Chapter 24: Problem 72
Consider the condensation of the diamine \(\mathrm{H}_{2} \mathrm{~N}\left(\mathrm{CH}_{2}\right)_{n} \mathrm{NH}_{2}\) with sebacic acid, \((\mathrm{HOOC})\left(\mathrm{CH}_{2}\right)_{8}(\mathrm{COOH})\), to obtain the polyamide. The polyamide has the following composition: \(67.2 \% \mathrm{C}\), \(10.5 \% \mathrm{H}, 10.4 \% \mathrm{~N}\), and \(11.9 \% \mathrm{O}\). What is the value of \(n ?\)
Short Answer
Step by step solution
Identify Molecular Formula
Calculate Molar Mass of Polyamide
Establish Empirical Formula
Verify Empirical Formula
Solve for n
Rectify Calculation and Solve
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Diamine
- A smaller value of \(n\) results in shorter chain polymers that may have different physical properties.
- Conversely, a larger \(n\) will produce longer chains, potentially enhancing the strength and flexibility of the polyamide.
Sebacic Acid
- During this reaction, a molecule of water is released, hence the name "condensation" polymerization.
- This water molecule is a result of the bond formation between the acid and the amine group.
Polyamide
- The polyamide composition, in this case, involves a recurring unit that combines elements from both the diamine and sebacic acid.
- These repeated units are responsible for the material properties, including strength, flexibility, and thermal stability.