The root-mean-square speed of an oxygen molecule, \(\mathrm{O}_{2}\), at \(21^{\circ} \mathrm{C}\) is \(479 \mathrm{~m} / \mathrm{s}\). Calculate the de Broglie wavelength for an \(\mathrm{O}_{2}\) molecule traveling at this speed. How does this wavelength compare with the approximate length of this molecule, which is about \(242 \mathrm{pm}\) ? (For this comparison, state the wavelength as a percentage of the molecular length).

Neutrons are used to obtain images of the hydrogen atoms in molecules. What energy must be imparted to each neutron in a neutron beam to obtain a wavelength of \(10.0 \mathrm{pm}\) ? Obtain the energy in electron volts \((\mathrm{eV})\left(1 \mathrm{eV}=1.602 \times 10^{-19} \mathrm{~J}\right)\)

The photoelectric work function of a metal is the minimum energy required to eject an electron by shining light on the metal. The work function of calcium is \(4.60 \times 10^{-19} \mathrm{~J}\). What is the longest wavelength of light (in nanometers) that can cause an electron to be ejected from calcium metal.

A hydrogen-like ion has a nucleus of charge \(+Z e\) and a single electron outside this nucleus. The energy levels of these ions are \(-Z^{2} R_{\mathrm{H}} / n^{2}\) (where \(Z=\) atomic number). Calculate the wavelength of the transition from \(n=3\) to \(n=2\) for \(\mathrm{He}^{+}\), a hydrogen-like ion. In what region of the spectrum does this emission occur?

Explain how the probe in a scanning tunneling microscope scans a sample on the surface of a metal.

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