Chapter 18: Problem 22
Write solubility product expressions for the following compounds. a. \(\mathrm{Ba}_{3}\left(\mathrm{PO}_{4}\right)_{2}\) b. \(\mathrm{FePO}_{4}\) c. \(\mathrm{PbI}_{2}\) d. \(\mathrm{Ag}_{2} \mathrm{~S}\)
Short Answer
Expert verified
a. \( K_{sp} = [\mathrm{Ba}^{2+}]^3[\mathrm{PO}_{4}^{3-}]^2 \); b. \( K_{sp} = [\mathrm{Fe}^{3+}][\mathrm{PO}_{4}^{3-}] \); c. \( K_{sp} = [\mathrm{Pb}^{2+}][\mathrm{I}^{-}]^2 \); d. \( K_{sp} = [\mathrm{Ag}^{+}]^2[\mathrm{S}^{2-}] \).
Step by step solution
01
Introduction to Solubility Product
Solubility product expressions are used to describe the equilibrium between a solid and its ions in a saturated solution. For a salt represented as \(aA_bB_c\), its solubility product expression is given by \(K_{sp} = [A^{b+}]^a [B^{c-}]^b\) where \([A^{b+}]\) and \([B^{c-}]\) are the molar concentrations of the ions in solution.
02
Solubility Product of \(\mathrm{Ba}_{3}\left(\mathrm{PO}_{4}\right)_{2}\)
For the compound \(\mathrm{Ba}_{3}\left(\mathrm{PO}_{4}\right)_{2}\), it dissociates into 3 \(\mathrm{Ba}^{2+}\) ions and 2 \(\mathrm{PO}_{4}^{3-}\) ions. The solubility product expression is: \[ K_{sp} = [\mathrm{Ba}^{2+}]^3[\mathrm{PO}_{4}^{3-}]^2 \].
03
Solubility Product of \(\mathrm{FePO}_{4}\)
The compound \(\mathrm{FePO}_4\) dissociates into 1 \(\mathrm{Fe}^{3+}\) ion and 1 \(\mathrm{PO}_4^{3-}\) ion. The solubility product expression is: \[ K_{sp} = [\mathrm{Fe}^{3+}][\mathrm{PO}_4^{3-}] \].
04
Solubility Product of \(\mathrm{PbI}_{2}\)
The dissolution of \(\mathrm{PbI}_2\) produces 1 \(\mathrm{Pb}^{2+}\) ion and 2 \(\mathrm{I}^-\) ions. Thus, the solubility product expression is: \[ K_{sp} = [\mathrm{Pb}^{2+}][\mathrm{I}^{-}]^2 \].
05
Solubility Product of \(\mathrm{Ag}_{2} \mathrm{~S}\)
For \(\mathrm{Ag}_{2} \mathrm{~S}\), the dissociation involves 2 \(\mathrm{Ag}^+\) ions and 1 \(\mathrm{S}^{2-}\) ion. The solubility product expression is: \[ K_{sp} = [\mathrm{Ag}^{+}]^2[\mathrm{S}^{2-}] \].
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Ksp expression
The solubility product, often represented as \( K_{sp} \), is a key concept in understanding how salts dissolve in water. It describes the point at which a solid substance reaches equilibrium with its dissolved ions in a solution. Here is a straightforward way to think about it: imagine when a salt is put into water, it breaks down into its individual ions. The interactions and balance between these ions in the solution are quantified by the \( K_{sp} \).### Writing Ksp ExpressionsTo formulate a \( K_{sp} \) expression:
- First, identify how the compound dissociates into ions. For example, \( \text{Ba}_3(\text{PO}_4)_2 \) dissociates into 3 \( \text{Ba}^{2+} \) ions and 2 \( \text{PO}_4^{3-} \) ions.
- Next, express the \( K_{sp} \) in terms of the concentrations of these ions raised to the power of their stoichiometric coefficients.
- Using the above example, the expression becomes \( K_{sp} = [\text{Ba}^{2+}]^3 [\text{PO}_4^{3-}]^2 \).
Chemical Equilibrium
Chemical equilibrium is an essential concept, especially when discussing solubility products in solutions. It occurs when a chemical reaction reaches a point where the rate of the forward reaction (solid dissolving) equals the rate of the reverse reaction (ions recombining to form the solid). In such a state, the concentrations of the reactants and products (or ions and solids, in our case) remain constant over time.### Equilibrium in SolubilityUnderstanding equilibrium in solubility involves:
- Recognizing that, at equilibrium, the amount of dissolved ions and undissolved solid remains constant as the rates of dissolution and precipitation are equal.
- For a saturated solution, the \( K_{sp} \) value reflects the maximum possible product of ion concentrations, without forming excess solid.
- Changes in conditions such as temperature or the presence of other ions can shift this equilibrium, changing the solubility product.
Dissociation in Solution
Dissociation in solution is a crucial concept for understanding the behavior of ionic compounds in water. It refers to the process by which a solid compound separates into its individual ions when dissolved in water. This is how substances like salts interact with water and achieve equilibrium.### Process of DissociationDuring dissociation:
- An ionic compound, such as \( \text{Ag}_2 \text{S} \), splits into its constituent ions in the solution, resulting in two \( \text{Ag}^+ \) ions and one \( \text{S}^{2-} \) ion.
- Each ion disperses uniformly in the water, contributing to the ionic concentration necessary for equilibrium.
- The degree of dissociation impacts the formation of the \( K_{sp} \) expression, as seen with compounds like \( \text{PbI}_2 \) where one \( \text{Pb}^{2+} \) and two \( \text{I}^{-} \) ions result from dissociation.