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Magnesium metal reacts with hydrobromic acid to produce hydrogen gas and a solution of magnesium bromide. Write the molecular equation for this reaction. Then write the corresponding net ionic equation.

Short Answer

Expert verified
Molecular Equation: \( \text{Mg}(s) + 2\text{HBr}(aq) \rightarrow \text{MgBr}_2(aq) + \text{H}_2(g) \) Net Ionic Equation: \( \text{Mg}(s) + 2\text{H}^+(aq) \rightarrow \text{Mg}^{2+}(aq) + \text{H}_2(g) \)

Step by step solution

01

Identify the Reactants and Products

Magnesium (\(\text{Mg}\)) reacts with hydrobromic acid (\(\text{HBr}\)) to form hydrogen gas (\(\text{H}_2\)) and magnesium bromide (\(\text{MgBr}_2\)). These substances are identified as the reactants and products of the reaction.
02

Write the Molecular Equation

The molecular equation for the reaction is:\[\text{Mg}(s) + 2\text{HBr}(aq) \rightarrow \text{MgBr}_2(aq) + \text{H}_2(g)\]This equation shows the reactants (magnesium and hydrobromic acid) and the products (magnesium bromide and hydrogen gas) without splitting them into ions.
03

Dissociate Aqueous Compounds into Ions

Write the ionic equation, considering that \(\text{HBr}\) is a strong acid and \(\text{MgBr}_2\) is soluble in water:\[\text{Mg}(s) + 2\text{H}^+(aq) + 2\text{Br}^-(aq) \rightarrow \text{Mg}^{2+}(aq) + 2\text{Br}^-(aq) + \text{H}_2(g)\]Separate the aqueous compounds (\(\text{HBr}\) and \(\text{MgBr}_2\)) into their ionic forms.
04

Write the Net Ionic Equation

Cancel out spectator ions (ions that appear on both sides of the equation): Here, \(\text{Br}^-\) ions are spectator ions. The net ionic equation is:\[\text{Mg}(s) + 2\text{H}^+(aq) \rightarrow \text{Mg}^{2+}(aq) + \text{H}_2(g)\]This equation shows only the ions that participate in the reaction.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Molecular Equation
A molecular equation is a way to represent a chemical reaction using the chemical formulas of the reactants and products. It shows the complete formula of each compound without breaking them down into ions. This type of equation gives a clear picture of what substances are involved in the reaction. For example, in the reaction between magnesium metal and hydrobromic acid, the molecular equation is: \[\text{Mg}(s) + 2\text{HBr}(aq) \rightarrow \text{MgBr}_2(aq) + \text{H}_2(g) \] This equation tells us that magnesium (solid) reacts with hydrobromic acid in an aqueous solution to produce magnesium bromide in an aqueous solution and hydrogen gas. This kind of equation is helpful when starting to learn about reactions because it provides a straightforward look at the overall process.
Spectator Ions
In chemical reactions, especially those involving ionic compounds, not all ions present in the reaction mixture participate in the chemical change. These non-participating ions are called spectator ions because they "watch" the reaction happen but do not get involved. For our example, the ions in hydrobromic acid, which disassociates into \(\text{H}^+\) and \(\text{Br}^-\), have different roles. The \(\text{Br}^-\) ions are spectator ions. When writing the net ionic equation, we exclude the spectator ions to focus on the actual chemical change. Thus, the spectator ions remain unchanged on both sides of the equation. Recognizing these ions is important for simplifying reactions and understanding which species are actually reacting.
Aqueous Solution
An aqueous solution is a solution in which the solvent is water. This is a common state for many reactions, particularly in chemistry labs. When a compound dissolves in water, it may dissociate into ions if it is soluble. This is particularly relevant for ionic compounds and strong acids. For instance, in our exercise, hydrobromic acid (\(\text{HBr}\)) is dissolved in water, making an aqueous solution of hydrobromic acid. The term *(aq)* signifies that a substance is dissolved in water, as with \(2\text{HBr}(aq)\). Understanding solutions in this context is crucial for recognizing how substances behave and interact in water.
Dissociation in Water
Dissociation in water occurs when an ionic compound or acid dissolves in water, breaking into its constituent ions. This process is common in aqueous solutions and is essential for understanding reactions involving ionic compounds and acids. In our specific example, when hydrobromic acid (an acid) dissolves in water, it dissociates completely to form \(\text{H}^+\) and \(\text{Br}^-\) ions. Similarly, substances like magnesium bromide would dissociate into \(\text{Mg}^{2+}\) and \(\text{Br}^-\) ions when dissolved in water. Dissociation is fundamental to forming the ionic equations and is pivotal in predicting the outcome of reactions in solution. It is a key concept in physical chemistry and explains a wide range of reaction behaviors.

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Most popular questions from this chapter

A \(0.608-\mathrm{g}\) sample of fertilizer contained nitrogen as ammonium sulfate, \(\left(\mathrm{NH}_{4}\right)_{2} \mathrm{SO}_{4}\). It was analyzed for nitrogen by heating with sodium hydroxide. \(\left(\mathrm{NH}_{4}\right)_{2} \mathrm{SO}_{4}(s)+2 \mathrm{NaOH}(a q) \longrightarrow\) $$ \mathrm{Na}_{2} \mathrm{SO}_{4}(a q)+2 \mathrm{H}_{2} \mathrm{O}(l)+2 \mathrm{NH}_{3}(g) $$ The ammonia was collected in \(46.3 \mathrm{~mL}\) of \(0.213 \mathrm{M} \mathrm{HCl}\) (hydrochloric acid), with which it reacted. $$ \mathrm{NH}_{3}(g)+\mathrm{HCl}(a q) \longrightarrow \mathrm{NH}_{4} \mathrm{Cl}(a q) $$ This solution was titrated for excess hydrochloric acid with \(44.3 \mathrm{~mL}\) of \(0.128 \mathrm{M} \mathrm{NaOH}\). $$ \mathrm{NaOH}(a q)+\mathrm{HCl}(a q) \longrightarrow \mathrm{NaCl}(a q)+\mathrm{H}_{2} \mathrm{O}(l) $$ What is the percentage of nitrogen in the fertilizer?

Classify each of the following reactions as a combination reaction, decomposition reaction, displacement reaction, or combustion reaction. a. When they are heated, ammonium dichromate crystals, \(\left(\mathrm{NH}_{4}\right)_{2} \mathrm{Cr}_{2} \mathrm{O}_{7}\), decompose to give nitrogen, water vapor, and solid chromium(III) oxide, \(\mathrm{Cr}_{2} \mathrm{O}_{3}\). b. When aqueous ammonium nitrite, \(\mathrm{NH}_{4} \mathrm{NO}_{2}\), is heated, it gives nitrogen and water vapor. C. When gaseous ammonia, \(\mathrm{NH}_{3}\), reacts with hydrogen chloride gas, HCl, fine crystals of ammonium chloride, \(\mathrm{NH}_{4} \mathrm{Cl}\), are formed. d. Aluminum added to an aqueous solution of sulfuric acid, \(\mathrm{H}_{2} \mathrm{SO}_{4}\), forms a solution of aluminum sulfate, \(\mathrm{Al}_{2}\left(\mathrm{SO}_{4}\right)_{3} .\) Hydrogen gas is released.

What volume of \(0.250 \mathrm{M} \mathrm{HNO}_{3}\) (nitric acid) reacts with \(44.8 \mathrm{~mL}\) of \(0.150 \mathrm{M} \mathrm{Na}_{2} \mathrm{CO}_{3}\) (sodium carbonate) in the following reaction? $$ 2 \mathrm{HNO}_{3}(a q)+\mathrm{Na}_{2} \mathrm{CO}_{3}(a q) \longrightarrow{2 \mathrm{NaNO}_{3}(a q)+\mathrm{H}_{2} \mathrm{O}(l)+\mathrm{CO}_{2}(g)} $$

Three \(1.0-\mathrm{g}\) samples of \(\mathrm{PbCl}_{2}, \mathrm{KCl}\), and \(\mathrm{CaCl}_{2}\) are placed in separate \(500-\mathrm{mL}\) beakers. In each case, enough \(25^{\circ} \mathrm{C}\) water is added to bring the total volume of the mixture to \(250 \mathrm{~mL}\). Each of the mixtures is then stirred for five minutes. Which of the mixtures will have the highest concentration of chloride (Cl \(^{-}\) ) ion?

An antacid tablet contains sodium hydrogen carbonate, \(\mathrm{NaHCO}_{3}\), and inert ingredients. A \(0.500-\mathrm{g}\) sample of powdered tablet was mixed with \(50.0 \mathrm{~mL}\) of \(0.190 \mathrm{M} \mathrm{HCl}\) (hydrochloric acid). The mixture was allowed to stand until it reacted. $$ \mathrm{NaHCO}_{3}(s)+\mathrm{HCl}(a q) \longrightarrow \mathrm{NaCl}(a q)+\mathrm{H}_{2} \mathrm{O}(l)+\mathrm{CO}_{2}(g) $$ The excess hydrochloric acid was titrated with \(47.1 \mathrm{~mL}\) of \(0.128\) \(M \mathrm{NaOH}\) (sodium hydroxide). $$ \mathrm{HCl}(a q)+\mathrm{NaOH}(a q) \longrightarrow \mathrm{NaCl}(a q)+\mathrm{H}_{2} \mathrm{O}(l) $$ What is the percentage of sodium hydrogen carbonate in the antacid?

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