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Iron in the form of fine wire burns in oxygen to form iron(III) oxide. $$ 4 \mathrm{Fe}(s)+3 \mathrm{O}_{2}(g) \longrightarrow 2 \mathrm{Fe}_{2} \mathrm{O}_{3}(s) $$ How many moles of \(\mathrm{O}_{2}\) are needed to produce \(3.91 \mathrm{~mol}\) \(\mathrm{Fe}_{2} \mathrm{O}_{3} ?\)

Short Answer

Expert verified
5.865 moles of \(\mathrm{O}_{2}\) are needed.

Step by step solution

01

Understand the Reaction

The chemical equation given is the balanced equation for the reaction between iron and oxygen to form iron(III) oxide. It shows that 4 moles of iron react with 3 moles of oxygen to produce 2 moles of iron(III) oxide.
02

Use Stoichiometry

According to the balanced chemical equation, 3 moles of \( \mathrm{O}_{2}\) are required to produce 2 moles of \( \mathrm{Fe}_{2} \mathrm{O}_{3}\). We will use this stoichiometric relationship to find out how many moles of \( \mathrm{O}_{2}\) are needed to produce 3.91 moles of \( \mathrm{Fe}_{2} \mathrm{O}_{3}\).
03

Set Up Proportional Equation

The relationship from the balanced equation: \( \frac{3 \text{ moles of } \mathrm{O}_{2}}{2 \text{ moles of } \mathrm{Fe}_{2} \mathrm{O}_{3}}\). Use the given amount of \( \mathrm{Fe}_{2} \mathrm{O}_{3} \): \( \frac{3 \text{ moles of } \mathrm{O}_{2}}{2} = \frac{x \text{ moles of } \mathrm{O}_{2}}{3.91}\). This equation will allow us to solve for \(x\), the moles of \( \mathrm{O}_{2} \).
04

Solve for Moles of Oxygen

Cross-multiply and solve for \(x\): \[ 3 \times 3.91 = 2x \]\[ 11.73 = 2x \]\[ x = \frac{11.73}{2} = 5.865 \]. This means 5.865 moles of \( \mathrm{O}_{2}\) are needed.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Chemical Reactions
Chemical reactions are processes in which one or more substances, known as reactants, are transformed into different substances, called products. They are described using chemical equations, which represent the reactants reacting together to form products.
In our example, iron (Fe) reacts with oxygen (\(\mathrm{O}_{2}\)) to form iron(III) oxide (\(\mathrm{Fe}_{2}\mathrm{O}_{3}\)). This reaction is energetic and results in the formation of a new substance with different properties compared to the reactants. In the equation:\[ 4 \mathrm{Fe(burning)} + 3 \mathrm{O}_{2}(g) \longrightarrow 2 \mathrm{Fe}_{2}\mathrm{O}_{3}(s) \]involves heat and light, typical of a combustion reaction.
  • Reactants: the starting materials (Iron and Oxygen).
  • Products: the substances formed (Iron(III) oxide).
  • Phase Designation: 's' for solid, 'g' for gas.
Understanding these components is essential to grasp how substances change during reactions and why reactions occur.
Mole Concept
The mole concept is a fundamental aspect of chemistry that allows chemists to count particles by weighing them. One mole of any substance contains Avogadro's number of entities, which is approximately \(6.022\times10^{23}\) molecules or atoms.
In stoichiometry, the mole ratio comes from the coefficients in a balanced chemical equation. For example, the equation \(4\mathrm{Fe} + 3\mathrm{O}_{2} \rightarrow 2 \mathrm{Fe}_{2}\mathrm{O}_{3}\) shows that 4 moles of iron react with 3 moles of \(\mathrm{O}_{2}\) to produce 2 moles of \(\mathrm{Fe}_{2}\mathrm{O}_{3}\). It illustrates how moles of different substances relate to one another in a chemical reaction.
  • One mole contains \(6.022\times10^{23}\) atoms or molecules.
  • The mole ratio from the equation helps convert between reactants and products.
  • In our problem, this ratio enables us to calculate how much oxygen is needed.
This ratio was used to find the number of moles of \(\mathrm{O}_{2}\) required to produce a given quantity of iron(III) oxide.
Balanced Chemical Equation
A balanced chemical equation is a chemical equation with equal numbers of each type of atom on both sides of the equation. This is based on the law of conservation of mass, which dictates that matter cannot be created or destroyed.
Balancing a chemical equation involves adjusting coefficients to ensure that the number of atoms for each element is the same on both the reactant and product sides of the equation. Let's revisit the equation for our exercise:\[ 4\mathrm{Fe} + 3\mathrm{O}_{2} \longrightarrow 2\mathrm{Fe}_{2}\mathrm{O}_{3} \]Here, the following steps have been taken:
  • Four iron atoms on both sides ensure the element is balanced.
  • Six oxygen atoms (in \(\mathrm{O}_{2}\) gas) match six oxygen atoms in the product (\(\mathrm{Fe}_{2}\mathrm{O}_{3}\)).
When an equation is balanced, it reflects the precise stoichiometric relationships needed to derive molar ratios necessary for solving stoichiometric calculations, thus ensuring accurate chemical predictions and outcomes.

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Most popular questions from this chapter

A 3.41-g sample of a metallic element, M, reacts completely with \(0.0158\) mol of a gas, \(\mathrm{X}_{2}\), to form \(4.52\) g MX. What are the identities of \(\mathrm{M}\) and \(\mathrm{X}\) ?

Boric acid, \(\mathrm{H}_{3} \mathrm{BO}_{3}\), is a mild antiseptic and is often used as an eyewash. A sample contains \(0.543 \mathrm{~mol} \mathrm{H}_{3} \mathrm{BO}_{3} .\) What is the mass of boric acid in the sample?

Why is the mass spectrum of a molecule much more complicated than that of an atom?

Carbon tetrachloride is a colorless liquid used in the manufacture of fluorocarbons and as an industrial solvent. How many molecules are there in \(7.58 \mathrm{mg}\) of carbon tetrachloride?

An exciting, and often loud, chemical demonstration involves the simple reaction of hydrogen gas and oxygen gas to produce water vapor: $$ 2 \mathrm{H}_{2}(g)+\mathrm{O}_{2}(g) \longrightarrow 2 \mathrm{H}_{2} \mathrm{O}(g) $$ The reaction is carried out in soap bubbles or balloons that are filled with the reactant gases. We get the reaction to proceed by igniting the bubbles or balloons. The more \(\mathrm{H}_{2} \mathrm{O}\) that is formed during the reaction, the bigger the bang. Explain the following observations. a. A bubble containing just \(\mathrm{H}_{2}\) makes a quiet "fffft" sound when ignited. b. When a bubble containing equal amounts of \(\mathrm{H}_{2}\) and \(\mathrm{O}_{2}\) is ignited, a sizable bang results. c. When a bubble containing a ratio of 2 to 1 in the amounts of \(\mathrm{H}_{2}\) and \(\mathrm{O}_{2}\) is ignited, the loudest bang results. d. When a bubble containing just \(\mathrm{O}_{2}\) is ignited, virtually no sound is made.

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