Chapter 12: Problem 89
A sample of potassium aluminum sulfate 12 -hydrate, \(\mathrm{KAl}\left(\mathrm{SO}_{4}\right)_{2} \cdot 12 \mathrm{H}_{2} \mathrm{O}\), containing \(118.6 \mathrm{mg}\) is dissolved in \(1.000 \mathrm{~L}\) of solution. Calculate the following for the solution: a. The molarity of \(\mathrm{KAl}\left(\mathrm{SO}_{4}\right)_{2}\). b. The molarity of \(\mathrm{SO}_{4}^{2-}\). c. The molality of \(\mathrm{KAl}\left(\mathrm{SO}_{4}\right)_{2}\), assuming that the density of the solution is \(1.00 \mathrm{~g} / \mathrm{mL}\).
Short Answer
Step by step solution
Find the Molar Mass of Compound
Calculate Moles of Compound
Calculate Molarity of Compound
Calculate Molarity of \(\mathrm{SO}_{4}^{2-}\)
Calculate Mass of Solvent
Calculate Molality of Compound
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Potassium Aluminum Sulfate
Molality
- Find the moles of solute, which you already calculated when finding the molarity.
- Determine the mass of the solvent in kilograms. This can be tricky because it requires subtracting the solute's mass from the total mass of the solution.
- Use the formula \( m = \frac{\text{moles of solute}}{\text{kilograms of solvent}} \) to calculate the molality.
Solution Density
- A liter of solution weighs approximately \(1000 \text{ g}\).
- Subtracting the solute's mass from this total gives the solvent's mass, crucial for molality calculations.
Molar Mass Calculation
- Potassium (K): \(1 \times 39.10 \text{ g/mol} = 39.10 \text{ g/mol}\)
- Aluminum (Al): \(1 \times 26.98 \text{ g/mol} = 26.98 \text{ g/mol}\)
- Sulfur (S) for sulfate group: \(2 \times 32.07 \text{ g/mol} = 64.14 \text{ g/mol}\)
- Oxygen (O) in sulfate and water combined: \((8 + 24) \times 16.00 \text{ g/mol} = 384.00 \text{ g/mol}\)
- Hydrogen (H) in water: \(24 \times 1.01 \text{ g/mol} = 24.24 \text{ g/mol}\)