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Under the right conditions, hydrogen gas, \(\mathrm{H}_{2}\), can be liquefied. Which is the most important intermolecular force that is responsible for allowing hydrogen molecules to be liquefied? a. hydrogen bonding b. dipole-dipole interactions c. London (dispersion) forces d. covalent bonds e. ion-dipole forces

Short Answer

Expert verified
The most important force allowing hydrogen molecules to liquefy is London (dispersion) forces (option c).

Step by step solution

01

Identifying Intermolecular Forces

Before deciding which type of force is responsible for the liquefaction of hydrogen gas, understand that hydrogen gas (\(\mathrm{H}_2\)) is non-polar because it consists of two identical atoms.
02

Analyzing Given Options

Review each intermolecular force to check its applicability:1. **Hydrogen Bonding**: Applicable to molecules with a N-H, O-H, or F-H bond. Since \(\mathrm{H}_2\) doesn't meet these conditions, eliminate option (a).2. **Dipole-Dipole Interactions**: These occur between polar molecules, but \(\mathrm{H}_2\) is non-polar. Eliminate option (b).3. **London (Dispersion) Forces**: These are present in all molecules, especially significant in non-polar molecules like hydrogen.4. **Covalent Bonds**: These occur within molecules, not between them, thus not applicable. Eliminate option (d).5. **Ion-Dipole Forces**: Occur between an ion and a polar molecules, not possible with non-polar \(\mathrm{H}_2\). Eliminate option (e).
03

Conclusion on Intermolecular Forces

Based on the analysis, London (dispersion) forces are the only applicable forces that can act between the non-polar \(\mathrm{H}_2\) molecules, allowing them to form a liquid under certain conditions.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Hydrogen Liquefaction
Liquefied hydrogen is achieved when hydrogen gas can transition into a liquid state. This process is important in industries and science when storing and transporting hydrogen is needed. For hydrogen gas to be liquefied, extremely low temperatures are required because the molecules need to slow down significantly.
This cooling process reduces the kinetic energy of hydrogen molecules, allowing intermolecular forces to become more effective, pulling the molecules closer together to form a liquid. These conditions often require temperatures below -253°C.
In these extreme conditions, even weak intermolecular forces, like those in hydrogen gas, can overcome the natural tendency of molecules to spread out, leading to liquefaction.
London Dispersion Forces
London dispersion forces, also known simply as dispersion forces, are the weakest type of intermolecular forces. Despite being weak, they are the primary forces acting between non-polar molecules like hydrogen gas (H\(_2\)).
These forces arise due to the momentary imbalance of electron distribution within a molecule, creating a temporary dipole. Although these dipoles are transient and ever-changing, they can induce similar dipoles in adjacent molecules, resulting in an attraction between them.
This attraction, albeit weak, is crucial in the context of liquefying gases like hydrogen, where enough molecules are brought close enough to transition into the liquid phase at low temperatures.
Non-polar Molecules
Understanding non-polar molecules is key to grasping why London dispersion forces are significant for hydrogen gas. Non-polar molecules, such as H\(_2\), occur when electrons in a molecule are shared equally between atoms. There is no permanent charge separation within these molecules.
This even electron distribution means they lack a permanent dipole – unlike water molecules which exhibit strong polarity.
As a result, the forces that typically act between polar molecules, like dipole-dipole interactions or hydrogen bonding, are not present. Instead, non-polar molecules only experience London dispersion forces, making understanding these forces essential for studying molecular interactions in non-polar substances.
Chemistry Concepts
Several chemistry concepts are essential for understanding the behavior of intermolecular forces, particularly as they apply to hydrogen liquefaction.
Intermolecular forces are attractions that occur between molecules, essential for determining the physical properties of compounds, including boiling and melting points. The strength of these forces varies; hydrogen bonding is strong and affects molecules like water, whereas London dispersion forces are weaker and are present in all molecules.
In liquefying hydrogen, recognizing that H\(_2\) is a non-polar molecule is vital because it dictates that only London dispersion forces are relevant. By comprehending these fundamental chemistry principles, one can better predict and explain the behaviors of various substances under different conditions.

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Most popular questions from this chapter

a. Is it possible to add heat to a pure substance and not observe a temperature change? If so, provide examples. b. Describe, on a molecular level, what happens to the heat being added to a substance just before and during melting. Do any of these molecular changes cause a change in temperature? Part 2: Consider two pure substances with equal molar masses: substance A, having very strong intermolecular attractions, and substance \(\mathrm{B}\), having relatively weak intermolecular attractions. Draw two separate heating curves for \(0.25\) -mol samples of substance \(A\) and substance \(B\) in going from the solid to the vapor state. You decide on the freezing point and boiling point for each substance, keeping in mind the information provided in this problem. Here is some additional information for constructing the curves. In both cases, the rate at which you add heat is the same. Prior to heating, both substances are at \(-50^{\circ} \mathrm{C}\), which is below their freezing points. The heat capacities of \(\mathrm{A}\) and \(\mathrm{B}\) are very similar in all states. a. As you were heating substances \(\mathrm{A}\) and \(\mathrm{B}\), did they melt after equal quantities of heat were added to each substance? Explain how your heating curves support your answer. b. What were the boiling points you assigned to the substances? Are the boiling points the same? If not, explain how you decided to display them on your curves. C. According to your heating curves, which substance reached the boiling point first? Justify your answer. d. Is the quantity of heat added to melt substance A at its melting point the same as the quantity of heat required to convert all of substance \(\mathrm{A}\) to a gas at its boiling point? Should these quantities be equal? Explain.

Describe the structure of a nematic liquid crystal. How is it similar to a liquid? How is it similar to a crystalline solid?

Chromium forms cubic crystals whose unit cell has an edge length of \(288.5 \mathrm{pm}\). The density of the metal is \(7.20 \mathrm{~g} / \mathrm{cm}^{3}\). Use these data and the atomic mass to calculate the number of atoms in a unit cell, assuming all atoms are at lattice points. What type of cubic lattice does chromium have?

What properties of water are unusual? How does hydrogen bonding explain some of these unusual properties?

An element crystallizes with a simple cubic lattice with atoms at all the lattice points. If the radius of the atom is \(200 . \mathrm{pm}\), what is the volume of the unit cell? a. \(8.00 \times 10^{6} \mathrm{pm}^{3}\) b. \(6.40 \times 10^{7} \mathrm{pm}^{3}\) c. \(4.00 \times 10^{4} \mathrm{pm}^{3}\) d. \(1.60 \times 10^{5} \mathrm{pm}^{3}\) e. \(6.00 \times 10^{7} \mathrm{pm}^{3}\)

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