/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 72 Explain the meaning of the symbo... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Explain the meaning of the symbol \(4 d^{6}\).

Short Answer

Expert verified
\(4 d^{6}\) represents 6 electrons in d-orbitals of the 4th energy level.

Step by step solution

01

Understanding the Notation

The notation "\(4 d^{6}\)" represents a chemical electron configuration. This particular configuration indicates the distribution of electrons in an atom or ion's orbitals in a specific shell or energy level.
02

Decoding the Coefficient

The number "4" before the letter "d" indicates the principal energy level or shell number. It specifies that the electrons being considered are in the fourth energy level of the atom.
03

Interpreting the Orbital Letter

The letter "d" denotes the type of orbital where the electrons are located. In this context, "d" refers to a set of five d-orbitals, which can collectively hold a maximum of 10 electrons.
04

Analyzing the Superscript

The superscript "6" tells us the number of electrons present in the d-orbitals of the fourth energy level. Therefore, there are 6 electrons occupying these d-orbitals.
05

Conclusion

The symbol "\(4 d^{6}\)" describes an electron configuration where 6 electrons are occupying the d-orbitals in the fourth principal energy level or shell of an atom.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Principal Energy Level
In the context of electron configuration, the term "principal energy level" refers to the main energy levels within an atom where electrons are likely to be found. These levels are denoted by integers such as 1, 2, 3, and 4.

The principal energy level is the n value in the electron configuration notation. For example, in the configuration "4d\(^{6}\)", the number "4" is the principal energy level. This means the electrons reside in the fourth energy level of an atom.

Each principal energy level can hold a certain number of electrons, determined by the formula \(2n^2\). Thus:
  • The first level can hold 2 electrons.
  • The second can hold 8 electrons.
  • The third can hold 18 electrons.
  • The fourth can hold 32 electrons.
Understanding principal energy levels is crucial because they help predict and explain the chemical properties of elements, such as reactivity and bonding.
D-Orbitals
D-orbitals are a group of orbitals within atoms where electrons can be found. As part of the electron configuration, "d" stands for these orbitals, specifically indicating a set of five orbitals within a given energy level.

Each d-orbital can hold a maximum of 2 electrons, adding up to a total of 10 electrons for all five d-orbitals when fully occupied.

In the example "4d\(^{6}\)", the "d" specifies that the configuration includes electrons in d-orbitals. The number "6" as a superscript shows that there are 6 electrons distributed among these d-orbitals.
  • D-orbitals are one of the four types of orbitals: s, p, d, and f.
  • These orbitals start to appear from the third principal energy level onwards.
D-orbitals are important because they shape the electronic structure and properties of transition metals and influence aspects like magnetic properties and complex formation.
Electron Shells
Electron shells are layers around the nucleus of an atom where electrons reside. These shells are defined by their distance from the nucleus, with closer shells being lower in energy.

Every shell corresponds to a principal energy level and can hold a certain number of electrons. The concept of electron shells helps to organize how electrons are distributed in an atom. For instance:
  • The first shell (closest to the nucleus) can contain up to 2 electrons.
  • The second shell can hold a maximum of 8 electrons.
  • Succeeding shells can host more electrons, following the \(2n^2\) rule.
In the configuration "4d\(^{6}\)", these 6 electrons are part of the fourth electron shell or principal energy level.

Knowledge about electron shells is pivotal for understanding how elements interact in chemical reactions. These shells provide insight into an element's valence electrons, which are vital for determining bonding and chemical behavior.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

A certain pitcher's fastballs have been clocked at about 100 mph. (a) Calculate the wavelength of a \(0.141-\mathrm{kg}\) baseball (in \(\mathrm{nm}\) ) at this speed. (b) What is the wavelength of a hydrogen atom at the same speed? \((1 \mathrm{mile}=1609 \mathrm{~m} .)\)

When light of frequency equal to \(2.11 \times 10^{15} \mathrm{~s}^{-1}\) shines on the surface of gold metal, the kinetic energy of ejected electrons is found to be \(5.83 \times 10^{-19} \mathrm{~J}\) What is the work function of gold?

All molecules undergo vibrational motions. Quantum mechanical treatment shows that the vibrational energy, \(E_{\mathrm{vib}},\) of a diatomic molecule like \(\mathrm{HCl}\) is given by \(E_{\mathrm{vib}}=\left(n+\frac{1}{2}\right) h \nu\) where \(n\) is a quantum given by \(n=0,1,2,3, \ldots\) and \(\nu\) is the fundamental frequency of vibration. (a) Sketch the first three vibrational energy levels for HCl. (b) Calculate the energy required to excite a \(\mathrm{HCl}\) molecule from the ground level to the first excited level. The fundamental frequency of vibration for \(\mathrm{HCl}\) is \(8.66 \times 10^{13} \mathrm{~s}^{-1} .\) (c) The fact that the lowest vibrational energy in the ground level is not zero but equal to \(\frac{1}{2} h \nu\) means that molecules will vibrate at all temperatures, including the absolute zero. Use the Heisenberg uncertainty principle to justify this prediction. (Hint: Consider a nonvibrating molecule and predict the uncertainty in the momentum and hence the uncertainty in the position.

The retina of a human eye can detect light when radiant energy incident on it is at least \(4.0 \times 10^{-17} \mathrm{~J}\). For light of 600 -nm wavelength, how many photons does this correspond to?

The ground-state electron configurations listed here are incorrect. Explain what mistakes have been made in each and write the correct electron configurations. Al: \(1 s^{2} 2 s^{2} 2 p^{4} 3 s^{2} 3 p^{3}\) B: \(1 s^{2} 2 s^{2} 2 p^{5}\) \(\mathrm{F}: 1 s^{2} 2 s^{2} 2 p^{6}\)

See all solutions

Recommended explanations on Chemistry Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.