/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 6 Explain why evaporation leads to... [FREE SOLUTION] | 91Ó°ÊÓ

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Explain why evaporation leads to cooling of the liquid.

Short Answer

Expert verified
Evaporation removes high-energy molecules from the liquid, reducing its temperature and causing cooling.

Step by step solution

01

Understanding Evaporation

Evaporation is a process where molecules at the surface of a liquid gain enough energy to transition into the gas phase. This occurs when these molecules absorb energy, often in the form of heat, from their surroundings.
02

Heat Absorption by Molecules

During evaporation, the most energetic molecules, those with the highest kinetic energy, absorb heat from the remaining liquid. They break free from the liquid surface, thus removing energy from the liquid.
03

Energy Depletion

As the molecules with the highest energy escape, the average kinetic energy of the remaining molecules decreases. Since temperature is a measure of average kinetic energy, the reduction in energy results in a lower temperature.
04

Cooling Effect

The decrease in temperature of the liquid is perceived as cooling. The continual loss of high-energy molecules and the consequent reduction in temperature are why evaporation cools the remaining liquid.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Cooling Effect
Evaporation leads to a cooling effect because it involves the escape of the most energetic molecules from a liquid. As these molecules transition into the gas phase, they take with them a considerable amount of energy. This process leaves less energy within the remaining liquid, resulting in a noticeable drop in temperature. This lowering of temperature is what we perceive as the cooling effect of evaporation.
During a hot day, sweat evaporating from our skin is a practical example of this phenomenon. The heat from our body provides the energy that sweat molecules need to evaporate. As they leave the skin, they carry away this heat, thus cooling us down.
Kinetic Energy
In the context of evaporation, the concept of kinetic energy is paramount. Kinetic energy refers to the energy possessed by an object due to its motion. In a liquid, not all molecules move at the same speed. Instead, they have a range of kinetic energies. Molecules with higher kinetic energy are more likely to reach the energy threshold required for evaporation.
As these high-energy molecules escape from the liquid's surface, they reduce the average kinetic energy of the remaining molecules. This is because only the molecules with sufficient kinetic energy can overcome the atmospheric pressure and intermolecular forces holding them in the liquid. Thus, the liquid cools as these molecules leave.
Temperature
Temperature is intricately linked to kinetic energy as it represents the average kinetic energy of the molecules in a substance. When evaporation occurs, and molecules with the highest kinetic energy leave the liquid, the overall average kinetic energy decreases. This decrease is reflected in a lower temperature, illustrating the direct relationship between temperature and kinetic energy.
Think about a pot of boiling water. When water evaporates, the temperature of the remaining water begins to drop as the most energetic molecules are no longer there. This concept of temperature reduction is crucial in understanding how and why certain cooling systems work.
Energy Absorption
Energy absorption is a key process in evaporation. For a molecule to transition from liquid to gas, it needs to absorb energy to overcome intermolecular attractions. The energy often comes from the surrounding environment, generally in the form of heat.
This heat provides the kinetic energy necessary for some molecules to escape the liquid. However, as the energy is absorbed by the escaping molecules, the remaining liquid loses heat, leading to cooling.
  • Heat is absorbed by surface molecules during evaporation.
  • This causes an energetic deficit in the remaining liquid.
  • The process results in a temperature drop, due to lower energy levels.
Hence, the absorption of energy by surface molecules can significantly reduce the temperature of the liquid, contributing to the cooling effect.

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Most popular questions from this chapter

Gold has cubic crystals whose unit cell has an edge length of \(407.9 \mathrm{pm}\). The density of the metal is \(19.3 \mathrm{~g} / \mathrm{cm}^{3}\). From these data and the atomic mass, calculate the number of gold atoms in a unit cell, assuming all atoms are at lattice points. What type of cubic lattice does gold have?

Predict the order of increasing vapor pressure at a given temperature for the following compounds: a. \(\mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{CH}_{2} \mathrm{CH}_{2} \mathrm{OH}\) b. \(\mathrm{CH}_{3} \mathrm{CH}_{2} \mathrm{OCH}_{2} \mathrm{CH}_{3}\) c. \(\mathrm{HOCH}_{2} \mathrm{CH}_{2} \mathrm{CH}_{2} \mathrm{OH}\) Explain why you chose this order.

Which of the following do you expect to be molecular solids? a. solid silicon tetrachloride, \(\mathrm{SiCl}_{4}\) b. lithium bromide, \(\mathrm{LiBr}\) c. cadmium, \(\mathrm{Cd}\) d. solid chlorine, \(\mathrm{Cl}_{2}\)

Consider a substance \(\mathrm{X}\) with a \(\Delta H_{\mathrm{vap}}=20.3 \mathrm{~kJ} / \mathrm{mol}\) and \(\Delta H_{\text {fius }}=9.0 \mathrm{~kJ} / \mathrm{mol}\). The melting point, freezing point, and heat capacities of both the solid and liquid \(\mathrm{X}\) are identical to those of water. a. If you place one beaker containing \(50 \mathrm{~g}\) of \(\mathrm{X}\) at \(-10^{\circ} \mathrm{C}\) and another beaker with \(50 \mathrm{~g}\) of \(\mathrm{H}_{2} \mathrm{O}\) at \(-10^{\circ} \mathrm{C}\) on a hot plate and start heating them, which material will reach the boiling point first? b. Which of the materials from part a, \(\mathrm{X}\) or \(\mathrm{H}_{2} \mathrm{O}\), would completely boil away first? c. On a piece of graph paper, draw the heating curve for \(\mathrm{H}_{2} \mathrm{O}\) and \(\mathrm{X}\). How do the heating curves reflect your answers from parts a and b?

An electric heater coil provided heat to a \(15.5\) -g sample of iodine, \(\mathrm{I}_{2}\), at the rate of \(3.48 \mathrm{~J} / \mathrm{s}\). It took \(4.54 \mathrm{~min}\) from the time the iodine began to melt until the iodine was completely melted. What is the heat of fusion per mole of iodine?

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