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Note whether the aqueous solution of each of the following salts will be acidic, basic, or neutral. a. \(\mathrm{Na}_{2} \mathrm{~S}\) b. \(\mathrm{Cu}\left(\mathrm{NO}_{3}\right)_{2}\) c. \(\mathrm{KClO}_{4}\) d. \(\mathrm{CH}_{3} \mathrm{NH}_{3} \mathrm{Cl}\)

Short Answer

Expert verified
a. Basic; b. Acidic; c. Neutral; d. Acidic.

Step by step solution

01

Determine the Nature of Each Ion

For each salt, identify the ions it dissociates into in water. Determine if each ion comes from a strong acid, strong base, weak acid, or weak base.
02

Analyze Sodium Sulfide, Na鈧係

Na鈧係 dissociates into 2Na鈦 and S虏鈦. The Na鈦 ion is from NaOH (a strong base), so it is neutral. The S虏鈦 ion is from H鈧係 (a weak acid), so it acts as a weak base.
03

Analyze Copper(II) Nitrate, Cu(NO鈧)鈧

Cu(NO鈧)鈧 dissociates into Cu虏鈦 and 2NO鈧冣伝 ions. The NO鈧冣伝 ion comes from HNO鈧 (a strong acid) and is neutral. The Cu虏鈦 ion is from a weak base, Cu(OH)鈧, so it acts as an acidic ion.
04

Analyze Potassium Perchlorate, KClO鈧

KClO鈧 dissociates into K鈦 and ClO鈧勨伝. The K鈦 ion is from KOH (a strong base) and is neutral. ClO鈧勨伝 is from HClO鈧 (a strong acid) and is also neutral. Therefore, the solution is neutral.
05

Analyze Methylammonium Chloride, CH鈧僋H鈧僀l

CH鈧僋H鈧僀l dissociates into CH鈧僋H鈧冣伜 and Cl鈦. The Cl鈦 ion is from HCl (a strong acid) and is neutral. The CH鈧僋H鈧冣伜 ion, however, is from CH鈧僋H鈧 (a weak base) thus acts as an acid, rendering the solution acidic.
06

Conclusion: Classify the Solutions

a. Na鈧係 is basic due to the S虏鈦 ion acting as a base. b. Cu(NO鈧)鈧 is acidic because Cu虏鈦 acts as an acid. c. KClO鈧 is neutral as both ions are neutral. d. CH鈧僋H鈧僀l is acidic because CH鈧僋H鈧冣伜 acts as an acid.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Aqueous Solutions
In chemistry, an aqueous solution is simply a solution where water is the solvent. It is represented by the notation (aq) after a chemical formula, indicating that the substance is dissolved in water. When salts are dissolved in water, they undergo a process called dissociation. This process is crucial as it influences the solution's characteristics, such as its acidity or basicity. Aqueous solutions have a great impact on chemical reactions and are often analyzed to predict behaviors and outcomes concerning acid-base reactions. By understanding how salts behave in aqueous solutions, we can determine their acid-base properties and classify them as either acidic, basic, or neutral. This is a fundamental step in predicting the nature of chemical reactions in water.
Dissociation of Ions
When salts are added to water, they dissociate, or split, into their respective ions. This dissociation process plays a key role in determining the properties of the resultant solution. For instance, when sodium sulfide (\(\mathrm{Na}_{2}\mathrm{~S}\)) is added to water, it dissociates into two sodium ions (\(\mathrm{2Na}^+\)) and one sulfide ion (\(\mathrm{S}^{2-}\)). Similarly, different salts dissociate into different ions, each contributing to the solution's overall acidity or basicity. Recognizing the source of each ion, whether it be from a weak or strong acid/base, is essential to predict how the ions will behave in the solution.
Strong Acids and Bases
Strong acids and bases dissociate completely in water, meaning all of their molecules dissociate into ions. This complete dissociation is a characteristic trait. For example, hydrochloric acid (\(\mathrm{HCl}\)) dissociates fully into hydrogen ions (\(\mathrm{H}^+\)) and chloride ions (\(\mathrm{Cl}^{-}\)). A similar behavior is seen with strong bases like sodium hydroxide (\(\mathrm{NaOH}\)), which dissociates into sodium ions (\(\mathrm{Na}^+\)) and hydroxide ions (\(\mathrm{OH}^-\)). These ions do not react further with the water, leading to a predictable effect on the solution's pH. Since strong acids and bases generate ions that do not alter the pH in water beyond their inherent roles, ions from strong acids and bases like \(\mathrm{Cl}^{-}\) from \(\mathrm{HCl}\) generally contribute to neutral solutions.
Weak Acids and Bases
Unlike strong acids and bases, weak acids and bases do not fully dissociate in water. This partial dissociation means that only a fraction of the molecules release ions. This characteristic makes weak acids and bases quite interesting in how they affect the pH of an aqueous solution. Acetic acid (\(\mathrm{CH}_3\mathrm{COOH}\)) is a common example, where only some of its molecules dissociate to form hydrogen ions (\(\mathrm{H}^+\)). Similarly, weak bases such as ammonia (\(\mathrm{NH}_3\)) partially release hydroxide ions (\(\mathrm{OH}^-\)) in the solution. These weak dissociations lead to the intriguing behavior where ions originating from salts of weak acids or bases can act as bases or acids respectively, and thus alter the pH of a solution significantly. Understanding these interactions helps in analyzing the reactivity and acidity/basicity of the resultant solutions in aqueous environments.

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Most popular questions from this chapter

Trimethylamine, \(\left(\mathrm{CH}_{3}\right)_{3} \mathrm{~N}\), is a gas with a fishy, ammonialike odor. An aqueous solution that is \(0.25 M\) trimethylamine has a pH of \(11.63\). What is \(K_{b}\) for trimethylamine?

The pH of a white vinegar solution is \(2.45 .\) This vinegar is an aqueous solution of acetic acid with a density of \(1.09 \mathrm{~g} / \mathrm{mL}\). What is the mass percentage of acetic acid in the solution?

If \(20.0 \mathrm{~mL}\) of a \(0.10 \mathrm{M} \mathrm{NaOH}\) solution is added to a \(30.0\) mL sample of a \(0.10 M\) weak acid, HA, what is the \(\mathrm{pH}\) of the resulting solution? \(\left(K_{a}=1.8 \times 10^{-5}\right.\) for HA \()\) a. \(2.87\) b. \(2.74\) c. \(4.74\) d. \(5.05\) e. \(8.73\)

Tartaric acid is a weak diprotic fruit acid with \(K_{a 1}=\) \(1.0 \times 10^{-3}\) and \(K_{a 2}=4.6 \times 10^{-5}\) a. Letting the symbol \(\mathrm{H}_{2} \mathrm{~A}\) represent tartaric acid, write the chemical equations that represent \(K_{a 1}\) and \(K_{a 2} .\) Write the chemical equation that represents \(K_{a 1} \times K_{a 2}\) b. Qualitatively describe the relative concentrations of \(\mathrm{H}_{2} \mathrm{~A}\), \(\mathrm{HA}^{-}, \mathrm{A}^{2-}\), and \(\mathrm{H}_{3} \mathrm{O}^{+}\) in a solution that is about \(0.5 \mathrm{M}\) in tartaric acid. c. Calculate the \(\mathrm{pH}\) of a \(0.0250 \mathrm{M}\) tartaric acid solution and the equilibrium concentration of \(\left[\mathrm{H}_{2} \mathrm{~A}\right]\) d. What is the \(A^{2-}\) concentration?

Write chemical equations for the acid ionizations of each of the following weak acids (express these in terms of \(\mathrm{H}_{3} \mathrm{O}^{+}\) ). a. \(\mathrm{HCO}_{2} \mathrm{H}\) (formic acid) b. HF (hydrofluoric acid) c. \(\mathrm{HN}_{3}\) (hydrazoic acid) d. HOCN (cyanic acid)

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