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Use valence bond theory to explain the bonding in \(\mathrm{Cl}_{2}\) and \(\mathrm{HCl}\). Show how the atomic orbitals overlap when a bond is formed.

Short Answer

Expert verified
Both \( \mathrm{Cl}_{2} \) and \( \mathrm{HCl} \) form sigma bonds via direct orbital overlap: \(3p-3p\) for \( \mathrm{Cl}_{2} \) and \(1s-3p\) for \( \mathrm{HCl} \).

Step by step solution

01

Understanding Valence Bond Theory

Valence Bond Theory (VBT) explains the formation of chemical bonds through the overlap of atomic orbitals. This theory is particularly useful for understanding covalent bonds between atoms. In this exercise, we'll apply VBT to explain the bonding in \( \mathrm{Cl}_{2} \) and \( \mathrm{HCl} \).
02

Chlorine Molecule (\( \mathrm{Cl}_{2} \)) Bonding Analysis

Each chlorine atom in \( \mathrm{Cl}_{2} \) has the electron configuration \([Ne] 3s^2 3p^5\), with one unpaired electron in the \(3p\) orbital. According to VBT, the \(3p\) orbital of one chlorine overlaps with the \(3p\) orbital of another chlorine. This head-on overlap forms a sigma \(\sigma\) bond, resulting in a \( \mathrm{Cl}_{2} \) molecule.
03

Hydrogen Chloride (\( \mathrm{HCl} \)) Bonding Analysis

Hydrogen has an atomic configuration of \(1s^1\), and chlorine has \([Ne] 3s^2 3p^5\). In \( \mathrm{HCl} \), the \(1s\) orbital of hydrogen overlaps with the \(3p\) orbital of chlorine. This orbital overlap leads to a sigma \(\sigma\) bond formation between hydrogen and chlorine atoms.
04

Visualizing the Orbital Overlap

In both molecules, the bonds are formed by the linear overlap of orbitals resulting in sigma \(\sigma\) bonds. Chlorine atoms in \( \mathrm{Cl}_{2} \) form bonds by \(3p-3p\) overlap, while in \( \mathrm{HCl} \), the bond results from \(1s-3p\) overlap. These overlaps are direct and end-to-end, characteristic of sigma bonds.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Orbital Overlap
When atoms come together to form a molecule, their atomic orbitals need to overlap. This is a fundamental aspect of how chemical bonds are created according to Valence Bond Theory. The concept of orbital overlap is all about how the electron clouds from two different atoms can merge to form a shared region where electrons can exist around both atoms. This shared region often results in a covalent bond.

In the case of a chlorine molecule, \(\mathrm{Cl}_{2}\), each chlorine atom has an unpaired electron in the \(3p\) orbital. These \(3p\) orbitals overlap directly with each other. This direct overlap is what allows the two chlorine atoms to share a pair of electrons, forming a bond. Similarly, in the hydrogen chloride molecule, \(\mathrm{HCl}\), the \(1s\) electron cloud of hydrogen atom overlaps with the \(3p\) orbital of the chlorine atom. This creates a similar overlap region where the bond is formed.

  • Orbital overlap refers to the merging of two atomic orbitals.
  • This overlap forms a region where electrons can be shared between two atoms.
  • In \(\mathrm{Cl}_{2}\), there is a \(3p-3p\) overlap, while in \(\mathrm{HCl}\), we see a \(1s-3p\) overlap.
Sigma Bonds
Sigma \(\sigma\) bonds are one of the strongest types of covalent bonds that can form. They occur due to the head-on overlap of atomic orbitals, creating a shared electron cloud that lies along the axis connecting two atomic nuclei. This is in contrast to other types of bonds, like pi \(\pi\) bonds, which occur from the side-to-side overlap of orbitals.

In the chlorine molecule \(\mathrm{Cl}_{2}\), the \(3p\) orbitals on each chlorine atom orient directly towards each other to overlap. This results in the formation of a sigma bond. It is this head-on orientation that distinguishes sigma bonds from other bond types. Just like \(\mathrm{Cl}_{2}\), the molecule of hydrogen chloride \(\mathrm{HCl}\) features a sigma bond, but here it results from the overlap of hydrogen's \(1s\) orbital with chlorine's \(3p\) orbital.

  • Sigma bonds are characterized by head-on orbital overlap.
  • They provide strong bonds due to their symmetrical electron density.
  • Both \(\mathrm{Cl}_{2}\) and \(\mathrm{HCl}\) have sigma bonds as a result of their orbital overlaps.
Chemical Bonding
Chemical bonding is the process by which atoms come together to create stable structures known as molecules. Valence Bond Theory is one of the main theories explaining how these bonds form. It shows us that when atomic orbitals overlap, a bond is created. This overlap allows sharing of electrons, which is the essence of covalent bonding.

In \(\mathrm{Cl}_{2}\), each chlorine atom brings one unpaired electron in its \(3p\) orbital to bond. In \(\mathrm{HCl}\), however, the situation is a bit different because we have a hydrogen atom joining with chlorine. The hydrogen provides its \(1s\) orbital, which overlaps with the \(3p\) orbital of chlorine, resulting in a successful bond formation. Every time such an overlap happens, a molecule is given all the properties we associate with a stable chemical entity.

  • Chemical bonding results in molecules consisting of multiple atoms.
  • These bonds form due to the sharing of electrons via orbital overlap.
  • Understanding how orbitals behave helps in explaining the nature of chemical bonds.

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Most popular questions from this chapter

Aluminum trichloride \(\left(\mathrm{AlCl}_{3}\right)\) is an electron-deficient molecule. It has a tendency to form a dimer (a molecule made of two \(\mathrm{AlCl}_{3}\) units): $$\mathrm{AlCl}_{3}+\mathrm{AlCl}_{3} \longrightarrow \mathrm{Al}_{2} \mathrm{Cl}_{6}$$ (a) Draw a Lewis structure for the dimer. (b) Describe the hybridization state of \(\mathrm{Al}\) in \(\mathrm{AlCl}_{3}\) and \(\mathrm{Al}_{2} \mathrm{Cl}_{6}\). (c) Sketch the geometry of the dimer. (d) Do these molecules possess a dipole moment?

Which of these pairs of atomic orbitals of adjacent nuclei can overlap to form a sigma bond? Which overlap to form a pi bond? Which cannot overlap (no bond)? Consider the \(x\) -axis to be the internuclear axis, that is, the line joining the nuclei of the two atoms. (a) \(1 s\) and \(1 s,\) (b) \(1 s\) and \(2 p_{x},\) (c) \(2 p_{x}\) and \(2 p_{y},\) (d) \(3 p_{y}\) and \(3 p_{y},\) (e) \(2 p_{x}\) and \(2 p_{x}\), (f) \(1 s\) and \(2 s\).

What is the hybridization state of the central \(\mathrm{N}\) atom in the azide ion, \(\mathrm{N}_{3}^{-}\) ? (Arrangement of atoms: NNN.)

The compounds carbon tetrachloride \(\left(\mathrm{CCl}_{4}\right)\) and silicon tetrachloride \(\left(\mathrm{SiCl}_{4}\right)\) are similar both in geometry and hybridization. However, \(\mathrm{CCl}_{4}\) does not react with water but \(\mathrm{SiCl}_{4}\) does. Explain the difference in their chemical reactivities. (Hint: The first step of the reaction is believed to be the addition of a water molecule to the Si atom in \(\mathrm{SiCl}_{4} .\) )

Define these terms: bonding molecular orbital, antibonding molecular orbital, pi molecular orbital, sigma molecular orbital.

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