Chapter 6: Problem 16
Write the chemical formula for (a) ruthenium(III) sulfide (b) scandium fluoride (c) osmium(VIII) oxide (d) manganese(II) sulfide (e) platinum(IV) chloride
Short Answer
Expert verified
(a) Ru鈧係鈧, (b) ScF鈧, (c) OsO鈧, (d) MnS, (e) PtCl鈧.
Step by step solution
01
Understanding the Metal Ion and Oxidation State
In a chemical formula, the metal cation's oxidation state is given in Roman numerals. For example, in ruthenium(III) sulfide, 'III' is the oxidation state of ruthenium, meaning it forms a 3+ ion (Ru鲁鈦).
02
Identifying the Non-metal and Its Charge
The non-metal ions can often be identified by their typical ionic charge. Sulfide ions (S虏鈦) form from sulfur atoms gaining two electrons.
03
Balancing Charges to Form the Compound
To form a neutral compound, the total positive charge must equal the total negative charge. For ruthenium(III) sulfide, we balance Ru鲁鈦 with S虏鈦 by forming Ru鈧係鈧, as two Ru鲁鈦 (total 6+) balances with three S虏鈦 (total 6鈭).
04
Repeating the Process for Each Compound
Repeat the above steps for each compound: (b) Scandium forms a 3+ ion (Sc鲁鈦), while fluoride forms a 1鈭 ion (F鈦), leading to the formula ScF鈧. (c) Osmium(VIII) oxide involves an Os鈦糕伜 ion and an oxide ion (O虏鈦), leading to the formula OsO鈧. (d) For manganese(II) sulfide, Mn虏鈦 and S虏鈦 combine in a 1:1 ratio to form MnS. (e) Platinum(IV) chloride involves a Pt鈦粹伜 ion with Cl鈦 ions, leading to the compound PtCl鈧 after balancing charges.
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Oxidation States
Oxidation states are a fundamental concept in writing chemical formulas. They indicate the number of electrons an atom has either gained, lost, or shared when forming a compound. This is crucial for identifying the charge on ions, particularly metal cations. The oxidation state is often represented with Roman numerals in parentheses following the element's name. For example, in ruthenium(III) sulfide, the "III" indicates that ruthenium has an oxidation state of +3. Understanding oxidation states helps predict how elements combine and how compounds are formed.
Remember:
Remember:
- The oxidation state represents the charge of an atom or ion in a compound.
- Roman numerals denote the oxidation state in the name of the compound.
Balancing Charges
The principle of balancing charges is key in forming chemical formulas for ionic compounds. The compound must be electrically neutral, meaning the total positive charge from the cations must equal the total negative charge from the anions. For instance, in ruthenium(III) sulfide, the Ru鲁鈦 ion has a +3 charge, and sulfide, S虏鈦, carries a -2 charge.
To balance these charges, you need 2 Ru鲁鈦 ions to equal the total negative charge of 3 S虏鈦 ions, resulting in Ru鈧係鈧.
Here's what you need to remember:
To balance these charges, you need 2 Ru鲁鈦 ions to equal the total negative charge of 3 S虏鈦 ions, resulting in Ru鈧係鈧.
Here's what you need to remember:
- Identify the charge of each ion from its oxidation state.
- Adjust the numbers of cations and anions so that their total charges balance out.
Metal and Non-metal Ions
In chemistry, many compounds consist of metals and non-metals combining to form ionic compounds. Metals typically form positive ions (cations) and non-metals form negative ions (anions). These ions are crucial in determining the chemical formula of a compound. Metal ions are often identified by their oxidation state, while non-metal ions have predictable charges based on their group in the periodic table. For instance:
- Scandium (Sc) generally forms a Sc鲁鈦 ion.
- Non-metals like oxygen and sulfide commonly form O虏鈦 and S虏鈦 ions, respectively.
Ionic Compounds
Ionic compounds are formed when metal cations and non-metal anions come together and balance their respective charges. These compounds are characterized by their structure of repeating units in a lattice. To form ionic compounds:
- Determine the oxidation states of the involved elements.
- Calculate how many of each ion is needed to balance the overall charge to zero.