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Explain how sodium hydroxide dissolves grease and hair from a stopped drain.

Short Answer

Expert verified
Sodium hydroxide dissolves grease via saponification and breaks down hair proteins, making them water-soluble.

Step by step solution

01

Understanding Sodium Hydroxide

Sodium hydroxide (NaOH), also known as lye or caustic soda, is a strong base. It is commonly used in cleaning products due to its ability to break down organic materials like grease and hair.
02

Chemical Reaction with Grease

When sodium hydroxide comes into contact with grease, it undergoes a chemical reaction known as saponification. This process converts the triglycerides in grease into soap and glycerol, which are soluble in water and can be washed away.
03

Chemical Reaction with Hair

Hair is composed mainly of a protein called keratin. Sodium hydroxide breaks down the keratin structure by attacking the peptide bonds in the protein, effectively dissolving the hair into smaller, soluble molecules.
04

Water Solubility Enhancement

As sodium hydroxide breaks down grease and hair, the resulting products become water-soluble. This means they can easily be flushed away with water, clearing the drain.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Saponification
Saponification is a fascinating chemical process in which fats and oils are transformed into soap and glycerol in the presence of a strong base like sodium hydroxide (NaOH). When sodium hydroxide reacts with triglycerides, which are the main components of oils and fats, it breaks them down into fatty acid salts—commonly known as soap—and glycerol. This is why sodium hydroxide is so effective in clearing a drain blocked with grease.

Here’s how it works:
  • Sodium hydroxide attacks the triglycerides in the grease.
  • The triglycerides are broken down into soap (which is soluble in water) and glycerol.
  • The conversion of greasy substances into water-soluble products means they can be easily rinsed away with water.
The process not only helps clear clogs but also explains why soap can effectively remove oily residues from surfaces during regular cleaning.
Keratin breakdown
Hair often contributes to clogged drains, and its main component is a protein called keratin. Keratin is a tough and fibrous protein that provides strength and resilience to hair, making it resistant to many chemicals. However, sodium hydroxide is capable of breaking down this protein structure.

Sodium hydroxide disintegrates keratin by attacking the peptide bonds that hold the protein's amino acids together. Once these bonds are broken, the protein breaks down into smaller, water-soluble molecules, which can then easily be flushed out with water. This makes sodium hydroxide a powerful agent for removing hair blockages from drains.

It’s important to note that while sodium hydroxide is effective, it should be used with caution, as it can also damage surfaces if not properly rinsed.
Chemical reaction
The use of sodium hydroxide in clearing drains is a perfect example of how chemical reactions can resolve everyday problems. A chemical reaction entails a transforming change where original substances rearrange their atoms to create new substances with different properties.

When sodium hydroxide is introduced to blocked drains:
  • It reacts with grease through saponification, forming soap and glycerol.
  • It breaks down hair keratin by attacking peptide bonds, turning it into water-soluble parts.
The magic here lies in the transformation of insoluble materials like grease and hair into soluble substances that water can easily wash away. The entire process highlights the practical application of chemistry in maintaining cleanliness and functionality in our households.

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Most popular questions from this chapter

Give the conjugate base to each of the following species regarded as acids. a. \(\mathrm{HPO}_{4}^{2-}\) b. \(\mathrm{H}_{2} \mathrm{~S}\) c. \(\mathrm{HNO}_{2}\) d. \(\mathrm{H}_{2} \mathrm{AsO}_{4}^{-}\)

Obtain the \(\mathrm{pH}\) corresponding to the following hydronium-ion concentrations. a. \(1.0 \times 10^{-8} M\) b. \(5.0 \times 10^{-12} M\) c. \(7.5 \times 10^{-3} M\) d. \(6.35 \times 10^{-9} M\)

For the following reactions, label each species as an acid or a base. Indicate the species that are conjugates of one another. a. \(\mathrm{HSO}_{4}^{-}+\mathrm{NH}_{3} \rightleftharpoons \mathrm{SO}_{4}^{2-}+\mathrm{NH}_{4}^{+}\) b. \(\mathrm{HPO}_{4}^{2-}+\mathrm{NH}_{4}^{+} \rightleftharpoons \mathrm{H}_{2} \mathrm{PO}_{4}^{-}+\mathrm{NH}_{3}\) c. \(\mathrm{Al}\left(\mathrm{H}_{2} \mathrm{O}\right)_{6}^{3+}+\mathrm{H}_{2} \mathrm{O} \rightleftharpoons \mathrm{Al}\left(\mathrm{H}_{2} \mathrm{O}\right)_{5} \mathrm{OH}^{2+}+\mathrm{H}_{3} \mathrm{O}^{+}\) d. \(\mathrm{SO}_{3}^{2-}+\mathrm{NH}_{4}^{+} \rightleftharpoons \mathrm{HSO}_{3}^{-}+\mathrm{NH}_{3}\)

For each of the following, write the complete chemical equation for the acid- base reaction that occurs. Describe each using Brønsted language (if appropriate) and then using Lewis language (show electron-dot formulas). a. The \(\mathrm{ClO}^{-}\) ion reacts with water. b. The reaction of \(\mathrm{NH}_{4}{ }^{+}\) and \(\mathrm{NH}_{2}^{-}\) in liquid ammonia to produce \(\mathrm{NH}_{3}\).

Ethanol, \(\mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{OH}\), can undergo self- ionization. Write the chemical equation for this self-ionization. Ex plain how you arrived at this equation. At room temperature, the ion product for this self-ionization is \(1.0 \times 10^{-20}\). What is the concentration of each ion at this temperature? Show how you arrived at these concentrations.

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