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When \(23.6 \mathrm{~g}\) of calcium chloride, \(\mathrm{CaCl}_{2}\), was dissolved in water in a calorimeter, the temperature rose from \(25.0^{\circ} \mathrm{C}\) to \(38.7^{\circ} \mathrm{C}\). If the heat capacity of the solution and the calorimeter is \(1258 \mathrm{~J} /{ }^{\circ} \mathrm{C}\), what is the enthalpy change when \(1 \mathrm{~mol}\) of cal. cium chloride dissolves in water? The solution process is $$\mathrm{CaCl}_{2}(s) \longrightarrow \mathrm{Ca}^{2+}(a q)+2 \mathrm{Cl}^{-}(a q) ; \Delta H=?$$

Short Answer

Expert verified
The enthalpy change is \( 81.03 \text{ kJ/mol} \).

Step by step solution

01

Calculate the Temperature Change

First, determine the change in temperature, denoted as \( \Delta T \). This is the final temperature minus the initial temperature of the solution.\[ \Delta T = 38.7^{\circ} \mathrm{C} - 25.0^{\circ} \mathrm{C} = 13.7^{\circ} \mathrm{C} \]
02

Calculate the Heat Transferred

Using the given heat capacity, calculate the heat absorbed by the solution using the formula \( q = C \cdot \Delta T \), where \( C \) is the total heat capacity.\[ q = 1258 \mathrm{~J}/{^{\circ} \mathrm{C}} \times 13.7^{\circ} \mathrm{C} = 17223.6 \mathrm{~J} \]
03

Determine the Moles of Calcium Chloride

Calculate the number of moles of \( \mathrm{CaCl}_2 \) using its molar mass. The molar mass of \( \mathrm{CaCl}_2 \) is \( 40.08 + 2 \times 35.45 = 110.98 \mathrm{~g/mol} \).\[ \text{Moles of } \mathrm{CaCl}_2 = \frac{23.6}{110.98} \approx 0.2125 \text{ moles} \]
04

Calculate the Enthalpy Change per Mole

Find the enthalpy change per mole by dividing the heat transferred by the number of moles of \( \mathrm{CaCl}_2 \).\[ \Delta H = \frac{17223.6 \mathrm{~J}}{0.2125 \text{ moles}} = 81032.94 \text{ J/mol} \]Convert this to kJ/mol:\[ \Delta H = 81.03 \text{ kJ/mol} \]
05

Conclusion: Report the Enthalpy Change

The enthalpy change when 1 mol of calcium chloride dissolves in water is \( \Delta H = 81.03 \text{ kJ/mol} \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Calorimetry
Calorimetry is a technique used to measure the heat absorbed or released during a chemical or physical process. This experimental method helps us understand the energy changes that accompany reactions. In the context of our exercise, a calorimeter is used to measure the heat change when calcium chloride (\( CaCl_2\)) dissolves in water.

To carry out a calorimetry experiment, you need to know a few key components:
  • The initial and final temperatures of the solution
  • The heat capacity of the calorimeter and its contents
  • Amount of substance being tested (in this case, calcium chloride)
By measuring these, you can calculate heat transfer, expressed as \( q \), using the formula:\[ q = C \cdot \Delta T \]where \( C \) is the heat capacity and \( \Delta T \) is the change in temperature.
Calcium Chloride Dissolution
Dissolution of calcium chloride is a common process studied in chemistry due to its interesting thermal effect. When calcium chloride (\( CaCl_2\)) dissolves in water, it dissociates into its ions:\[ CaCl_2(s) \rightarrow Ca^{2+}(aq) + 2Cl^{-}(aq) \]

This process is exothermic, meaning it releases heat. The exothermic nature of this reaction is evidenced by the increase in temperature observed in the calorimeter. When 23.6 grams of calcium chloride are dissolved, the temperature of the solution rises, which we measure and analyze through calorimetry to find the enthalpy change. This is an important parameter, as it indicates how much heat is exchanged with the surroundings when a mole of the compound dissolves.
Heat Transfer
Heat transfer is the movement of thermal energy from one object or substance to another. In our exercise, heat is transferred from the calcium chloride solution to the surrounding water in the calorimeter.

By calculating the change in the solution's temperature (\( \Delta T = 13.7^{\circ} \text{C}\)), and knowing the heat capacity (\( 1258 \,\text{J}/^{\circ}\text{C}\)), we can find the total heat transferred, \( q \), using:\[ q = 1258 \,\text{J}/^{\circ}\text{C} \times 13.7^{\circ}\text{C} = 17223.6 \,\text{J} \]
This value represents the total energy change due to the dissolution of calcium chloride. Understanding this heat transfer is crucial for calculating the enthalpy change, which is the focus of the experiment.
Molar Mass Determination
Molar mass is a fundamental property of a substance representing the mass of one mole of its molecules. For calcium chloride (\( CaCl_2\)), its molar mass is calculated as:
  • 40.08 g/mol for calcium
  • 35.45 g/mol for each chlorine ion
The total molar mass of calcium chloride is:\[ 40.08 + 2 \times 35.45 = 110.98 \,\text{g/mol} \]

Having this information allows us to determine how many moles of calcium chloride were dissolved in the experiment. Given 23.6 grams of calcium chloride, the number of moles is:\[ \frac{23.6 \,\text{g}}{110.98 \,\text{g/mol}} \approx 0.2125 \text{ moles} \]Understanding the molar mass is key to calculating the enthalpy change per mole, which tells us how much energy is exchanged when one mole of \( CaCl_2\) dissolves in water.

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Most popular questions from this chapter

A piece of lead of mass \(121.6 \mathrm{~g}\) was heated by an electrical coil. From the resistance of the coil, the current, and the time the current flowed, it was calculated that \(235 \mathrm{~J}\) of heat was added to the lead. The temperature of the lead rose from \(20.4^{\circ} \mathrm{C}\) to \(35.5^{\circ} \mathrm{C}\). What is the specific heat of the lead?

An iron skillet weighing \(1.63 \mathrm{~kg}\) is heated on a stove to \(178^{\circ} \mathrm{C}\). Suppose the skillet is cooled to room temperature, \(21^{\circ} \mathrm{C}\). How much heat energy (in joules) must be removed to effect this cooling? The specific heat of iron is \(0.449 \mathrm{~J} /\left(\mathrm{g} \cdot{ }^{\circ} \mathrm{C}\right)\).

A bullet weighing 235 grains is moving at a speed of \(2.52 \times 10^{3} \mathrm{ft} / \mathrm{s}\). Calculate the kinetic energy of the bullet in joules and in calories. One grain equals \(0.0648 \mathrm{~g}\).

Calcium oxide (quicklime) reacts with water to produce calcium hydroxide (slaked lime). $$\mathrm{CaO}(s)+\mathrm{H}_{2} \mathrm{O}(l) \longrightarrow \mathrm{Ca}(\mathrm{OH})_{2}(s) ; \Delta H=-65.2 \mathrm{~kJ}$$ The heat released by this reaction is sufficient to ignite paper. How much heat is released when \(24.5 \mathrm{~g}\) of calcium oxide reacts?

An industrial process for manufacturing sulfuric acid, \(\mathrm{H}_{2} \mathrm{SO}_{4}\), uses hydrogen sulfide, \(\mathrm{H}_{2} \mathrm{~S}\), from the purification of natural gas. In the first step of this process, the hydrogen sulfide is burned to obtain sulfur dioxide, \(\mathrm{SO}_{2}\). $$\begin{gathered}2 \mathrm{H}_{2} \mathrm{~S}(g)+3 \mathrm{O}_{2}(g) \longrightarrow 2 \mathrm{H}_{2} \mathrm{O}l)+2\mathrm{SO}_{2}(g) ; \\ \Delta H^{\circ}=-1124 \mathrm{~kJ}\end{gathered}$$ The density of sulfur dioxide at \(25^{\circ} \mathrm{C}\) and \(1.00 \mathrm{~atm}\) is \(2.62 \mathrm{~g} /\mathrm{L}\), and the molar heat capacity is \(30.2 \mathrm{~J} /\left(\mathrm{mol} \cdot{ }^{\circ} \mathrm{C}\right) .\) (a) How much heat would be evolved in producing \(1.00 \mathrm{~L}\) of \(\mathrm{SO}_{2}\) at \(25^{\circ} \mathrm{C}\) and \(1.00\) atm? (b) Suppose heat from this reaction is used to heat \(1.00 \mathrm{~L}\) of \(\mathrm{SO}_{2}\) from \(25^{\circ} \mathrm{C}\) and \(1.00 \mathrm{~atm}\) to \(500^{\circ} \mathrm{C}\) for its use in the next step of the process. What percentage of the heat evolved is required for this?

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