/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 32 A certain rifle bullet has a mas... [FREE SOLUTION] | 91Ó°ÊÓ

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A certain rifle bullet has a mass of \(5.00\) grams. Calculate the de Broglie wavelength of the bullet traveling at 1250 miles per hour.

Short Answer

Expert verified
The de Broglie wavelength of the bullet is approximately \(2.37 \times 10^{-34} \text{ meters}\).

Step by step solution

01

Convert Mass to Kilograms

The mass of the bullet is given in grams. To convert it to kilograms, divide by 1000.Mass in kilograms: \(5.00 \text{ g} = 5.00 \times 10^{-3} \text{ kg}\).
02

Convert Velocity to Meters per Second

Velocity is given in miles per hour. We need to convert this to meters per second.First, convert miles to kilometers: \(1250 \text{ mph} = 1250 \times 1.60934 = 2011.68 \text{ km/h}\).Then convert kilometers per hour to meters per second: \(2011.68 \text{ km/h} = \frac{2011.68 \times 1000}{3600} \text{ m/s} \approx 558.8 \text{ m/s}\).
03

Use the de Broglie Wavelength Formula

The de Broglie wavelength formula is:\[\lambda = \frac{h}{mv}\]where:- \(h = 6.626 \times 10^{-34} \text{ m}^2 \text{ kg/s}\) is the Planck's constant,- \(m\) is the mass in kilograms, - \(v\) is the velocity in meters per second.
04

Calculate the Wavelength

Substitute the mass and velocity into the de Broglie equation:\[\lambda = \frac{6.626 \times 10^{-34}}{5.00 \times 10^{-3} \times 558.8}\]Perform the calculation:\[\lambda \approx \frac{6.626 \times 10^{-34}}{2.794} \approx 2.37 \times 10^{-34} \text{ meters}\]

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Planck's constant
The concept of Planck's constant is pivotal when dealing with quantum mechanics. It is a fundamental constant denoted by the symbol \( h \) and has a value of \( 6.626 \times 10^{-34} \, \text{m}^2 \, \text{kg/s} \). Max Planck introduced it to explain the black-body radiation problem, and it has since become a cornerstone of quantum theory.
  • Planck's constant is essential in the calculation of the energy of photons: \( E = hu \), where \( u \) is the frequency.
  • In de Broglie relations, it's used to relate a particle’s momentum to its wave-like characteristics.
Without Planck’s constant, we wouldn’t be able to understand the dual nature of particles behaving as both waves and particles.
This duality is described through the de Broglie wavelength formula \( \lambda = \frac{h}{mv} \), where \( \lambda \) is the wavelength of particle matter, \( m \) is mass and \( v \) is velocity.
Remembering the value and significance of Planck's constant helps in synthesizing the behavior of microscopic particles across various quantum physics problems.
Unit conversions
Unit conversions are crucial for solving problems accurately, especially when dealing with measurements in physics that require specific metric units for calculations.
To ensure correct results, one must convert all units to a standard form before applying formulas or equations.
In our example, two main conversions are performed:
  • Convert mass from grams to kilograms because the SI unit for mass in physics is kilogram. Use the conversion: \( 1 \text{ gram} = 1 \times 10^{-3} \text{ kilograms} \).
  • Convert velocity from miles per hour to meters per second, as the SI unit for speed is meters per second. This requires first converting miles to kilometers: \( 1 \text{ mile} = 1.60934 \text{ km} \), and then changing hours to seconds: \( 1 \text{ hour} = 3600 \text{ seconds} \).
Making these conversions ensures that all values in the equation for de Broglie wavelength are in compatible units, allowing for correct calculation of physical quantities.
Mass and velocity
Mass and velocity are two fundamental properties in physics that determine how objects move and interact.
In the context of the de Broglie wavelength, these properties help calculate the wave-like nature of particles.
  • Mass \( (m) \) measures the amount of matter in an object, usually in kilograms for scientific calculations.
  • Velocity \( (v) \) is the speed of the object in a specified direction, which must be in meters per second for calculations in the de Broglie formula.
For a bullet traveling at high speed, like in our problem,
the small mass in kilograms and high velocity ensure the de Broglie wavelength is exceedingly small, underlining why wave-like nature isn't noticeable in macroscopic objects. This highlights the quantum theory principle that particles have smaller wavelengths, unnoticed in everyday experiences but vital in atomic and subatomic scales.

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