Chapter 15: Problem 110
Antimony(V) chloride, \(\mathrm{SbCl}_{5}\), dissociates on heating to give antimony(III) chloride, \(\mathrm{SbCl}_{3}\), and chlorine. $$ \mathrm{SbCl}_{5}(g) \rightleftharpoons \mathrm{SbCl}_{3}(g)+\mathrm{Cl}_{2}(g) $$ A closed 3.50-L vessel initially contains \(0.0125 \mathrm{~mol} \mathrm{SbCl}_{5}\). What is the total pressure at \(248^{\circ} \mathrm{C}\) when equilibrium is achieved? The value of \(K_{c}\) at \(248^{\circ} \mathrm{C}\) is \(2.50 \times 10^{-2}\).
Short Answer
Step by step solution
Write the equilibrium expression for the reaction
Determine the initial concentrations
Set up the ICE table
Solve for x using the equilibrium expression
Calculate equilibrium concentrations
Calculate total pressure at equilibrium
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Equilibrium Constant
- If \( K_c \) is much greater than 1, the reaction favors the formation of products.
- If \( K_c \) is much less than 1, the reactants are favored.
- A \( K_c \) value around 1 indicates a balance between products and reactants.
ICE Table
Ideal Gas Law
- \(P\) is the pressure,
- \(n\) is the number of moles,
- \(R\) is the ideal gas constant (\(0.0821 \, \mathrm{L} \, \mathrm{atm/mol} \, \mathrm{K}\)),
- \(T\) is the temperature in Kelvin, and
- \(V\) is the volume.