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Seawater contains \(0.0065 \%\) (by mass) of bromine. How many grams of bromine are there in \(2.50 \mathrm{~L}\) of seawater? The density of seawater is \(1.025 \mathrm{~g} / \mathrm{cm}^{3}\).

Short Answer

Expert verified
There are approximately 0.167 grams of bromine in 2.50 liters of seawater.

Step by step solution

01

Calculate the Total Mass of Seawater

First, we need to find the total mass of the seawater. Since the volume of seawater is given as \(2.50\, \text{L}\) and the density of seawater is \(1.025\, \text{g/cm}^3\), we can use the formula for density: \(\text{Density} = \frac{\text{Mass}}{\text{Volume}}\). Rearranging, the formula for mass becomes \(\text{Mass} = \text{Density} \times \text{Volume}\). Convert \(2.50\, \text{L}\) to \( \text{cm}^3\) because \(1\, \text{L} = 1000\, \text{cm}^3\). Therefore, \(2.50\, \text{L} = 2500\, \text{cm}^3\). Now calculate the mass: \(\text{Mass} = 1.025\, \text{g/cm}^3 \times 2500\, \text{cm}^3 = 2562.5\, \text{g}\).
02

Calculate the Mass of Bromine in Seawater

Now that we have the total mass of the seawater, we need to find the mass of bromine. It is given that seawater contains \(0.0065\%\) by mass of bromine, which means that in every \(100\, \text{g}\) of seawater, there are \(0.0065\, \text{g}\) of bromine. To find how much bromine is in the \(2562.5\, \text{g}\) of seawater, we use the formula: \(\text{Mass of bromine} = \text{percentage} \times \text{total mass}\). This becomes \(\frac{0.0065}{100} \times 2562.5 = 0.1665625\, \text{g}\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Density and Volume Conversion
The first step to determine the amount of bromine in seawater involves calculating the total mass of the seawater. You start by knowing the volume of seawater given in liters. In this problem, it's 2.50 liters. To work effectively with density, we need the volume in cubic centimeters. Remember, 1 liter is equivalent to 1000 cubic centimeters.
To convert 2.50 liters to cubic centimeters:
  • 2.50 liters x 1000 cm³/liter = 2500 cm³
Next, we use the formula for density. Density is defined as mass per unit volume, often written as:
\[\text{Density} = \frac{\text{Mass}}{\text{Volume}}\]If you rearrange the formula to solve for mass, it becomes:
\[\text{Mass} = \text{Density} \times \text{Volume}\]Here, the density of seawater is 1.025 g/cm³. Now, multiply the density by the volume to find the mass of the seawater:
  • Mass = 1.025 g/cm³ x 2500 cm³ = 2562.5 g
Mass Percent Calculation
Once you have figured out the total mass of the seawater, the next step is to calculate the mass of bromine contained within that seawater. The problem states that bromine comprises 0.0065% of the seawater by mass.
This kind of percentage is called 'mass percent'. It tells you how many grams of a substance, in this case bromine, are present in 100 grams of the solution or mixture.
Using mass percent is straightforward. To find how much bromine is in 2562.5 grams of seawater, apply the formula:
  • \[\text{Mass of bromine} = \left(\frac{\text{Percentage}}{100}\right) \times \text{Total mass of seawater}\]
  • \[\text{Mass of bromine} = \left(\frac{0.0065}{100}\right) \times 2562.5\]
  • This results in approximately 0.1665625 grams of bromine in the seawater.
Bromine Mass Calculation
To conclude, we calculate the mass of bromine present in the given seawater. Given that we've derived bromine's mass percentage and the total mass of seawater, you might ask: why is this calculation useful?
Although the percentage is quite small (0.0065%), it's crucial for chemical engineers and environmental scientists to precisely understand these concentrations for various applications, such as desalination or chemical extraction processes.
In practical terms, we treat bromine as any other solute in a solvent. Bromine's low concentration might make detection and calculation seem trivial, but accurate measurements ensure effective chemical management and utilization.
Take note:
  • Always keep track of unit conversions to avoid inconsistencies.
  • Double-check calculations to ensure accuracy, especially with smaller percentages.
Through these calculated steps, we can determine the specific amount of a solute, such as bromine, in a given volume of solvent, like seawater.

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