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Give the notation for a voltaic cell constructed from a hydrogen electrode (cathode) in \(1.0 M \mathrm{HCl}\) and a nickel electrode (anode) in \(1.0 \mathrm{M} \mathrm{NiSO}_{4}\) solution. The electrodes are connected by a salt bridge.

Short Answer

Expert verified
\(Ni(s) | Ni^{2+}(1.0M) || H^+(1.0M) | H_2(g)\)

Step by step solution

01

Identify the cell components

A voltaic cell is made up of two half-cells; in this case, we have a hydrogen electrode and a nickel electrode. The hydrogen electrode will serve as the cathode and the nickel electrode as the anode.
02

Write the electrode reactions

For the hydrogen electrode (cathode), the reaction is: \(2H^+(aq) + 2e^- \rightarrow H_2(g)\). For the nickel electrode (anode), the reaction is: \(Ni(s) \rightarrow Ni^{2+}(aq) + 2e^-\).
03

Determine the direction of electron flow

Electrons flow from the anode to the cathode in a voltaic cell. Thus, electrons will move from the nickel electrode to the hydrogen electrode.
04

Write the cell notation

Cell notation follows the format: Anode | Anode Solution || Cathode Solution | Cathode. For the given voltaic cell, it becomes: \(Ni(s) | Ni^{2+}(1.0M) || H^+(1.0M) | H_2(g)\), where \(||\) represents the salt bridge and \(|\) separates different phases or components in the solution.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Electrode Reactions
In a voltaic cell, reactions occur at the electrodes, which are crucial for producing electrical energy. Let's break down the electrode reactions using the hydrogen and nickel electrodes from the exercise.
  • Hydrogen Electrode (Cathode): The hydrogen electrode serves as the cathode. Here, the reaction involves the reduction of hydrogen ions. The chemical equation is: \(2H^+(aq) + 2e^- \rightarrow H_2(g)\). This reaction shows that two electrons combine with hydrogen ions to form hydrogen gas.

  • Nickel Electrode (Anode): Serving as the anode, the nickel electrode undergoes oxidation. The reaction here is: \(Ni(s) \rightarrow Ni^{2+}(aq) + 2e^-\). This means a solid nickel atom loses electrons to form nickel ions.
At the anode, oxidation occurs, and electrons are released. At the cathode, reduction takes place, and electrons are accepted. Together, these reactions make it possible for the voltaic cell to generate an electric current.
Electron Flow
The flow of electrons is vital in a voltaic cell, allowing it to convert chemical energy into electrical energy. Understanding this electron movement is key.
Electrons always flow from the anode to the cathode in a voltaic cell. This direction is consistent because electron flow always moves from a region of higher potential to a region of lower potential.
In our example, electrons leave the nickel electrode (anode) and travel through an external circuit to reach the hydrogen electrode (cathode). This happens because nickel undergoes oxidation, losing electrons which then flow towards the cathode where they are needed for reduction.
  • The nickel electrode is the source of electrons, so it loses electrons.
  • The hydrogen electrode gains electrons as they flow, which drives the reduction reaction.
This consistent electron movement powers various devices connected to the cell, showcasing the practical importance of controlling electron flow in voltaic cells.
Cell Notation
Cell notation is a shorthand description of the components and reactions occurring in a voltaic cell. It provides detailed but concise information.
The general format for cell notation is: "Anode | Anode Solution || Cathode Solution | Cathode". Here's how we translate the given voltaic cell into cell notation:
For the nickel and hydrogen cell: \(Ni(s) | Ni^{2+}(1.0M) || H^+(1.0M) | H_2(g)\).
  • "Ni(s) | Ni^{2+}(1.0M)": This part represents the anode along with its ionic solution. Solid nickel undergoes oxidation.
  • "||": This symbol signifies the presence of a salt bridge, which maintains charge balance by allowing ions to pass between the two half-cells.
  • "H^+(1.0M) | H_2(g)": This represents the cathode, detailing the hydrogen ions in solution that are being reduced to gaseous hydrogen.
Cell notation is crucial as it gives a quick summary of the electrochemical cell's components and processes, making it easier to understand complex systems in a readable format.

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Most popular questions from this chapter

Balance the following skeleton equations. The reactions occur in acidic or basic aqueous solution, as indicated. a. \(\mathrm{MnO}_{4}^{-}+\mathrm{S}^{2-} \longrightarrow \mathrm{MnO}_{2}+\mathrm{S}_{8}\) (basic) b. \(\mathrm{IO}_{3}^{-}+\mathrm{HSO}_{3}^{-} \longrightarrow \mathrm{I}^{-}+\mathrm{SO}_{4}^{2-} \quad\) (acidic) c. \(\mathrm{Fe}(\mathrm{OH})_{2}+\mathrm{CrO}_{4}{ }^{2-} \longrightarrow \mathrm{Fe}(\mathrm{OH})_{3}+\mathrm{Cr}(\mathrm{OH})_{4}^{-} \quad\) (basic) d. \(\mathrm{Cl}_{2} \longrightarrow \mathrm{Cl}^{-}+\mathrm{ClO}^{-}\) (basic)

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