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Using solubility rules, predict the solubility in water of the following ionic compounds. a. \(\mathrm{PbS}\) b. \(\mathrm{AgNO}_{3}\) c. \(\mathrm{Na}_{2} \mathrm{CO}_{3}\) d. \(\mathrm{CaI}_{2}\)

Short Answer

Expert verified
PbS is insoluble; AgNO鈧, Na鈧侰O鈧, and CaI鈧 are soluble in water.

Step by step solution

01

Understand Solubility Rules

Solubility rules help predict whether a compound will dissolve in water. Generally, nitrates (NO鈧冣伝) are soluble, most salts of sodium (Na鈦), potassium (K鈦), and ammonium (NH鈧勨伜) are soluble, while sulfides (S虏鈦) and carbonates (CO鈧兟测伝) are mostly insoluble except when paired with alkali metals or ammonium. Chlorides, bromides, and iodides are usually soluble except for those of silver (Ag鈦), lead (Pb虏鈦), and mercury (Hg虏鈦).
02

Analyze PbS

Lead sulfide (PbS) is a sulfide. According to solubility rules, most sulfides are insoluble except those of alkali and alkaline earth metals and ammonium ions. Since Pb is a transition metal, PbS is insoluble in water.
03

Analyze AgNO鈧

Silver nitrate (AgNO鈧) includes the nitrate ion. The solubility rule states that all nitrates are soluble in water, thus AgNO鈧 is soluble in water.
04

Analyze Na鈧侰O鈧

Sodium carbonate (Na鈧侰O鈧) contains sodium. According to solubility rules, salts containing alkali metals like sodium (Na鈦) are soluble. Therefore, Na鈧侰O鈧 is soluble in water.
05

Analyze CaI鈧

Calcium iodide (CaI鈧) is an iodide. The solubility rules state that iodides are generally soluble except those of lead, silver, and mercury. Since Ca is not an exception, CaI鈧 is soluble in water.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Ionic Compounds
Ionic compounds form when positive and negative ions attract each other to create a solid. These compounds are made up of metal and non-metal ions. For example, in the compound sodium chloride (NaCl), sodium (Na) is a positive ion, and chloride (Cl) is a negative ion. This ionic attraction between oppositely charged ions creates the stable compound NaCl.

When dissolved in water, ionic compounds dissociate into their individual ions. This dissociation process is crucial for understanding their solubility, as it affects how the compound behaves in solution. Some common properties of ionic compounds include:
  • High melting and boiling points due to strong electrostatic forces between ions.
  • Generally soluble in water because water molecules can surround and stabilize the ions.
  • Conduct electricity when dissolved in water or melted, as the free-moving ions carry an electric charge.
Understanding ionic compounds is essential in predicting whether they will dissolve in water.
Solubility Prediction
Solubility prediction involves using established solubility rules to determine whether an ionic compound will dissolve in water. These rules are based on general trends and observations in chemistry. By knowing what materials commonly dissolve, the prediction process becomes straightforward, leading to accurate conclusions.

Some key solubility rules include:
  • Nitrates (\( ext{NO}_3^-\)) are always soluble regardless of the other ion they are paired with.
  • Salts containing alkali metals like sodium (\( ext{Na}^+\)), potassium (\( ext{K}^+\)), and ammonium (\( ext{NH}_4^+\)) are soluble.
  • Most iodides, bromides, and chlorides are soluble, except when paired with silver (\( ext{Ag}^+\)), lead (\( ext{Pb}^{2+}\)), or mercury (\( ext{Hg}^+\)).
  • Carbonates (\( ext{CO}_3^{2-}\)) and sulfides (\( ext{S}^{2-}\)) are generally insoluble unless they are combined with alkali metals or ammonium.
These rules provide a framework for predicting the outcome of solubility exercises in chemistry.
Water Solubility
Water solubility refers to the ability of a compound to dissolve in water, which is a universal solvent due to its polar nature. Water molecules are polar, meaning they have a slight charge due to the unequal sharing of electrons. This allows water to interact with charged ionic substances effectively, breaking them apart into individual ions.

Water solubility depends on two main factors:
  • The nature of the solute: Ionic compounds like sodium chloride dissolve well in water because their charged ions interact favorably with water molecules.
  • The nature of the solvent: Water is polar and able to stabilize ions, making it ideal for dissolving ionic compounds.
Water's capability to dissolve substances plays a critical role in various chemical reactions and biological processes.
Chemistry Education
Chemistry education provides students with the foundational knowledge to understand and predict chemical phenomena, such as solubility. Students learn to identify different types of compounds and apply solubility rules to predict the behavior of those compounds in water. This empowers students to solve problems and conduct experiments with confidence.

Key aspects of chemistry education include:
  • Fostering a clear understanding of periodic trends, such as how atoms form compounds.
  • Teaching critical solubility rules to handle real-world chemical applications.
  • Encouraging hands-on experiments to observe chemical reactions and changes in solubility.
  • Developing analytical skills through practice and application of chemical concepts.
With these tools, students can successfully predict whether particular ionic compounds will dissolve in water, using a methodical approach to solving chemistry problems.

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Most popular questions from this chapter

A metal, \(\mathrm{M}\), was converted to the chloride, \(\mathrm{MCl}_{2} .\) Then a solution of the chloride was treated with silver nitrate to give silver chloride crystals, which were filtered from the solution. \(\mathrm{MCl}_{2}(a q)+2 \mathrm{AgNO}_{3}(a q) \longrightarrow \mathrm{M}\left(\mathrm{NO}_{3}\right)_{2}(a q)+2 \mathrm{AgCl}(s)\) If \(2.434 \mathrm{~g}\) of the metal gave \(7.964 \mathrm{~g}\) of silver chloride, what is the atomic weight of the metal? What is the metal?

A transition metal \(\mathrm{X}\) forms an oxide of formula \(\mathrm{X}_{2} \mathrm{O}_{3} .\) It is found that only \(50 \%\) of \(X\) atoms in this compound are in the \(+3\) oxidation state. The only other stable oxidation states of \(\mathrm{X}\) are \(+2\) and \(+5 .\) What percentage of \(X\) atoms are in the \(+2\) oxidation state in this compound?

Determine the volume of sulfuric acid solution needed to prepare \(37.4 \mathrm{~g}\) of aluminum sulfate, \(\mathrm{Al}_{2}\left(\mathrm{SO}_{4}\right)_{3}\), by the reaction \(2 \mathrm{Al}(s)+3 \mathrm{H}_{2} \mathrm{SO}_{4}(a q) \longrightarrow \mathrm{Al}_{2}\left(\mathrm{SO}_{4}\right)_{3}(a q)+3 \mathrm{H}_{2}(g)\) The sulfuric acid solution, whose density is \(1.104 \mathrm{~g} / \mathrm{mL}\), contains \(15.0 \% \mathrm{H}_{2} \mathrm{SO}_{4}\) by mass.

Determine the oxidation numbers of all the elements in each of the following compounds. (Hint: Look at the ions present.) a. \(\mathrm{Mn}\left(\mathrm{ClO}_{3}\right)_{2}\) b. \(\mathrm{Fe}_{2}\left(\mathrm{CrO}_{4}\right)_{3}\) c. \(\mathrm{HgCr}_{2} \mathrm{O}_{7}\) d. \(\mathrm{Co}_{3}\left(\mathrm{PO}_{4}\right)_{2}\)

An alloy of aluminum and magnesium was treated with sodium hydroxide solution, in which only aluminum reacts. \(2 \mathrm{Al}(s)+2 \mathrm{NaOH}(a q)+6 \mathrm{H}_{2} \mathrm{O}(l) \longrightarrow{2 \mathrm{NaAl}(\mathrm{OH})_{4}(a q)+3 \mathrm{H}_{2}(g)}\) If a sample of alloy weighing \(1.118\) g gave \(0.1068 \mathrm{~g}\) of hydrogen, what is the percentage of aluminum in the alloy?

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