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Obtain the oxidation number for the element noted in each of the following. a. Cr in \(\mathrm{CrO}_{3}\) b. \(\mathrm{Hg}\) in \(\mathrm{Hg}_{2} \mathrm{Cl}_{2}\) c. Ga in \(\mathrm{Ga}(\mathrm{OH})_{3}\) d. \(\mathrm{P}\) in \(\mathrm{Na}_{3} \mathrm{PO}_{4}\)

Short Answer

Expert verified
a. +6 b. +1 c. +3 d. +5

Step by step solution

01

Assign Oxidation States in CrO3

In \( \text{CrO}_3 \), oxygen has an oxidation number of \(-2\). With three oxygen atoms, the total oxidation contribution is \(-6\). Assign \( x \) as the oxidation number for chromium (Cr). Thus, the equation is:\[ x + 3(-2) = 0 \]Solving for \( x \), we get:\[ x - 6 = 0 \]\[ x = +6 \]
02

Assign Oxidation States in Hg2Cl2

In \( \text{Hg}_2\text{Cl}_2 \), each chlorine (Cl) atom has an oxidation number of \(-1\), thus for two chlorine atoms, the total contribution is \(-2\). Let \( x \) be the oxidation number for each mercury (Hg) atom. Since there are two Hg atoms, the equation is:\[ 2x + 2(-1) = 0 \]Solving for \( x \), we get:\[ 2x - 2 = 0 \]\[ 2x = 2 \]\[ x = +1 \]
03

Assign Oxidation States in Ga(OH)3

In \( \text{Ga(OH)}_3 \), the hydroxide (OH) ion has a charge of \(-1\). With three hydroxide ions, the total contribution is \(-3\). Assign \( x \) as the oxidation number for gallium (Ga). Thus, the equation is:\[ x + 3(-1) = 0 \]Solving for \( x \), we get:\[ x - 3 = 0 \]\[ x = +3 \]
04

Assign Oxidation States in Na3PO4

In \( \text{Na}_3\text{PO}_4 \), sodium (Na) has an oxidation number of \(+1\). With three sodium atoms, the total contribution is \(+3\). Oxygen has an oxidation number of \(-2\), and with four oxygen atoms, the total contribution is \(-8\). Assign \( x \) as the oxidation number for phosphorus (P). Thus, the equation is:\[ 3(+1) + x + 4(-2) = 0 \]Solving for \( x \), we get:\[ 3 + x - 8 = 0 \]\[ x - 5 = 0 \]\[ x = +5 \]

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Redox Reactions
Redox reactions involve the transfer of electrons between substances. In these reactions, one reactant loses electrons and is oxidized, while the other gains electrons and is reduced.
The key to understanding redox reactions is recognizing the change in oxidation numbers of elements in the reaction. An increase in oxidation number means oxidation, and a decrease means reduction. A classic example of a redox reaction is the reaction of hydrogen with oxygen to form water. In this reaction, hydrogen is oxidized as it loses electrons and oxygen is reduced as it gains electrons. To determine if a redox reaction has occurred, look for:
  • Changes in oxidation numbers
  • Transfer of electrons
  • Presence of an oxidizing agent (substance being reduced) and a reducing agent (substance being oxidized)
Redox reactions are central to many processes, including metabolism and energy production in living organisms, as well as in industrial applications such as the extraction of metals.
Chemical Equations
Chemical equations are symbolic representations of chemical reactions. They show the reactants that enter the reaction and the products that are formed.
Balancing these equations ensures that the law of conservation of mass is maintained, meaning that the number of each type of atom is the same on both sides of the equation. An important aspect of understanding chemical equations is knowing how to assign oxidation numbers and identify redox reactions. Identifying the changes in oxidation numbers helps to not only balance the equation but also to understand the underlying process occurring during the reaction. While balancing a chemical equation, keep in mind:
  • Write down the unbalanced equation.
  • Count the number of atoms of each element in reactants and products.
  • Use coefficients to balance elements one at a time.
  • Check to make sure that all atoms and charges are balanced.
By mastering these steps, students can effectively balance chemical reactions and gain insights into the chemical changes occurring.
Valency
Valency is the combining capacity of an element. It indicates how many atoms of an element will combine with atoms of another element.
Valency is crucial for understanding different types of chemical bonds and formations of compounds. For most elements, valency is related to the number of electrons in their outer shell. Elements aim to fill or empty this outer shell to achieve a stable configuration, similar to noble gases. There are several types of valency:
  • Monovalent: An element that can form one bond, like hydrogen or chlorine.
  • Divalent: An element that can form two bonds, like oxygen or magnesium.
  • Trivalent: An element that can form three bonds, like nitrogen or aluminum.
Understanding valency helps predict how elements will interact in chemical reactions. It simplifies writing chemical formulas and helps in balancing chemical equations effectively.

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Most popular questions from this chapter

Gold has compounds containing gold(I) ion or gold(III) ion. A compound of gold and chlorine was treated with a solution of silver nitrate, \(\mathrm{AgNO}_{3}\), to convert the chloride ion in the compound to a precipitate of AgCl. A \(162.7-\mathrm{mg}\) sample of the gold compound gave \(100.3 \mathrm{mg} \mathrm{AgCl}\). a. Calculate the percentage of the chlorine in the gold compound. b. Decide whether the formula of the compound is \(\mathrm{AuCl}\) or \(\mathrm{AuCl}_{3}\)

A \(0.608-\mathrm{g}\) sample of fertilizer contained nitrogen as ammonium sulfate, \(\left(\mathrm{NH}_{4}\right)_{2} \mathrm{SO}_{4}\). It was analyzed for nitrogen by heating with sodium hydroxide. \(\left(\mathrm{NH}_{4}\right)_{2} \mathrm{SO}_{4}(s)+2 \mathrm{NaOH}(a q) \longrightarrow\) $$ \mathrm{Na}_{2} \mathrm{SO}_{4}(a q)+2 \mathrm{H}_{2} \mathrm{O}(l)+2 \mathrm{NH}_{3}(g) $$ The ammonia was collected in \(46.3 \mathrm{~mL}\) of \(0.213 \mathrm{M} \mathrm{HCl}\) (hydrochloric acid), with which it reacted. $$ \mathrm{NH}_{3}(g)+\mathrm{HCl}(a q) \longrightarrow \mathrm{NH}_{4} \mathrm{Cl}(a q) $$ This solution was titrated for excess hydrochloric acid with \(44.3 \mathrm{~mL}\) of \(0.128 \mathrm{M} \mathrm{NaOH}\). $$ \mathrm{NaOH}(a q)+\mathrm{HCl}(a q) \longrightarrow \mathrm{NaCl}(a q)+\mathrm{H}_{2} \mathrm{O}(l) $$ What is the percentage of nitrogen in the fertilizer?

If \(45.1 \mathrm{~mL}\) of a solution containing \(8.30 \mathrm{~g}\) of silver nitrate is added to \(30.6 \mathrm{~mL}\) of \(0.511 M\) sodium carbonate solution, calculate the molarity of silver ion in the resulting solution. (Assume volumes are additive.)

A chemist wants to prepare \(0.50 M\) HCl. Commercial hydrochloric acid is \(12.4 M\). How many milliliters of the commercial acid does the chemist require to make up \(1.50 \mathrm{~L}\) of the dilute acid?

When the following equation is balanced by the halfreaction method using the smallest set of whole-number stoichiometric coefficients possible, how many electrons are canceled when the two half-reactions are added together? $$ \mathrm{K}(s)+\mathrm{N}_{2}(g) \Rightarrow \mathrm{K}_{3} \mathrm{~N}(s) $$

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