Chapter 21: Problem 58
The nucleus of nitrogen- 18 lies above the stability belt. Write an equation for a nuclear reaction by which nitrogen- 18 can achieve stability.
Short Answer
Expert verified
Nitrogen-18 undergoes beta decay to form Oxygen-18.
Step by step solution
01
Identify the Characteristics of Nitrogen-18
Nitrogen-18 (
^{18}_{7}N) is an isotope with 7 protons (atomic number) and 18 nucleons (mass number). It lies above the stability belt, meaning it has a higher neutron-to-proton ratio than stable isotopes.
02
Determine the Likely Decay Mode
Since Nitrogen-18 has an excess of neutrons, the likely mode of decay to achieve stability is beta decay (β− decay), where a neutron is converted into a proton, emitting an electron (beta particle) and an antineutrino. This process decreases the neutron-proton ratio.
03
Write the Nuclear Reaction Equation
In beta decay, a neutron in the nucleus of nitrogen-18 is converted into a proton, resulting in the formation of a new element with one more proton than nitrogen, which is oxygen. The nuclear reaction can be written as:\[ ^{18}_{7}N \rightarrow \, ^{18}_{8}O \, + \, e^- \, + \, \bar{u}_e \]Here, e^- represents the emitted beta particle, and \(\bar{u}_e\) represents the antineutrino.
04
Verify the Stability of the Product
The product of the decay reaction is Oxygen-18 (
^{18}_{8}O), which is a stable isotope. This confirms that the beta decay process has successfully brought nitrogen-18 to a stable state.
Unlock Step-by-Step Solutions & Ace Your Exams!
-
Full Textbook Solutions
Get detailed explanations and key concepts
-
Unlimited Al creation
Al flashcards, explanations, exams and more...
-
Ads-free access
To over 500 millions flashcards
-
Money-back guarantee
We refund you if you fail your exam.
Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!
Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Nitrogen-18 Decay
Nitrogen-18 (
^{18}_{7}N) is a radioactive isotope with an unstable nucleus. It has 7 protons and 18 nucleons (sum of protons and neutrons). This isotope lies above the stability belt—a graphical representation of stable isotopes based on their neutron-to-proton (n/p) ratio. A position above this belt indicates
^{18}_{7}N has too many neutrons compared to protons.
To achieve stability, nitrogen-18 undergoes a decay process. In its case, beta decay (β− decay) is most likely because it involves a transformation that addresses its imbalance. Through this decay, nitrogen-18 can change into a more stable form, which is oxygen-18. Understanding its decay path explains how unstable isotopes seek stability.
To achieve stability, nitrogen-18 undergoes a decay process. In its case, beta decay (β− decay) is most likely because it involves a transformation that addresses its imbalance. Through this decay, nitrogen-18 can change into a more stable form, which is oxygen-18. Understanding its decay path explains how unstable isotopes seek stability.
Beta Decay Process
Beta decay is a fundamental nuclear reaction, where a neutron in the atomic nucleus is transformed into a proton. This transformation results in the emission of a beta particle (electron, e−) and an antineutrino (\bar{u}_e).
This process can be expressed in a nuclear equation: \[ ^{18}_{7}N \rightarrow \, ^{18}_{8}O \, + \, e^- \, + \, \bar{u}_e \]
This process can be expressed in a nuclear equation: \[ ^{18}_{7}N \rightarrow \, ^{18}_{8}O \, + \, e^- \, + \, \bar{u}_e \]
- Neutron (n) changes to Proton (p)
- Release of a beta particle (\(e^-\))
- Emission of an antineutrino (\(\bar{u}_e\))
Neutron-to-Proton Ratio
The neutron-to-proton (n/p) ratio is crucial in determining atomic stability. An ideal balance between neutrons and protons keeps the nucleus stable.
In nitrogen-18, the n/p ratio is higher than in stable isotopes. This higher ratio indicates excess neutrons, prompting the atom towards beta decay to adjust and enhance stability. The beta decay process decreases the n/p ratio by converting a neutron to a proton, which is essential for achieving equilibrium.
In nitrogen-18, the n/p ratio is higher than in stable isotopes. This higher ratio indicates excess neutrons, prompting the atom towards beta decay to adjust and enhance stability. The beta decay process decreases the n/p ratio by converting a neutron to a proton, which is essential for achieving equilibrium.
- More neutrons than protons indicate instability.
- Adjusting n/p ratio is crucial for nuclear stability.
- In ^{18}_{7}N, beta decay reduces n/p ratio, aiding stability.
Oxygen-18 Stability
Oxygen-18 (
^{18}_{8}O) is the stable product of nitrogen-18's beta decay. This isotope has an equal number of neutrons and protons (10 each), which aligns well with the ideal n/p ratio for stability.
Once nitrogen-18 decays through beta decay, it achieves a stable configuration as oxygen-18. This new isotope no longer undergoes radioactive decay under normal conditions, reflecting the end goal of attaining a stable nuclear form. Oxygen-18’s stability is characterized by:
Once nitrogen-18 decays through beta decay, it achieves a stable configuration as oxygen-18. This new isotope no longer undergoes radioactive decay under normal conditions, reflecting the end goal of attaining a stable nuclear form. Oxygen-18’s stability is characterized by:
- Nuclear balance: Equal protons and neutrons.
- Lying on the stability belt, indicative of stable isotopes.
- No further decay means reduced radioactivity.