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Hydroquinone, used as a photographic developer, is \(65.4 \% \mathrm{C}, 5.5 \% \mathrm{H}\), and \(29.1 \% \mathrm{O}\), by mass. What is the empirical formula of hydroquinone?

Short Answer

Expert verified
The empirical formula of hydroquinone is \(\text{C}_3\text{H}_3\text{O}\).

Step by step solution

01

Convert Percentages to Grams

Assume you have 100 g of the substance, so the percentages can be directly converted to grams. This gives: 65.4 g of C, 5.5 g of H, and 29.1 g of O.
02

Calculate Moles of Each Element

Convert the masses to moles using the molar mass of each element:- For carbon: \( \frac{65.4 \, \text{g}}{12.01 \, \text{g/mol}} = 5.45 \, \text{mol} \)- For hydrogen: \( \frac{5.5 \, \text{g}}{1.008 \, \text{g/mol}} = 5.46 \, \text{mol} \)- For oxygen: \( \frac{29.1 \, \text{g}}{16.00 \, \text{g/mol}} = 1.82 \, \text{mol} \)
03

Find the Simplest Whole Number Ratio

Divide each mole value by the smallest number of moles calculated, which is 1.82 moles:- For carbon: \( \frac{5.45}{1.82} \approx 3 \)- For hydrogen: \( \frac{5.46}{1.82} \approx 3 \)- For oxygen: \( \frac{1.82}{1.82} = 1 \)
04

Write the Empirical Formula

The empirical formula is determined by the whole number ratios found in Step 3. The empirical formula of hydroquinone is \( \text{C}_3\text{H}_3\text{O} \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Percent Composition
Percent composition is an essential concept in chemistry that helps us understand how different elements contribute to a compound's overall mass.
When we speak about the percent composition of a chemical compound, we're referring to the
  • mass percentage of each individual element
  • in comparison to the entire mass of the compound itself

It's like looking at a fruit salad and determining how much of it is apples, bananas, and grapes in terms of their weight contributions.

In the context of the exercise, hydroquinone was specified as comprising 65.4% carbon, 5.5% hydrogen, and 29.1% oxygen by mass. To find the empirical formula, you can convert these percentages into grams, assuming you have a 100 g sample.
  • This conversion directly gives you the weight of each element in grams.
Afterward, you can use these figures in calculations to discover the compound's empirical formula. By doing this, you get a clearer picture of the compound's construction and relative elemental distribution.
Molecular Chemistry
Molecular chemistry dives into the study of molecules, which is a more detailed blueprint than viewing a compound simply as a mix of elements.
Each molecule is a grouping of atoms held together by chemical bonds, and understanding their ratios is fundamental in molecular chemistry.

For hydroquinone, besides recognizing the specific atoms that make it up, it's equally important to grasp how these atoms are bonded and arranged to form the entire molecule.
However, in determining its empirical formula, we focus more on the ratio of these atoms in their simplest form rather than delving into the complex structure itself.

In simpler terms, the empirical formula provides a foundational framework showing the smallest integer ratios of atoms. These ratios arise from the calculate moles for each element, as done with carbon, hydrogen, and oxygen in the exercise,
  • once converted from their respective percentages into grams,
  • then into moles using their molar masses.
This simplification assists us in forming a basic understanding of the compound without needing detailed visualization of the molecular structure.
Chemical Calculations
Chemical calculations are crucial for transforming raw numerical data into meaningful results.
They provide us the tools to move from observations into concrete steps in problem-solving.
In the case of molecules, calculating the empirical formula involves several key mathematical conversions, which include:

  • Converting mass percentages to grams
  • Turning those grams into moles using the atomic masses of each element
  • Formulating the simplest whole number ratio

These calculations are central to grasping the concept of empirical formulas, establishing ratios with precision based on real experimental data.

For instance, in the problem with hydroquinone, you take 65.4 g, 5.5 g, and 29.1 g for carbon, hydrogen, and oxygen, respectively, and use their molar masses - 12.01 g/mol for C, 1.008 g/mol for H, and 16.00 g/mol for O, to transition from mass to moles.
By aligning these molar values to the smallest calculated mole value (oxygen here with 1.82 moles), you identify and confirm the ratios needed to write the empirical formula.
This empirical formula, in turn, becomes a key descriptor of the substance, assisting chemists in identifying the compound and predicting its behaviors and reactions within various settings.

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Most popular questions from this chapter

A mixture consisting of \(12.8 \mathrm{~g}\) of calcium fluoride, \(\mathrm{CaF}_{2}\), and \(13.2 \mathrm{~g}\) of sulfuric acid, \(\mathrm{H}_{2} \mathrm{SO}_{4}\), is heated to drive off hydrogen fluoride, HF. $$ \mathrm{CaF}_{2}(s)+\mathrm{H}_{2} \mathrm{SO}_{4}(l) \longrightarrow 2 \mathrm{HF}(g)+\mathrm{CaSO}_{4}(s) $$ What is the maximum number of grams of hydrogen fluoride that can be obtained?

Calculate the percentage composition for each of the following compounds (three significant figures). a. \(\mathrm{CO}\) b. \(\mathrm{CO}_{2}\) c. \(\mathrm{NaH}_{2} \mathrm{PO}_{4}\) d. \(\mathrm{Co}\left(\mathrm{NO}_{3}\right)_{2}\)

A fertilizer is advertised as containing \(14.0 \%\) nitrogen (by mass). How much nitrogen is there in \(4.15 \mathrm{~kg}\) of fertilizer?

Copper metal reacts with nitric acid. Assume that the reaction is $$ 3 \mathrm{Cu}(s)+8 \mathrm{HNO}_{3}(a q) \longrightarrow{3 \mathrm{Cu}}\left(\mathrm{NO}_{3}\right)_{2}(a q)+2 \mathrm{NO}(g)+4 \mathrm{H}_{2} \mathrm{O}(I) $$ If \(5.92 \mathrm{~g} \mathrm{Cu}\left(\mathrm{NO}_{3}\right)_{2}\) is eventually obtained, how many grams of nitric oxide, NO, would have formed also, according to the preceding equation?

A \(1.547-\mathrm{g}\) sample of blue copper(II) sulfate pentahydrate, \(\mathrm{CuSO}_{4} \cdot 5 \mathrm{H}_{2} \mathrm{O}\), is heated carefully to drive off the water. The white crystals of \(\mathrm{CuSO}_{4}\) that are left behind have a mass of \(0.989 \mathrm{~g} .\) How many moles of \(\mathrm{H}_{2} \mathrm{O}\) were in the original sample? Show that the relative molar amounts of \(\mathrm{CuSO}_{4}\) and \(\mathrm{H}_{2} \mathrm{O}\) agree with the formula of the hydrate.

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