Chapter 11: Problem 88
Metallic barium has a body-centered cubic structure (all atoms at the lattice points) and a density of \(3.51 \mathrm{~g} / \mathrm{cm}^{3}\). Assume barium atoms to be spheres. The spheres in a bodycentered array occupy \(68.0 \%\) of the total space. Find the atomic radius of barium. (See Problem 11.87.)
Short Answer
Step by step solution
Understand the Structure
Calculate Volume of a Unit Cell
Calculate Mass Per Unit Cell
Calculate Volume of the Unit Cell
Relate Unit Cell Volume to Atomic Radius
Solve for the Atomic Radius
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Atomic Radius
To calculate the atomic radius of barium, we use the relationship between the cube's side length and the atomic radius in a bcc crystal, given as:
- \[ a = \frac{4r}{\sqrt{3}} \]
- First, you need to solve for the cube's side length using the volume \( V \) of the unit cell: \( a = V^{1/3} \).
- Then, use this side length to calculate \( r \) using the formula \( r = \frac{a \sqrt{3}}{4} \).
Density Formula
- \[ \rho = \frac{m}{V} \]
For barium in a body-centered cubic structure, we know:
- Density \( \rho = 3.51 \text{ g/cm}^3 \)
- Mass per unit cell, which comes from multiplying the mass per atom by the number of atoms per unit cell (2 for bcc).
- Rearrange the density formula to: \[ V = \frac{m}{\rho} \]
- Substitute the mass of the unit cell and the density to find the volume \( V \).
Packing Efficiency
Understanding packing efficiency helps in visualizing how atoms are arranged in crystalline solids. For barium, this means:
- 68% of the volume of the unit cell is filled with barium atoms.
- The rest, 32%, is the "empty" space not occupied by atoms.
- \[ \text{Packing Efficiency} = \frac{ \text{Volume occupied by atoms} }{ \text{Total unit cell volume} } \times 100 \%\]
Unit Cell Volume
Here's how you can find it:
- Start with the mass per atom, calculated from the molar mass and Avogadro's number.
- Multiply this by 2, since there are two atoms per unit cell in a bcc structure.
- Apply the density formula \( V = \frac{m}{\rho} \) using the mass of the unit cell and the given density.