/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 58 A 2.5-L flask at \(15^{\circ} \m... [FREE SOLUTION] | 91Ó°ÊÓ

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A 2.5-L flask at \(15^{\circ} \mathrm{C}\) contains a mixture of three gases, \(\mathrm{N}_{2},\) He, and \(\mathrm{Ne},\) at partial pressures of \(0.32 \mathrm{~atm}\) for \(\mathrm{N}_{2}, 0.15\) atm for \(\mathrm{He},\) and 0.42 atm for \(\mathrm{Ne}\). (a) \(\mathrm{Cal}\) culate the total pressure of the mixture. (b) Calculate the volume in liters at STP occupied by He and Ne if the \(\mathrm{N}_{2}\) is removed selectively.

Short Answer

Expert verified
(a) Total pressure is 0.89 atm. (b) Volume at STP is 1.377 L.

Step by step solution

01

Calculate the Total Pressure

To calculate the total pressure of the gas mixture, we sum up the partial pressures of all the gases present. The formula for total pressure \( P_{\text{total}} \) is given by:\[ P_{\text{total}} = P_{\text{N}_2} + P_{\text{He}} + P_{\text{Ne}} \]Substitute the given values:\[ P_{\text{total}} = 0.32\, \text{atm} + 0.15\, \text{atm} + 0.42\, \text{atm} = 0.89\, \text{atm} \]
02

Calculate Moles of He and Ne

At STP, 1 mole of any ideal gas occupies 22.4 L. First, we need to find the number of moles of He and Ne present using the ideal gas law, \( PV = nRT \), and then compute the total volume at STP. For calculation, use \( R = 0.0821 \, \text{L atm}{/}\text{mol K} \). The temperature \( T \) is \((15 + 273) \text{K} = 288 \text{K} \).Calculate moles separately for each gas:For He:\[ n_{\text{He}} = \frac{P_{\text{He}}V}{RT} = \frac{0.15 \times 2.5}{0.0821 \times 288} \approx 0.0159 \, \text{mol} \]For Ne:\[ n_{\text{Ne}} = \frac{P_{\text{Ne}}V}{RT} = \frac{0.42 \times 2.5}{0.0821 \times 288} \approx 0.0456 \, \text{mol} \]
03

Calculate Volume at STP

Using the moles calculated, find the total volume they occupy at STP. Using the fact that 1 mole occupies 22.4 L at STP, we have:For He:\[ V_{\text{He, STP}} = n_{\text{He}} \times 22.4 = 0.0159 \times 22.4 \approx 0.356 \text{ L} \]For Ne:\[ V_{\text{Ne, STP}} = n_{\text{Ne}} \times 22.4 = 0.0456 \times 22.4 \approx 1.021 \text{ L} \]Add the two volumes:\[ V_{\text{total, STP}} = V_{\text{He, STP}} + V_{\text{Ne, STP}} = 0.356 + 1.021 = 1.377 \text{ L} \]

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Ideal Gas Law
The ideal gas law is an essential equation in chemistry and physics, used to relate the pressure, volume, temperature, and number of moles of a gas. This relationship is expressed in the formula \( PV = nRT \). Here, \( P \) stands for pressure, \( V \) for volume, \( n \) for the number of moles, \( R \) is the ideal gas constant, and \( T \) stands for temperature in Kelvin. This equation helps us understand how gases behave under different conditions.

The beauty of the ideal gas law is its simplicity and versatility. It applies to ideal gases, which are hypothetical gases that perfectly follow this law under all conditions. Real gases approximate this behavior under a wide range of conditions. Understanding the ideal gas law allows us to compute unknown properties of a gas if we know the others. For example, if we know the pressure, volume, and temperature of a gas, we can solve for the number of moles present.
  • Calculate pressure using the formula: \( P = \frac{nRT}{V} \)
  • Find volume by rearranging: \( V = \frac{nRT}{P} \)
  • Moles can be found with: \( n = \frac{PV}{RT} \)
  • Temperature can be rearranged as: \( T = \frac{PV}{nR} \)
The ideal gas constant \( R \) is typically 0.0821 L atm/mol K. Using this constant ensures all units fit correctly in calculative scenarios. Understanding this will make solving gas-related exercises simpler.
Standard Temperature and Pressure (STP)
Standard Temperature and Pressure, abbreviated as STP, is a reference point used in chemistry to provide a clear comparison between different gas measurements. At STP, the temperature is set at 0°C (273.15 K), and the pressure is set at 1 atm. This is a convenient standard for calculations because it allows for a straightforward determination of the volume occupied by one mole of an ideal gas.

Under these conditions, 1 mole of any ideal gas occupies 22.4 liters. This rule of thumb drastically simplifies conversions between moles and volume, especially when calculating gases in controlled laboratory settings or theoretical exercises. When asked to convert gas volumes to STP, keep these conditions in mind for precise results.
  • STP helps in comparing gas properties easily across different scenarios.
  • Always convert temperatures to Kelvin when dealing with gases for consistent calculations.
Real-world applications often need adjustments for non-ideal behavior, but the STP condition remains foundational for introductory exercises.
Moles and Volume Calculations
To determine the volume of gases at specific conditions, one can utilize the relationship between the number of moles and volume derived from the ideal gas law. At STP, where the calculation becomes simpler, the volume of an ideal gas can be directly calculated using its moles because one mole of gas is equivalent to 22.4 L.

In the given problem, we first calculate the moles of each gas using the ideal gas law with the given initial conditions. After finding the moles, we rely on the STP volume of 22.4 L/mole to get the volume at STP.
Consider the following when working through moles and volume:
  • First, use \( PV = nRT \) to calculate the number of moles if pressure, volume, and temperature are known.
  • Then, apply the standard volume at STP to find actual volume: \( V = n imes 22.4 \) L
  • Ensure unit consistency to avoid errors, especially with temperature (use Kelvin) and pressure (in atm).
Using these steps, you can accurately solve for volumes under different conditions and solidify your understanding of gas behavior.

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Most popular questions from this chapter

What are the basic assumptions of the kinetic molecular theory of gases?

What does the Maxwell speed distribution curve tell us? Does Maxwell's theory work for a sample of 200 molecules? Explain.

Which of the following two statements is correct? (a) Heat is produced by the collision of gas molecules against one another. (b) When a gas is heated, the molecules collide with one another more often.

Apply your knowledge of the kinetic theory of gases to these situations. (a) Does a single molecule have a temperature? (b) Two flasks of volumes \(V_{1}\) and \(V_{2}\left(V_{2}>V_{1}\right)\) contain the same number of helium atoms at the same temperature. (i) Compare the root- meansquare (rms) speeds and average kinetic energies of the helium (He) atoms in the flasks. (ii) Compare the frequency and the force with which the He atoms collide with the walls of their containers. (c) Equal numbers of He atoms are placed in two flasks of the same volume at temperatures \(T_{1}\) and \(T_{2}\left(T_{2}>T_{1}\right)\). (i) Compare the rms speeds of the atoms in the two flasks. (ii) Compare the frequency and the force with which the He atoms collide with the walls of their containers. (d) Equal numbers of He and neon (Ne) atoms are placed in two flasks of the same volume and the temperature of both gases is \(74^{\circ} \mathrm{C}\). Comment on the validity of these statements: (i) The rms speed of He is equal to that of Ne. (ii) The average kinetic energies of the two gases are equal. (iii) The rms speed of each He atom is \(1.47 \times 10^{3} \mathrm{~m} / \mathrm{s}\)

A sample of air contains only nitrogen and oxygen gases whose partial pressures are 0.80 atm and 0.20 atm, respectively. Calculate the total pressure and the mole fractions of the gases.

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