/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 156 A fertilizer contains phosphorus... [FREE SOLUTION] | 91Ó°ÊÓ

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A fertilizer contains phosphorus in two compounds, \(\mathrm{Ca}\left(\mathrm{H}_{2} \mathrm{PO}_{4}\right)_{2} \cdot \mathrm{H}_{2} \mathrm{O}\) and \(\mathrm{CaHPO}_{4}\). The fertilizer contains \(30.0 \%\) \(\mathrm{Ca}\left(\mathrm{H}_{2} \mathrm{PO}_{4}\right)_{2} \cdot \mathrm{H}_{2} \mathrm{O}\) and \(10.0 \% \mathrm{CaHPO}_{4}\) (by mass). What is the mass percentage of phosphorus in the fertilizer?

Short Answer

Expert verified
The mass percentage of phosphorus in the fertilizer is 9.66%.

Step by step solution

01

Determine the mass percentage of phosphorus in each compound

To find the mass percentage of phosphorus in each compound, first calculate the molar masses of \( \mathrm{Ca}\left(\mathrm{H}_{2} \mathrm{PO}_{4}\right)_{2} \cdot \mathrm{H}_{2} \mathrm{O} \) and \( \mathrm{CaHPO}_{4} \). For \( \mathrm{Ca}\left(\mathrm{H}_{2} \mathrm{PO}_{4}\right)_{2} \cdot \mathrm{H}_{2} \mathrm{O} \), the molar mass is the sum of the masses of \( 1 \text{ Ca} \), \( 2 \times \text{(H}_2\text{PO}_4)} \), and \( 1 \text{ H}_2\text{O} \). Similarly, for \( \mathrm{CaHPO}_{4} \), calculate the sum of the masses of \( 1 \text{ Ca} \), \( 1 \text{ HPO}_4 \). Use the periodic table for atomic weights. After finding the molar mass of each compound, calculate the percentage mass of phosphorus out of the total molar mass for each one.
02

Calculate the phosphorus mass percentage in Ca(H2PO4)2·H2O

The compound \( \mathrm{Ca}\left(\mathrm{H}_{2} \mathrm{PO}_{4}\right)_{2} \cdot \mathrm{H}_{2} \mathrm{O} \) contains 2 phosphorus atoms. With phosphorus having an atomic mass of approximately \( 31.0 \text{ g/mol} \), the mass contributed by phosphorus is \( 2 \times 31.0 = 62.0 \text{ g/mol} \). The molar mass of \( \mathrm{Ca}\left(\mathrm{H}_{2} \mathrm{PO}_{4}\right)_{2} \cdot \mathrm{H}_{2} \mathrm{O} \) is approximately \( 252.2 \text{ g/mol} \). Thus, the percentage of phosphorus in this compound is \( \frac{62.0}{252.2} \times 100 \approx 24.6\% \).
03

Calculate the phosphorus mass percentage in CaHPO4

The compound \( \mathrm{CaHPO}_{4} \) contains 1 phosphorus atom, contributing \( 31.0 \text{ g/mol} \) to its molar mass. The molar mass of \( \mathrm{CaHPO}_{4} \) is approximately \( 136.1 \text{ g/mol} \). Therefore, the phosphorus mass percentage is \( \frac{31.0}{136.1} \times 100 \approx 22.8\% \).
04

Calculate the total phosphorus content in the fertilizer

The fertilizer contains \( 30.0\% \) of \( \mathrm{Ca}\left(\mathrm{H}_{2} \mathrm{PO}_{4}\right)_{2} \cdot \mathrm{H}_{2} \mathrm{O} \) and \( 10.0\% \) of \( \mathrm{CaHPO}_{4} \). The phosphorus contribution from \( \mathrm{Ca}\left(\mathrm{H}_{2} \mathrm{PO}_{4}\right)_{2} \cdot \mathrm{H}_{2} \mathrm{O} \) is \( 0.30 \times 24.6\% = 7.38\% \), and from \( \mathrm{CaHPO}_{4} \) is \( 0.10 \times 22.8\% = 2.28\% \).
05

Summarize the total phosphorus content

Add the phosphorus contributions from both compounds to get the total phosphorus content: \( 7.38\% + 2.28\% = 9.66\% \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Molar Mass Calculation
Understanding molar mass is crucial in chemical calculations. Molar mass refers to the mass of one mole of a substance, expressed in grams per mole (\( ext{g/mol}\)). It acts as a bridge between the atomic scale and the macroscopic scale, allowing us to count atoms by weighing them. Molar mass is determined by summing up the atomic masses of all atoms in the given molecular formula.
In this exercise, two compounds are involved: \(\text{Ca(H}_2\text{PO}_4\text{)}_2\cdot \text{H}_2\text{O}\) and \(\text{CaHPO}_4\). For \(\text{Ca(H}_2\text{PO}_4\text{)}_2\cdot \text{H}_2\text{O}\), we calculate the combined mass of 1 calcium atom, 4 hydrogen atoms, 2 phosphorus atoms, 8 oxygen atoms, and an additional water molecule. Similarly, for \(\text{CaHPO}_4\), we find the mass of 1 calcium, 1 hydrogen, 1 phosphorus, and 4 oxygen atoms.
Using atomic weights from the periodic table is essential in these calculations:
  • Calcium (Ca) around 40 g/mol
  • Phosphorus (P) approximately 31 g/mol
  • Hydrogen (H) about 1 g/mol per atom
  • Oxygen (O) around 16 g/mol per atom
The accurate molar masses for these compounds facilitate further percentage mass calculations needed to determine phosphorus content.
Phosphorus Compounds
Phosphorus compounds play a significant role in fertilizers, enhancing plant growth by contributing essential nutrients to the soil. The compounds in this exercise, \(\text{Ca(H}_2\text{PO}_4\text{)}_2\cdot \text{H}_2\text{O}\) and \(\text{CaHPO}_4\), each contain phosphorus but in varying forms and proportions.
Understanding the phosphorous content involves recognizing the structure of these compounds:
  • \(\text{Ca(H}_2\text{PO}_4\text{)}_2\cdot \text{H}_2\text{O}\) is known as calcium dihydrogen phosphate and includes two phosphorus atoms per molecule.
  • \(\text{CaHPO}_4\) is calcium hydrogen phosphate, carrying one phosphorus atom per molecule.
Each compound's molecular structure influences its reactivity and solubility in soil, impacting how effectively nutrients like phosphorus are delivered to plants. Such knowledge is pivotal for creating balanced fertilizers that support sustainable agriculture and optimal plant health.
Mass Contribution Analysis
Mass contribution analysis helps determine how much of each element contributes to the total mass of a compound, especially important in multi-element substances like fertilizers. By calculating the mass percentage of each element, we can identify the prevalence of specific components, like phosphorus, within a mixture.
To perform mass contribution analysis, the total mass of each compound is first considered:
  • Convert the percentage of each compound in the fertilizer to its proportional phosphorus contribution.
    • For \(\text{Ca(H}_2\text{PO}_4\text{)}_2\cdot \text{H}_2\text{O}\), contributing 24.6% phosphorus, its net contribution is found by \((0.30 \times 24.6\%) = 7.38\%\)
    • For \(\text{CaHPO}_4\), with 22.8% phosphorus, the calculation is \((0.10 \times 22.8\%) = 2.28\%\)
  • The cumulative phosphorus percentage in the fertilizer is obtained by summing these contributions, totaling 9.66%.
This analysis validates the effective phosphorus content in the fertilizer, ensuring it meets agricultural needs. Such details assist agriculturalists in choosing fertilizers based on their crop requirements and environmental conditions, optimizing the use of each element like phosphorus.

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