/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 17 Which of the following salts wou... [FREE SOLUTION] | 91影视

91影视

Log out

Learning Materials

Features

Discover

Chapter 16: Problem 17

Which of the following salts would produce the most basic aqueous solution? a. \(\mathrm{NaF}\) b. \(\mathrm{KBr}\) c. \(\mathrm{NH}_{4} \mathrm{Cl}\) d. \(\mathrm{MgCl}_{2}\) e. \(\mathrm{LiNO}_{3}\)

Short Answer

Expert verified
NaF produces the most basic aqueous solution.

Step by step solution

01

Identify the Salt's Ions

Evaluate each salt to identify the cation and anion it forms in aqueous solution. For example, NaF dissociates into Na鈦� and F鈦� ions.
02

Consider the Ion's Acid-Base Properties

Determine whether the ions can react with water to form an acidic or basic solution. Typically, the conjugate base of a weak acid forms a basic solution, as it can accept protons from water.
03

Analyze \\(\mathrm{NaF}\\)

F鈦� is the conjugate base of HF, a weak acid. Therefore, F鈦� can accept protons from water, forming OH鈦� ions and creating a basic solution.
04

Analyze \\(\mathrm{KBr}\\)

Br鈦� is the conjugate base of HBr, a strong acid, and hence, it cannot effectively accept protons from water to increase the solution's basicity.
05

Analyze \\(\mathrm{NH}_{4}\mathrm{Cl}\\)

NH鈧勨伜 is the conjugate acid of NH鈧�, a weak base. It donates protons to water, making the solution acidic rather than basic.
06

Analyze \\(\mathrm{MgCl}_{2}\\)

Cl鈦�, like Br鈦�, is the conjugate base of a strong acid (HCl) and does not increase the basicity of the solution.
07

Analyze \\(\mathrm{LiNO}_{3}\\)

NO鈧冣伝 is the conjugate base of a strong acid (HNO鈧�), meaning it does not contribute to the basicity of the solution.
08

Determine the Most Basic Solution

Since F鈦� is the only anion from a weak acid among the options, NaF will create the most basic aqueous solution due to the formation of OH鈦� ions.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91影视!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Conjugate Bases
When we talk about salts and their potential to create basic solutions, the concept of a conjugate base becomes crucial. A conjugate base is what remains after an acid loses a proton. This means that the stronger the acid, the weaker its conjugate base will be at accepting protons. The experiment of determining a basic solution involves identifying the salt that can produce an anion able to accept protons from water, leading to the formation of hydroxide ions (OH鈦�).
  • For instance, consider fluoride ion (F鈦�) from the salt NaF. F鈦� is the conjugate base of HF, a weak acid. As such, F鈦� can effectively accept a proton, allowing for the creation of a more basic solution.
  • On the other hand, bromide ion (Br鈦�) comes from HBr, a strong acid, making its conjugate base weak and not inclined to accept protons. Hence, Br鈦� contributes less to basicity.
Aqueous Solutions
Aqueous solutions are those in which a solute is dissolved in water. This concept is essential for understanding salts' behavior upon dissolving in water. When a salt dissolves, it breaks down into its constituent ions. The interaction of these ions with water determines if the solution will be acidic or basic.
  • For example, NaF when dissolved in water separates into Na鈦� and F鈦�. It is this dissociation that allows the formation of hydroxide ions, making the solution basic.
  • By contrast, MgCl鈧� dissociates into Mg虏鈦� and Cl鈦�, where Chloride (Cl鈦�) largely remains inert because it results from the dissociation of a strong acid (HCl) and doesn't form hydroxide ions.
Understanding the solubility and dissociation of salts in water is pivotal in predicting the resulting pH of the solution.
Acid-Base Properties
The acid-base properties of ions derived from dissolved salts are key to understanding whether a solution will be acidic, neutral, or basic. This involves considering the original strength of the corresponding acid or base.
  • An ion like F鈦� from a weak acid (HF) not only produces a basic environment but also illustrates how the original acid's weakness correlates with a greater basicity of its conjugate base.
  • In contrast, ions like Cl鈦� or Br鈦�, coming from strong acids, do not provide an extra source of hydroxide ions in solution and therefore, do not increase the pH.
  • NH鈧勨伜, however, behaves differently as it acts as a conjugate acid of NH鈧�, a weak base. NH鈧勨伜 donates protons, potentially making the solution more acidic rather than basic.
These properties clarify why some salts, when dissolved, lead to more basic solutions than others, emphasizing the need to examine both the original acid/base strength and the resulting ions' interaction with water.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

What is the concentration of oxalate ion, \(\mathrm{C}_{2} \mathrm{O}_{4}^{2-}\), in \(0.10 M\) oxalic acid, \(\mathrm{H}_{2} \mathrm{C}_{2} \mathrm{O}_{4} ? K_{a 1}\) is \(5.6 \times 10^{-2}\), and \(K_{a 2}\) is \(5.1 \times 10^{-5}\)

Ethanolamine, \(\mathrm{HOC}_{2} \mathrm{H}_{4} \mathrm{NH}_{2}\), is a viscous liquid with an ammonialike odor; it is used to remove hydrogen sulfide from natural gas. A \(0.15 M\) aqueous solution of ethanolamine has a pH of \(11.34\). What is \(K_{b}\) for ethanolamine?

Calculate the \(\mathrm{pH}\) of a solution obtained by mixing \(35.0 \mathrm{~mL}\) of \(0.15 M\) acetic acid with \(25.0 \mathrm{~mL}\) of \(0.10 \mathrm{M}\) sodium acetate.

A solution made up of \(1.0 \mathrm{M} \mathrm{NH}_{3}\) and \(0.50 \mathrm{M}\) \(\left(\mathrm{NH}_{4}\right)_{2} \mathrm{SO}_{4}\) has a pH of \(9.26\). a. Write the net ionic equation that represents the reaction of this solution with a strong acid. b. Write the net ionic equation that represents the reaction of this solution with a strong base. c. To \(100 . \mathrm{mL}\) of this solution, \(10.0 \mathrm{~mL}\) of \(1.00 \mathrm{M} \mathrm{HCl}\) is added. How many moles of \(\mathrm{NH}_{3}\) and \(\mathrm{NH}_{4}{ }^{+}\) are present in the reaction system before and after the addition of the HCl? What is the \(\mathrm{pH}\) of the resulting solution? d. Why did the \(\mathrm{pH}\) change only slightly upon the addition of \(\mathrm{HCl} ?\)

Write chemical equations for the acid ionizations of each of the following weak acids (express these in terms of \(\mathrm{H}_{3} \mathrm{O}^{+}\) ). a. HBrO (hypobromous acid) b. \(\mathrm{HClO}_{2}(\) chlorous acid \()\) c. \(\mathrm{HNO}_{2}\) (nitrous acid) d. HCN (hydrocyanic acid)
See all solutions

Recommended explanations on Chemistry Textbooks

Chemical Reactions

Read Explanation

Making Measurements

Read Explanation

Nuclear Chemistry

Read Explanation

Physical Chemistry

Read Explanation

Chemistry Branches

Read Explanation

Inorganic Chemistry

Read Explanation
View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.