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Pheromones are a special type of compound secreted by the females of many insect species to attract the males for mating. One pheromone has the molecular formula \(\mathrm{C}_{19} \mathrm{H}_{38} \mathrm{O}\). Normally, the amount of this pheromone secreted by a female insect is about \(1.0 \times 10^{-12} \mathrm{~g}\). How many molecules are there in this quantity?

Short Answer

Expert verified
There are approximately \(2.13 \times 10^{9}\) molecules in the pheromone sample.

Step by step solution

01

Determine Molar Mass

First, calculate the molar mass of the pheromone. Using the atomic masses: Carbon (C) = 12 g/mol, Hydrogen (H) = 1 g/mol, and Oxygen (O) = 16 g/mol. The molecular formula is: \(\mathrm{C}_{19} \mathrm{H}_{38} \mathrm{O}\).Calculate it as follows: \[ (19 \times 12) + (38 \times 1) + (1 \times 16) = 228 + 38 + 16 = 282 \text{ g/mol} \]
02

Convert Grams to Moles

Next, convert the mass of the pheromone from grams to moles using its molar mass. The formula for this is: \[ \text{moles} = \frac{\text{mass}}{\text{molar mass}} \]Substitute the numbers: \[ \text{moles} = \frac{1.0 \times 10^{-12} \, \text{g}}{282 \, \text{g/mol}} \approx 3.54 \times 10^{-15} \, \text{mol} \]
03

Calculate Number of Molecules

To find the number of molecules, use Avogadro's number, which is approximately \(6.022 \times 10^{23}\) molecules/mol. Multiply the number of moles by Avogadro's number: \[ \text{Number of molecules} = 3.54 \times 10^{-15} \, \text{mol} \times 6.022 \times 10^{23} \, \text{molecules/mol} \]Calculate to find: \[ \text{Number of molecules} \approx 2.13 \times 10^{9} \, \text{molecules} \]

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Molar Mass Calculation
When we talk about molar mass, we are referring to the mass of one mole of a substance, which is fundamental in chemistry. It is expressed in grams per mole (g/mol). To calculate the molar mass of any compound, you need to know its molecular formula and the atomic mass of each element involved.
The molecular formula gives you the number of each type of atom in the compound. In the case of the pheromone with the formula \( \mathrm{C}_{19} \mathrm{H}_{38} \mathrm{O} \), we need the atomic masses of carbon, hydrogen, and oxygen.
  • Carbon (C) has an atomic mass of 12 g/mol.
  • Hydrogen (H) has an atomic mass of 1 g/mol.
  • Oxygen (O) has an atomic mass of 16 g/mol.

The molar mass calculation itself is straightforward. Multiply the atomic mass of each element by the number of times it appears in the molecule and then sum up all these values:
\[ (19 \times 12) + (38 \times 1) + (1 \times 16) = 282 \, \text{g/mol} \]
This means the molar mass of the pheromone is 282 g/mol.
Avogadro's Number
Avogadro's number is a cornerstone concept in chemistry that is crucial for understanding the relationship between atoms and moles. It represents the number of atoms, ions, or molecules present in one mole of any substance. This number is a fixed value: \(6.022 \times 10^{23}\).
This large number helps chemists convert between microscopic scales of atoms and macroscopic amounts that can be measured. For example, if you have one mole of a substance, you won't have just a small handful of molecules—you have an extensive, large set of \(6.022 \times 10^{23}\) individual molecules.
In our pheromone example, once you have converted grams to moles, Avogadro's number is used in order to determine how many individual pheromone molecules are present in a given amount of substance.
It serves as a bridge between atomic and macroscopic chemistry and is essential for mole conversion calculations.
Mole Conversion
Mole conversion is a practical technique that lets us transition between the mass of a chemical substance and the amount of substance in moles, making use of the molar mass and Avogadro's number.
To perform a mole conversion: follow these steps:
  • Convert the mass of the substance to moles using the molar mass using the formula: \( \text{moles} = \frac{\text{mass}}{\text{molar mass}} \).
  • In the example of our pheromone: \( \text{moles} = \frac{1.0 \times 10^{-12} \, \text{g}}{282 \, \text{g/mol}} \approx 3.54 \times 10^{-15} \, \text{mol} \).

After finding the moles of your substance, you can then use Avogadro's number to calculate the number of molecules:
  • Multiply moles by Avogadro's number: \( \text{Number of molecules} = 3.54 \times 10^{-15} \, \text{mol} \times 6.022 \times 10^{23} \, \text{molecules/mol} \).
  • This calculation gives \( \text{Number of molecules} \approx 2.13 \times 10^{9} \, \text{molecules} \).

This technique lets you work with real-life quantities of substances by linking mass, moles, and molecular count in a comprehensible way.

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Most popular questions from this chapter

Hydrogen has two stable isotopes, \({ }_{1}^{1} \mathrm{H}\) and \({ }_{1}^{2} \mathrm{H},\) and sulfur has four stable isotopes, \({ }_{16}^{32} \mathrm{~S},{ }_{16}^{33} \mathrm{~S},{ }_{16}^{34} \mathrm{~S},\) and \({ }_{16}^{36} \mathrm{~S} .\) How many peaks would you observe in the mass spectrum of the positive ion of hydrogen sulfide, \(\mathrm{H}_{2} \mathrm{~S}^{+}\) ? Assume no decomposition of the ion into smaller fragments.

(a) A research chemist used a mass spectrometer to study the two isotopes of an element. Over time, she recorded a number of mass spectra of these isotopes. On analysis, she noticed that the ratio of the taller peak (the more abundant isotope) to the shorter peak (the less abundant isotope) gradually increased with time. Assuming that the mass spectrometer was functioning normally, what do you think was causing this change? (b) Mass spectrometry can be used to identify the formulas of molecules having small molecular masses. To illustrate this point, identify the molecule which most likely accounts for the observation of a peak in a mass spectrum at: 16 amu, \(17 \mathrm{amu}, 18 \mathrm{amu},\) and 64 amu. (c) Note that there are (among others) two likely molecules that would give rise to a peak at 44 amu, namely, \(\mathrm{C}_{3} \mathrm{H}_{8}\) and \(\mathrm{CO}_{2} .\) In such cases, a chemist might try to look for other pea generated when some of the molecules break apart in the spectrometer. For example, if a chemist sees a peak at 44 amu and also one at 15 amu, which molecule is producing the 44 amu peak? Why? (d) Using the following precise atomic masses: \({ }^{1} \mathrm{H}(1.00797 \mathrm{amu}),{ }^{12} \mathrm{C}(12.00000 \mathrm{amu}),\) and \({ }^{16} \mathrm{O}(15.99491 \mathrm{amu}),\) how precisely must the masses of \(\mathrm{C}_{3} \mathrm{H}_{8}\) and \(\mathrm{CO}_{2}\) be measured to distinguish between them? (e) Every year millions of dollars' worth of gold is stolen. In most cases the gold is melted down and shipped abroad. This way the gold retains its value while losing all means of identification. Gold is a highly unreactive metal that exists in nature in the uncombined form. During the mineralization of gold, that is, the formation of gold nuggets from microscopic gold particles, various elements such as cadmium (Cd), lead (Pb), and zinc (Zn) are incorporated into the nuggets. The amounts and types of the impurities or trace elements in gold vary according to the location where it was mined. Based on this knowledge, describe how you would identify the source of a piece of gold suspected of being stolen from Fort Knox, the federal gold depository.

Carbon dioxide \(\left(\mathrm{CO}_{2}\right)\) is the gas that is mainly responsible for global warming (the greenhouse effect). The burning of fossil fuels is a major cause of the increased concentration of \(\mathrm{CO}_{2}\) in the atmosphere. Carbon dioxide is also the end product of metabolism (see Example 3.13). Using glucose as an example of food, calculate the annual human production of \(\mathrm{CO}_{2}\) in grams, assuming that each person consumes \(5.0 \times 10^{2} \mathrm{~g}\) of glucose per day. The world's population is 6.5 billion, and there are 365 days in a year.

Propane \(\left(\mathrm{C}_{3} \mathrm{H}_{8}\right)\) is a component of natural gas and is used in domestic cooking and heating. (a) Balance the following equation representing the combustion of propane in air: $$ \mathrm{C}_{3} \mathrm{H}_{8}+\mathrm{O}_{2} \longrightarrow \mathrm{CO}_{2}+\mathrm{H}_{2} \mathrm{O} $$ (b) How many grams of carbon dioxide can be produced by burning 3.65 moles of propane? Assume that oxygen is the excess reagent in this reaction.

Peroxyacylnitrate (PAN) is one of the components of smog. It is a compound of \(\mathrm{C}, \mathrm{H}, \mathrm{N},\) and \(\mathrm{O}\). Determine the percent composition of oxygen and the empirical formula from the following percent composition by mass: 19.8 percent \(\mathrm{C}, 2.50\) percent \(\mathrm{H}, 11.6\) percent \(\mathrm{N}\). What is its molecular formula given that its molar mass is about \(120 \mathrm{~g}\) ?

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