Chapter 23: Problem 54
Using crystal field theory, sketch the energy-level diagram for the \(d\) orbitals in an octahedral field; then fill in the electrons for the metal ion in each of the following complexes. How many unpaired electrons are there in each case? a. \(\mathrm{ZrCl}_{6}^{4-}\) b. \(\mathrm{OsCl}_{6}{ }^{2-}\) (low-spin) c. \(\mathrm{MnCl}_{6}{ }^{4-}\) (high-spin)
Short Answer
Step by step solution
Understand Crystal Field Theory
Octahedral Crystal Field Splitting
Determine the Electron Configuration of the Central Metal Ion
Fill in Electrons for \(\mathrm{ZrCl}_{6}^{4-}\)
Fill in Electrons for \(\mathrm{OsCl}_{6}^{2-}\) (Low-Spin)
Fill in Electrons for \(\mathrm{MnCl}_{6}^{4-}\) (High-Spin)
Unlock Step-by-Step Solutions & Ace Your Exams!
-
Full Textbook Solutions
Get detailed explanations and key concepts
-
Unlimited Al creation
Al flashcards, explanations, exams and more...
-
Ads-free access
To over 500 millions flashcards
-
Money-back guarantee
We refund you if you fail your exam.
Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!
Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Octahedral coordination complex
- The geometry is important for predicting how these complexes will react.
- The symmetry affects orbital interactions and dictates resultant electronic configurations.
d orbital splitting
Split of the d Orbitals
When the metal ion is subject to the electric field created by the surrounding ligands in an octahedral arrangement, its five degenerate d orbitals split into two sets:- Three lower-energy orbitals, termed t2g (comprising the dxy, dyz, and dxz orbitals).
- Two higher-energy orbitals, termed eg (comprising the dx^2-y^2 and dz^2 orbitals).