Chapter 12: Problem 46
What mass of solution containing \(6.50 \%\) sodium sulfate, \(\mathrm{Na}_{2} \mathrm{SO}_{4}\), by mass contains \(1.50 \mathrm{~g} \mathrm{Na}_{2} \mathrm{SO}_{4} ?\)
Short Answer
Expert verified
23.08 g of solution.
Step by step solution
01
Understand the Percentage Composition
The problem states that the solution contains \(6.50\%\) sodium sulfate by mass. This means that in every \(100\, \text{g}\) of the solution, \(6.50\, \text{g}\) is sodium sulfate \(\mathrm{Na}_2\mathrm{SO}_4}\).
02
Setup the Proportion
To find the total mass of the solution that contains \(1.50\, \text{g}\) of \(\mathrm{Na}_2\mathrm{SO}_4}\), we set up a proportion based on the percentage. \[\frac{6.50\, \text{g Na}_2\mathrm{SO}_4}}{100\, \text{g solution}} = \frac{1.50\, \text{g Na}_2\mathrm{SO}_4}}{x\, \text{g solution}}\]Here, \(x\) is the unknown total mass of the solution.
03
Solve for x
Cross-multiply to solve the equation for \(x\):\[6.50x = 100 \times 1.50\]Solve for \(x\):\[x = \frac{150}{6.50} = 23.08\]
04
Interpret the Result
The calculations show that to have \(1.50\, \text{g}\) of \(\mathrm{Na}_2\mathrm{SO}_4}\), you need \(23.08\, \text{g}\) of the solution containing \(6.50\%\) sodium sulfate by mass.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Sodium Sulfate Solution
Sodium sulfate (\( \mathrm{Na}_2\mathrm{SO}_4} \)) is a chemical compound that is often used in various applications such as in detergents, paper production, and even medicine.
When sodium sulfate is dissolved in water, it forms a sodium sulfate solution. This describes a mixture where sodium sulfate is uniformly distributed throughout the solvent, usually water, making it a homogeneous solution, meaning it looks the same throughout.
In the original exercise, it's specified that the sodium sulfate solution has a particular concentration, namely 6.50% by mass. This means for every 100 grams of the solution, 6.50 grams is pure sodium sulfate.
When sodium sulfate is dissolved in water, it forms a sodium sulfate solution. This describes a mixture where sodium sulfate is uniformly distributed throughout the solvent, usually water, making it a homogeneous solution, meaning it looks the same throughout.
In the original exercise, it's specified that the sodium sulfate solution has a particular concentration, namely 6.50% by mass. This means for every 100 grams of the solution, 6.50 grams is pure sodium sulfate.
- Solutions are important in chemistry because they allow for controlled reactions.
- Homogeneous solutions make it easier to predict chemical reactions.
- Knowing the precise concentration lets chemists create solutions for specific chemical needs.
Solution Concentration
Solution concentration refers to the amount of solute present in a given quantity of solvent or solution. It tells us how much of a substance there is mixed into another, playing a crucial role in chemistry experiments and industrial applications.
There are various ways to express solution concentration, but in this exercise, concentration is given as a percentage by mass. This practically implies:\[\text{Percentage by mass} = \left(\frac{\text{mass of solute}}{\text{mass of solution}}\right) \times 100\]Understanding how to interpret this allows you to determine how much of a substance (sodium sulfate in the original problem) is in a particular solution. This is particularly useful for tasks where specific concentrations are required.
There are various ways to express solution concentration, but in this exercise, concentration is given as a percentage by mass. This practically implies:\[\text{Percentage by mass} = \left(\frac{\text{mass of solute}}{\text{mass of solution}}\right) \times 100\]Understanding how to interpret this allows you to determine how much of a substance (sodium sulfate in the original problem) is in a particular solution. This is particularly useful for tasks where specific concentrations are required.
- Percentage concentrations are widely used due to their simplicity.
- It's important to distinguish between weight/weight percentage versus volume/volume or molarity.
Mass Proportion in Chemistry
When calculating how much of each material is present in a chemical solution, we often use mass proportion. Mass proportion compares the mass of different components in a solution and is commonly used in chemistry to figure out how much of one element is needed compared to another.In our exercise, we created a proportion to solve for the total mass of the solution needed to have a specific mass of sodium sulfate. By setting up the proportion:\[\frac{6.50\, \text{g Na}_2\mathrm{SO}_4}}{100\, \text{g solution}} = \frac{1.50\, \text{g Na}_2\mathrm{SO}_4}}{x\, \text{g solution}}\]we determine the answer through simple cross-multiplication.This technique ensures that the true ratio of the components is preserved when calculating a requirement or providing a reaction formula for any quantity of material. Understanding this relationship is crucial because:
- It helps in scaling chemical reactions up or down.
- Ensures that the desired chemical specifications are met.
- Reduces waste by indicating the exact amounts needed.