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Do you expect an aqueous solution of sodium hypochlorite to be acidic, neutral, or basic? What about an aqueous solution of sodium perchlorate?

Short Answer

Expert verified
NaOCl solution is basic; NaClO鈧 solution is neutral.

Step by step solution

01

Understanding Sodium Hypochlorite (NaOCl) in Water

Sodium hypochlorite dissociates in water to form sodium ions (Na鈦) and hypochlorite ions (OCl鈦). The sodium ion does not affect the pH, as it is a spectator ion, but the hypochlorite ion can hydrolyze water, forming hypochlorous acid (HOCl) and hydroxide ions (OH鈦). The reaction is:\[\text{OCl}^- + \text{H}_2\text{O} \rightleftharpoons \text{HOCl} + \text{OH}^-\]The production of OH鈦 ions makes the solution basic.
02

Evaluating the Nature of Sodium Perchlorate (NaClO鈧) in Water

Sodium perchlorate dissociates in water to produce sodium ions (Na鈦) and perchlorate ions (ClO鈧勨伝). Neither of these ions affects the pH significantly. Sodium ions are spectator ions, and the perchlorate ion is the conjugate base of a very strong acid (HClO鈧) and thus has negligible basicity. Therefore, a solution of sodium perchlorate remains neutral.
03

Conclusion

Based on the analysis, sodium hypochlorite affects the pH of the solution by increasing the concentration of hydroxide ions, making it basic. On the other hand, sodium perchlorate does not influence the pH because its constituent ions do not alter the pH, leading to a neutral solution. This understanding is based on the behavior of their ions in water.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Acidic, Basic, and Neutral Solutions
When discussing solutions, it is crucial to classify them based on pH levels. This classification is essential as it determines the solution鈥檚 behavior and application.
An acidic solution has a pH of less than 7. This means it has more hydrogen ions ( H鈦 ) than hydroxide ions ( OH鈦 ).
In contrast, a basic solution has a pH greater than 7, meaning it has a higher concentration of hydroxide ions ( OH鈦 ) compared to hydrogen ions.
A neutral solution is perfectly balanced, with equal amounts of H鈦 and OH鈦 , resulting in a pH of exactly 7. Water is the perfect example of a neutral solution.
Understanding these distinctions helps us predict how different substances will behave when dissolved in water. It also aids in determining the nature, reactivity, and potential use of the solution created.
Sodium Hypochlorite
Sodium hypochlorite (NaOCl) is a compound commonly used in household bleach. It plays a fascinating role in altering the pH of solutions. When NaOCl is dissolved in water, it separates into sodium ions (Na鈦) and hypochlorite ions (OCl鈦).

While sodium ions act as spectator ions and do not affect pH, the hypochlorite ions significantly impact it. These ions undergo hydrolysis, interacting with water, leading to the formation of hypochlorous acid (HOCl) and hydroxide ions (OH鈦):
\[\text{OCl}^- + \text{H}_2\text{O} \rightleftharpoons \text{HOCl} + \text{OH}^-\]
The reaction increases hydroxide ion concentration, tipping the balance towards a more basic solution. This is why sodium hypochlorite solutions are basic rather than neutral or acidic. This property makes it effective for disinfection, as basic environments can offer unique antimicrobial properties.
Sodium Perchlorate
Sodium perchlorate ( NaClO鈧 ) is another salt that has an interesting interaction with water. When dissolved, it disassociates into sodium ions ( Na鈦 ) and perchlorate ions ( ClO鈧勨伝 ).

As with sodium hypochlorite, the sodium ions here are spectator ions and do not alter the solution's pH.
The key difference lies in the perchlorate ions. Derived from a strong acid (perchloric acid HClO鈧 ), perchlorate ions are weak bases and exhibit negligible effects on pH.
Consequently, a solution of sodium perchlorate is neutral, as neither ion influences the balance of H鈦 and OH鈦 in the solution.
This neutrality is advantageous in many chemical processes and analyses, as it does not alter the acidity or basicity of the environment it's in.

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Most popular questions from this chapter

Calculate \(E^{\circ}\) for the disproportionation of \(\operatorname{In}^{+}(a q)\). $$ 3 \operatorname{In}^{+}(a q) \rightleftharpoons 2 \operatorname{In}(s)+\operatorname{In}^{3+}(a q) $$ (Disproportionation is a reaction in which a species undergoes both oxidation and reduction.) Use the following standard potentials: $$ \begin{gathered} \mathrm{In}^{+}(a q)+\mathrm{e}^{-} \Longrightarrow \operatorname{In}(s) ; E^{\circ}=-0.21 \mathrm{~V} \\ \mathrm{In}^{3+}(a q)+2 \mathrm{e}^{-} \Longrightarrow \mathrm{In}^{+}(a q) ; E^{\circ}=-0.40 \mathrm{~V} \end{gathered} $$ From \(E^{\circ}\), calculate \(\Delta G^{\circ}\) for the disproportionation (in kilojoules). Does this reaction occur spontaneously?

Devise a chemical method for separating a solution containing \(\mathrm{NaCl}\) and \(\mathrm{MgCl}_{2}\) to give two solutions or compounds each containing only one of the metal ions.

Complete and balance the following equations. a. \(\mathrm{K}(s)+\mathrm{Br}_{2}(l)\) b. \(\mathrm{K}(s)+\mathrm{H}_{2} \mathrm{O}(l) \longrightarrow\) c. \(\mathrm{NaOH}(s)+\mathrm{CO}_{2}(g) \longrightarrow\) d. \(\mathrm{Li}_{2} \mathrm{CO}_{3}(a q)+\mathrm{HNO}_{3}(a q) \longrightarrow\) e. \(\mathrm{K}_{2} \mathrm{SO}_{4}(a q)+\mathrm{Pb}\left(\mathrm{NO}_{3}\right)_{2}(a q) \longrightarrow\)

Use balanced equations to show how you could prepare \(\mathrm{Na}_{2} \mathrm{CO}_{3}\) from carbon, \(\mathrm{NaOH}\), air, and \(\mathrm{H}_{2} \mathrm{O}\).

Give equations for the preparation of \(\mathrm{N}_{2} \mathrm{O}\). You can use \(\mathrm{NaOH}, \mathrm{NaNO}_{3}, \mathrm{H}_{2} \mathrm{SO}_{4}\), and \(\left(\mathrm{NH}_{4}\right)_{2} \mathrm{SO}_{4}\left(\right.\) plus \(\mathrm{H}_{2} \mathrm{O}\) ). Sev- eral steps are required.

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