/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 25 A small car is traveling at twic... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

A small car is traveling at twice the speed of a larger car, which has twice the mass of the smaller car. Which car has the greater kinetic energy? (Or do they both have the same kinetic energy?)

Short Answer

Expert verified
The smaller car has greater kinetic energy.

Step by step solution

01

Understand the concept of kinetic energy

Kinetic energy is given by the formula \( KE = \frac{1}{2}mv^2 \), where \( m \) is the mass and \( v \) is the velocity of the object.
02

Assign variables for masses and velocities

Let the mass of the smaller car be \( m \) and the mass of the larger car be \( 2m \). Denote the velocity of the smaller car as \( v \), and since it's traveling twice as fast, the velocity of the larger car is \( \frac{v}{2} \).
03

Compute the kinetic energy of the smaller car

Using the formula, the kinetic energy of the smaller car is \( KE_{small} = \frac{1}{2}mv^2 \).
04

Compute the kinetic energy of the larger car

For the larger car, the kinetic energy is \( KE_{large} = \frac{1}{2}(2m)\left(\frac{v}{2}\right)^2 \). Simplify to get \( KE_{large} = \frac{1}{2}(2m)\frac{v^2}{4} = \frac{1}{4}mv^2 \).
05

Compare the kinetic energies

From the calculations, \( KE_{small} = \frac{1}{2}mv^2 \) and \( KE_{large} = \frac{1}{4}mv^2 \). Clearly, \( \frac{1}{2}mv^2 > \frac{1}{4}mv^2 \).
06

Conclusion: Determine which car has greater kinetic energy

Since \( KE_{small} > KE_{large} \), the smaller car has greater kinetic energy.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Mass and Velocity
When discussing kinetic energy, two main factors come into play: mass and velocity. Mass is the amount of matter in an object, usually measured in kilograms. Velocity refers to the speed of something in a particular direction and involves both magnitude and direction, unlike speed which only involves magnitude. In physics, they play a crucial role in determining how much kinetic energy an object possesses. Kinetic energy can be described as the energy of motion. The formula for kinetic energy is given as \( KE = \frac{1}{2}mv^2 \). This equation shows that kinetic energy is directly proportional to the mass of an object and the square of its velocity. This means that even a small increase in velocity will have a large effect on kinetic energy because velocity is squared in the formula. Therefore, in energy-related scenarios like our exercise, both mass and velocity are considered to understand their impact on kinetic energy.
Physics Problem Solving
Solving physics problems often involves a methodical approach to simplify complex situations. Let's break down the process used in the exercise above.
  • Identify variables: Starting with a clear understanding of what each variable represents is crucial. In our exercise, the small car's mass and velocity were defined by \( m \) and \( v \) respectively, while the larger car’s mass and velocity were consequently \( 2m \) and \( \frac{v}{2} \).
  • Use known formulas: In this situation, employing the kinetic energy formula helps navigate through the problem systematically.
  • Substitute and simplify: Replacing variables with appropriate values and simplifying any equations or expressions is a vital part.
  • Compare results: Finally, comparing the results allows you to draw conclusions about the scenario you are exploring.
Placing each step neatly in order will ensure clarity and reduce errors, making complex physics problems more manageable.
Energy Comparison
Understanding energy comparison is vital for evaluating the differences in kinetic energy when objects of different masses and velocities are in motion. In our example scenario, we had a small car moving faster and a larger car moving slower.
  • The small car, with a mass of \( m \) and velocity \( v \), results in a kinetic energy of \( \frac{1}{2}mv^2 \).
  • In contrast, the larger car, with \( 2m \) mass and \( \frac{v}{2} \) velocity, achieves \( \frac{1}{4}mv^2 \) in kinetic energy.
From this, it becomes apparent that the smaller, faster car has the greater kinetic energy. Why? Because even though the larger car has more mass, the velocity impacting its kinetic energy is being squared and results in a greater overall influence compared to mass alone. This comparison not only stresses the importance of velocity but also offers insight into how objects with differing physical attributes transfer or sustain energy.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Carbon disulfide bums in air, producing carbon dioxide and sulfur dioxide. $$\mathrm{CS}_{2}(l)+3 \mathrm{O}_{2}(\mathrm{~g}) \longrightarrow \mathrm{CO}_{2}(g)+2 \mathrm{SO}_{2}(g) ;\Delta H=-1077 \mathrm{~kJ}$$ What is \(\Delta H\) for the following equation? $$\frac{1}{2} \mathrm{CS}_{2}(l)+\frac{3}{2} \mathrm{O}_{2}(g) \longrightarrow \frac{1}{2} \mathrm{CO}_{2}(g)+\mathrm{SO}_{2}(g)$$

The process of dissolving ammonium nitrate, \(\mathrm{NH}_{4} \mathrm{NO}_{3}\), in water is an endothermic process. What is the sign of \(q ?\) If you were to add some ammonium nitrate to water in a flask, would you expect the flask to feel warm or cool?

Formic acid, \(\mathrm{HCHO}_{2}\), was first discovered in ants ( formica is Latin for "ant"). In an experiment, \(5.48 \mathrm{~g}\) of formic acid was burned at constant pressure. $$2 \mathrm{HCHO}_{2}(l)+\mathrm{O}_{2}(g) \longrightarrow 2 \mathrm{CO}_{2}(g)+2 \mathrm{H}_{2} \mathrm{O}(l)$$ If \(30.3 \mathrm{~kJ}\) of heat evolved, what is \(\Delta H\) per mole of formic acid?

A \(20.0 \mathrm{~g}\) block of iron at \(50.0^{\circ} \mathrm{C}\) and a \(20.0 \mathrm{~g}\) block of aluminum at \(45^{\circ} \mathrm{C}\) are placed in contact with each other. Assume that heat is only transferred between the two blocks. a. Draw an arrow indicating the heat flow between the blocks. b. What is the sign of \(q_{\mathrm{sys}}\) for the aluminum when the blocks first come into contact? c. What will you observe when \(q_{s y s}\) for the iron is zero? d. Estimate the temperature of the \(\mathrm{Al}\) and \(\mathrm{Fe}\) blocks when \(q_{\mathrm{sys}}\) of the iron equals \(q_{\text {sys }}\) of the aluminum.

The energy, \(E\), needed to move an object a distance \(d\) by applying a force \(F\) is \(E=F \times d\). What must be the SI unit of force if this equation is to be consistent with the SI unit of energy for \(E ?\)

See all solutions

Recommended explanations on Chemistry Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.