/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 35 Three students (X, Y, and Z) are... [FREE SOLUTION] | 91Ó°ÊÓ

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Three students (X, Y, and Z) are assigned the task of determining the mass of a sample of iron. Each student makes three determinations with a balance. The results in grams are \(X(61.5,61.6,61.4) ; Y(62.8,\) 62.2,62.7)\(; \mathrm{Z}(61.9,62.2,62.1) .\) The actual mass of the iron is \(62.0 \mathrm{~g}\). Which student is the least precise? Which student is the most accurate?

Short Answer

Expert verified
Student Y is the least precise. Student Z is the most accurate.

Step by step solution

01

Understanding Precision

Precision refers to the consistency of repeated measurements. To find it, we check how close each student's measurements are to each other. We calculate the range or standard deviation of each student's measurements.
02

Calculation of Precision

For each student, calculate the range: - Student X: Range = 61.6 - 61.4 = 0.2 g - Student Y: Range = 62.8 - 62.2 = 0.6 g - Student Z: Range = 62.2 - 61.9 = 0.3 g Student Y has the largest range, indicating the least precision.
03

Understanding Accuracy

Accuracy refers to how close a measurement is to the true value. We will compare the average of each student's measurements to the actual mass of 62.0 g. The closer the average is to 62.0 g, the more accurate the student is.
04

Calculation of Accuracy

Calculate the average for each student and compare it to the actual mass: - Student X: Average = (61.5 + 61.6 + 61.4) / 3 = 61.5 g - Student Y: Average = (62.8 + 62.2 + 62.7) / 3 = 62.57 g - Student Z: Average = (61.9 + 62.2 + 62.1) / 3 = 62.07 g Student Z's average (62.07 g) is closest to 62.0 g, indicating the most accuracy.
05

Conclusion

Based on the calculated precision and accuracy, Student Y is the least precise due to the largest range in measurements, and Student Z is the most accurate due to the average closest to the actual mass.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Precision vs Accuracy
When we talk about measurements, two important terms come into play: precision and accuracy. While they are often used interchangeably in everyday conversation, they have distinct meanings in the world of science and mathematics.
  • **Precision** refers to the consistency of repeated measurements. If you measure something several times and get results that are close to each other, your measurements are said to be precise. However, precision doesn't necessarily mean you are close to the actual value.
  • **Accuracy** refers to how close your measurement is to the true or accepted value. An accurate measurement hits close to the target, even if repeated measures aren't closely grouped.
Think of precision and accuracy like archery: hitting the bullseye consistently means both high precision and high accuracy. Hitting the target consistently but in a group that's near the edge indicates high precision but low accuracy. Conversely, hitting near the bullseye only once out of the group means low precision, but one measurement can be very accurate.
In our exercise, Student Z demonstrated the most accuracy with their average measurement closest to the actual mass, while students X and Y showed varying levels of precision due to the ranges in their measurements.
Standard Deviation in Measurements
Standard deviation is a key concept when talking about precision. It helps quantify the amount of variation or dispersion in a set of measurements. A low standard deviation means measurements are close to the mean (or average), indicating precision. In contrast, a high standard deviation indicates measurements are spread out over a wider range, showing less precision.

In the exercise, we used range rather than standard deviation to determine precision. Range is simply the difference between the highest and lowest values. That works well for small sets of data like the three measurements each student made.
Imagine if the measurements were more variable; calculating the standard deviation would give us a clear picture of that variability. For Student Y, with a range of 0.6g, this suggests a larger spread, meaning their measurements are less precise.
If we calculated the standard deviation for the students, we'd likely find a pattern similar to the range calculations. But for short datasets, either method suffices to determine precision.
Calculating Measurement Range
Calculating the range of measurements is a straightforward method to understand precision quickly, particularly in smaller data sets. To find the range, simply subtract the smallest measurement from the largest one.

Let's look at our students as examples:
  • **Student X:** The range is calculated from 61.6 (the largest value) minus 61.4 (the smallest value), resulting in a range of 0.2g.
  • **Student Y:** The range is 62.8 - 62.2, giving us 0.6g.
  • **Student Z:** The range here is 62.2 - 61.9, resulting in 0.3g.
You'll notice Student Y has the largest range, indicating the least precision. This simple calculation helps quickly assess variability among results. The smaller the range, the higher the precision; while a larger range suggests measurements are not as closely grouped.
Using range is especially useful when measurements are few and you wish to make a rapid assessment, but it can be complemented by standard deviation in larger and more complex data sets to better understand measurement precision.

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