Chapter 14: Problem 82
Predict the general temperature and pressure conditions for the optimum conversion of ethylene \(\left(\mathrm{C}_{2} \mathrm{H}_{4}\right)\) to ethane \(\left(\mathrm{C}_{2} \mathrm{H}_{6}\right)\). $$ \mathrm{C}_{2} \mathrm{H}_{4}(g)+\mathrm{H}_{2}(g) \rightleftharpoons \mathrm{C}_{2} \mathrm{H}_{6}(g) ; \Delta H^{\circ}<0 $$
Short Answer
Step by step solution
Understand the Reaction
Apply Le Chatelier's Principle for Temperature
Apply Le Chatelier's Principle for Pressure
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Le Chatelier's Principle
Exothermic Reaction
- Lower Temperature: When the temperature drops, the system naturally shifts towards producing more heat to balance the change, thus favoring the forward reaction.
- Practical Application: Industrial settings often exploit this property to increase the production rate and yield by maintaining lower operational temperatures.
Pressure and Temperature Effects
- Higher Pressure: According to Le Chatelier's Principle, increasing pressure encourages the reaction to proceed towards the side with fewer gas molecules. In this case, that is the side producing ethane (\(\mathrm{C}_{2} \mathrm{H}_{6}\)), which has fewer moles than the reactants.
- Lower Temperature: Lower temperatures encourage the formation of products in exothermic reactions, as the system compensates by generating more heat.
Gas Reactions
- Volume Changes: Because gases expand with higher temperature, adjusting temperature and pressure significantly alters the behavior of the reaction at equilibrium.
- Pressure Sensitivity: In reactions involving gases, pressure changes can substantially alter the equilibrium position due to the compressible nature of gases.