Chapter 14: Problem 43
Explain why termolecular reactions are rare.
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Chapter 14: Problem 43
Explain why termolecular reactions are rare.
These are the key concepts you need to understand to accurately answer the question.
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Reactions can be classified as unimolecular, bimolecular, and so on. Why are there no zero-molecular reactions?
As we know, methane burns readily in oxygen in a highly exothermic reaction. Yet a mixture of methane and oxygen gas can be kept indefinitely without any apparent change. Explain.
Define activation energy. What role does activation energy play in chemical kinetics?
For gas-phase reactions, we can replace the concentration terms in Equation (14.3) with the pressures of the gaseous reactant. (a) Derive the equation $$ \ln \frac{P_{t}}{P_{0}}=-k t $$ where \(P_{t}\) and \(P_{0}\) are the pressures at \(t=t\) and \(t=0\) respectively. (b) Consider the decomposition of azomethane $$ \mathrm{CH}_{3}-\mathrm{N}=\mathrm{N}-\mathrm{CH}_{3}(g) \longrightarrow \mathrm{N}_{2}(g)+\mathrm{C}_{2} \mathrm{H}_{6}(g) $$ The data obtained at \(300^{\circ} \mathrm{C}\) are shown in the following table: $$ \begin{array}{cc} \text { Time (s) } & \begin{array}{c} \text { Partial Pressure of } \\ \text { Azomethane (mmHg) } \end{array} \\ \hline 0 & 284 \\ 100 & 220 \\ 150 & 193 \\ 200 & 170 \\ 250 & 150 \\ 300 & 132 \end{array} $$ Are these values consistent with first-order kinetics? If so, determine the rate constant by plotting the data as shown in Figure \(14.7(\mathrm{~b})\). (c) Determine the rate constant by the half-life method.
How does a catalyst increase the rate of a reaction?
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