Chapter 23: Problem 38
Give the coordination number of the transition element in each of the following complexes. a. \(\left[\mathrm{Ni}\left(\mathrm{NH}_{3}\right)_{6}\right]\left(\mathrm{ClO}_{3}\right)_{2}\) b. \(\left[\mathrm{Cu}\left(\mathrm{NH}_{3}\right)_{4}\right] \mathrm{SO}_{4}\) c. \(\left[\mathrm{Cr}(\mathrm{en})_{3}\right] \mathrm{Cl}_{3}\) d. \(\mathrm{K}_{2}\left[\mathrm{Ni}(\mathrm{CN})_{4}\right]\)
Short Answer
Step by step solution
Understand Coordination Number
Determine for Complex a
Determine for Complex b
Determine for Complex c
Determine for Complex d
Unlock Step-by-Step Solutions & Ace Your Exams!
-
Full Textbook Solutions
Get detailed explanations and key concepts
-
Unlimited Al creation
Al flashcards, explanations, exams and more...
-
Ads-free access
To over 500 millions flashcards
-
Money-back guarantee
We refund you if you fail your exam.
Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!
Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Coordination Number
- For example, if a metal ion is surrounded by six ammonia molecules, its coordination number is six, because each ammonia donates one pair of electrons to the metal.
- The coordination number is not fixed and can range from 2 to 12, with 4 and 6 being the most common in these complexes.
- Understanding coordination number helps predict geometrical structure, which influences the properties and function of the complex.
Transition Metals
- They have partially filled d-orbitals, enabling them to form complex structures with various ligands.
- Transition metals can exhibit multiple oxidation states, making them versatile in chemical reactions.
- They often display beautiful colors in their compounds due to d-d electron transitions.
Ligands
- Ligands can vary in size and charge, from small molecules like water and ammonia to larger entities like ethylenediamine (\(\mathrm{en}\)).
- Ligands are classified based on the number of donor atoms: monodentate (one donor atom) and bidentate (two donor atoms), as seen in \(\left[\mathrm{Cr}(\mathrm{en})_{3}\right] \mathrm{Cl}_{3}\) where ethylenediamine acts as a bidentate ligand.
- Bidentate and polydentate ligands form chelates with the metal, resulting in more stable complexes due to the chelate effect.
Coordinate Bonding
- Coordinate bonds are formed when ligands, like ammonia or cyanide, donate a pair of electrons to a metal ion.
- These bonds are just as strong as covalent bonds and can create complex geometrical arrangements around the metal.
- This type of bonding is responsible for the formation of stable structures like \(\left[\mathrm{Cu}\left(\mathrm{NH}_{3}\right)_{4}\right] \mathrm{SO}_{4}\) and \(\mathrm{K}_{2}\left[\mathrm{Ni}(\mathrm{CN})_{4}\right]\).