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A 2.10-L vessel contains \(4.65 \mathrm{~g}\) of a gas at \(1.00 \mathrm{~atm}\) and \(27.0^{\circ} \mathrm{C}\). (a) Calculate the density of the gas in grams per liter. (b) What is the molar mass of the gas?

Short Answer

Expert verified
The gas density is 2.214 g/L and its molar mass is 54.57 g/mol.

Step by step solution

01

Convert Temperature to Kelvin

First, convert the temperature from degrees Celsius to Kelvin using the formula: \[ K = ^\circ C + 273.15 \]. Substituting the given value, we have \[ 27.0 + 273.15 = 300.15 \text{ K} \].
02

Calculate Density

The density of the gas is calculated using the formula: \[ \text{Density} = \frac{\text{mass}}{\text{volume}} \].The mass of the gas is given as 4.65 g and the volume as 2.10 L, so: \[ \text{Density} = \frac{4.65}{2.10} = 2.214 \text{ g/L} \].
03

Use Ideal Gas Law to Find Molar Mass

Use the ideal gas law: \[ PV = nRT \]. First, solve for the number of moles \( n \) using \[ n = \frac{PV}{RT} \], where:- \( P = 1.00 \text{ atm} \)- \( V = 2.10 \text{ L} \)- \( R = 0.0821 \text{ L atm} / \text{mol K} \)- \( T = 300.15 \text{ K} \)Substitute these values:\[ n = \frac{1.00 \times 2.10}{0.0821 \times 300.15} = 0.0852 \text{ mol} \].
04

Calculate Molar Mass

The molar mass \( M \) is calculated using: \[ M = \frac{\text{mass}}{n} \]. Substitute the known values:\[ M = \frac{4.65}{0.0852} = 54.57 \text{ g/mol} \].

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Gas Density Calculation
Gas density tells us how much mass is contained in a certain volume of a gas, usually measured in grams per liter (g/L). Knowing the density of a gas is crucial, especially in applications involving gases under different conditions of temperature and pressure. To find the density, you can use the formula:
  • Density = \( \frac{\text{mass}}{\text{volume}} \)

In our problem, the gas weighs 4.65 grams, and it occupies a volume of 2.10 liters. Plugging these values into the formula gives:
  • Density = \( \frac{4.65}{2.10} = 2.214 \text{ g/L} \)

A higher density means more mass in a smaller volume, while a lower density indicates less mass in a larger volume. Understanding gas density helps in various fields like engineering and environmental science.
Temperature Conversion to Kelvin
When dealing with gases, particularly in equations like the ideal gas law, it's important to use Kelvin for temperature. Kelvin is an absolute temperature scale and ensures that the mathematical relationships work correctly.

To convert from Celsius to Kelvin, use the simple formula:
  • Kelvin (K) = Celsius (°C) + 273.15

In the exercise example, the temperature given is 27°C. Therefore, the conversion process is straightforward:
  • K = 27 + 273.15 = 300.15 K

This conversion ensures that we are using the right units for solving gas problems. Kelvin eliminates the possibility of negative temperatures, which can cause errors in calculations involving gases.
Molar Mass Determination
Molar mass is the mass of one mole of a substance, usually expressed in grams per mole (g/mol). It's a key property in chemistry, serving as a bridge between the macroscopic and microscopic worlds.

To find the molar mass of a gas using the ideal gas law, follow these steps. Start by rearranging the ideal gas law \( PV = nRT \) to find the number of moles, \( n \):
  • \( n = \frac{PV}{RT} \)

Substitute the values of pressure \( P \), volume \( V \), the gas constant \( R \), and temperature \( T \) to calculate the moles of gas. For instance:
  • \( n = \frac{1.00 \times 2.10}{0.0821 \times 300.15} = 0.0852 \text{ mol} \)

Once you have the number of moles, the molar mass can be determined using:
  • \( M = \frac{\text{mass}}{n} \)

By substituting the mass of gas and moles:
  • \( M = \frac{4.65}{0.0852} = 54.57 \text{ g/mol} \)

Knowing the molar mass helps identify unknown gases and is vital in fields such as analytical chemistry and petrochemicals.

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Most popular questions from this chapter

Compare the root-mean-square speeds of \(\mathrm{O}_{2}\) and \(\mathrm{UF}_{6}\) at \(65^{\circ} \mathrm{C}\).

A quantity of gas weighing \(7.10 \mathrm{~g}\) at 741 torr and \(44^{\circ} \mathrm{C}\) occupies a volume of \(5.40 \mathrm{~L}\). What is its molar mass?

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An ideal gas originally at \(0.85 \mathrm{~atm}\) and \(66^{\circ} \mathrm{C}\) was allowed to expand until its final volume, pressure, and temperature were \(94 \mathrm{~mL}, 0.60 \mathrm{~atm},\) and \(45^{\circ} \mathrm{C}\), respectively. What was its initial volume?

The volume of a gas is \(5.80 \mathrm{~L},\) measured at \(1.00 \mathrm{~atm} .\) What is the pressure of the gas in \(\mathrm{mmHg}\) if the volume is changed to \(9.65 \mathrm{~L} ?\) (The temperature remains constant.)

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